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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#369824#6506. Chase Game 3401rk8#WA 16ms3784kbC++171.8kb2024-03-28 18:24:572024-03-28 18:24:58

Judging History

你现在查看的是最新测评结果

  • [2024-03-28 18:24:58]
  • 评测
  • 测评结果:WA
  • 用时:16ms
  • 内存:3784kb
  • [2024-03-28 18:24:57]
  • 提交

answer

#include <bits/stdc++.h>
#include <bits/extc++.h>
using namespace std; using namespace __gnu_pbds; using namespace __gnu_cxx;
#define For(i,x,y,...) for(int i=x,##__VA_ARGS__;i<=(y);++i)
#define rFor(i,x,y,...) for(int i=x,##__VA_ARGS__;i>=(y);--i)
#define Rep(i,x,y,...) for(int i=x,##__VA_ARGS__;i<(y);++i)
#define pb emplace_back
#define sz(a) int((a).size())
#define all(a) begin(a),end(a)
#define fi first
#define se second
typedef long long LL; typedef vector<int> Vi; typedef pair<int,int> Pii;
auto ckmax=[](auto &x,auto y) { return x<y ? x=y,true : false; };
auto ckmin=[](auto &x,auto y) { return y<x ? x=y,true : false; };
sfmt19937 mt(chrono::steady_clock::now().time_since_epoch().count());
int rnd(int l,int r) { return uniform_int_distribution<>(l,r)(mt); }
template<typename T=int>T read() { T x; cin>>x; return x; }

const int mod = 998244353;
struct mint {
	int x; mint(int x=0):x(x<0?x+mod:x<mod?x:x-mod){}
	mint(LL y) { y%=mod, x=y<0?y+mod:y; }
	mint& operator += (const mint &y) { x=x+y.x<mod?x+y.x:x+y.x-mod; return *this; }
	mint& operator -= (const mint &y) { x=x<y.x?x-y.x+mod:x-y.x; return *this; }
	mint& operator *= (const mint &y) { x=1ll*x*y.x%mod; return *this; }
	friend mint operator + (mint x,const mint &y) { return x+=y; }
	friend mint operator - (mint x,const mint &y) { return x-=y; }
	friend mint operator * (mint x,const mint &y) { return x*=y; }
};	mint Pow(mint x,LL y=mod-2) { mint z(1);for(;y;y>>=1,x*=x)if(y&1)z*=x;return z; }

const int N = 4e5+5;
int n,a[N];

void MAIN() {
	cin>>n; For(i,1,n) cin>>a[i];
	Rep(i,1,n) if( abs(a[i]-a[i+1]) > 2 ) { cout<<"No\n"; return; }
	cout<<"Yes\n";
} signed main() {
#ifdef FT
	freopen("in","r",stdin); freopen("out","w",stdout);
#endif
	ios::sync_with_stdio(0);cin.tie(0);
	int lft=read(); while( lft-- ) {
		MAIN();
	}
	return 0;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3612kb

input:

5
2
1 2
3
2 3 1
4
1 4 3 2
5
1 5 2 3 4
6
1 2 3 4 5 6

output:

Yes
Yes
No
No
Yes

result:

ok 5 token(s): yes count is 3, no count is 2

Test #2:

score: 0
Accepted
time: 1ms
memory: 3572kb

input:

8
2
1 2
2
2 1
3
1 2 3
3
3 1 2
3
2 1 3
3
2 3 1
3
3 2 1
3
1 3 2

output:

Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes

result:

ok 8 token(s): yes count is 8, no count is 0

Test #3:

score: -100
Wrong Answer
time: 16ms
memory: 3784kb

input:

100000
4
4 1 3 2
4
3 2 4 1
4
3 2 1 4
4
2 4 3 1
4
1 2 3 4
4
2 3 1 4
4
1 3 4 2
4
3 4 1 2
4
1 3 2 4
4
1 4 3 2
4
3 4 2 1
4
3 2 4 1
4
4 2 3 1
4
3 2 4 1
4
4 1 2 3
4
3 2 1 4
4
4 1 3 2
4
1 3 4 2
4
1 4 2 3
4
2 4 3 1
4
2 3 1 4
4
4 2 3 1
4
2 1 3 4
4
3 1 2 4
4
1 2 3 4
4
4 3 2 1
4
3 4 1 2
4
1 3 2 4
4
4 2 1 3
4
3...

output:

No
No
No
Yes
Yes
No
Yes
No
Yes
No
Yes
No
Yes
No
No
No
No
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
No
Yes
Yes
Yes
No
Yes
No
No
Yes
No
No
No
Yes
Yes
Yes
Yes
No
No
No
No
No
No
Yes
Yes
Yes
No
Yes
Yes
Yes
Yes
No
No
Yes
Yes
No
No
No
Yes
Yes
Yes
Yes
Yes
Yes
No
No
Yes
Yes
No
No
Yes
No
Yes
No
Yes
Yes
No
...

result:

wrong answer expected YES, found NO [1st token]