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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#368593 | #6424. Go | C1942huangjiaxu | WA | 3ms | 72184kb | C++14 | 2.2kb | 2024-03-27 13:42:06 | 2024-03-27 13:42:07 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
const int N=1005,M=1e6+5,B=1e6+7,P=1e9+7;
int dx[4]={0,1,0,-1},dy[4]={1,0,-1,0};
int T,n,id[N][N],cnt,px[M],py[M],ans,va[M],Ans;
int dfn[M],low[M],co[M],tot,cl[M],Cl[M],sz[M],Sz[M];
bool ch[M],cut[M];
vector<int>e[M],g[M];
char s[N][N];
bool onb(int x,int y){
return x>0&&x<=n&&y>0&&y<=n;
}
bool lf(int x,int y){
for(int k=0;k<4;++k){
int i=x+dx[k],j=y+dy[k];
if(onb(i,j)&&s[i][j]=='.')return true;
}
return false;
}
void tarjan(int x){
dfn[x]=low[x]=++dfn[0],co[x]=tot,cl[x]=ch[x],sz[x]=1;
for(auto v:e[x]){
if(!dfn[v]){
g[x].push_back(v);
tarjan(v);
low[x]=min(low[x],low[v]);
if(low[v]>=dfn[x])cut[x]=true;
cl[x]+=cl[v],sz[x]+=sz[v];
}else low[x]=min(low[x],dfn[x]);
}
}
void calc(int x){
if(!Cl[co[x]])va[x]-=Sz[co[x]];
if(cut[x]){
int Rs=Sz[co[x]]-1,Rc=Cl[co[x]]-ch[x];
for(auto v:g[x])if(low[v]>=dfn[x]){
if(!cl[v])va[x]+=sz[v];
Rs-=sz[v],Rc-=cl[v];
}
if(!Rc)va[x]+=Rs;
}else{
if(Cl[co[x]]-ch[x]==0)va[x]+=Sz[co[x]]-1;
}
for(auto v:g[x])calc(v);
}
int rev(int i,int j){
if(s[i][j]=='o')return va[id[i][j]];
int res=0,Rs=1,Rc=lf(i,j);
set<int>S;
for(int k=0;k<4;++k){
int x=i+dx[k],y=j+dy[k];
if(onb(x,y)&&s[x][y]=='o')S.insert(co[id[x][y]]);
}
for(auto v:S){
if(!Cl[v])res-=Sz[v];
Rs+=Sz[v],Rc+=Cl[v];
}
if(!Rc)res+=Rs;
return res;
}
void solve(){
scanf("%d",&n);
for(int i=1;i<=cnt;++i)e[i].clear(),g[i].clear(),co[i]=va[i]=0;
cnt=dfn[0]=tot=ans=Ans=0;
for(int i=1;i<=n;++i)scanf("%s",s[i]+1);
for(int i=1;i<=n;++i)
for(int j=1;j<=n;++j)if(s[i][j]=='o'){
id[i][j]=++cnt;
ch[cnt]=lf(i,j);
px[cnt]=i,py[cnt]=j;
}
for(int i=1;i<=cnt;++i)
for(int j=0;j<4;++j){
int x=px[i]+dx[j],y=py[i]+dy[j];
if(onb(x,y)&&s[x][y]=='o')e[i].push_back(id[x][y]);
}
for(int i=1;i<=cnt;++i)if(!co[i]){
++tot;
tarjan(i);
Cl[tot]=cl[i],Sz[tot]=sz[i];
if(g[i].size()>1)cut[i]=true;
else cut[i]=false;
if(!cl[i])ans+=Sz[tot];
calc(i);
}
for(int i=1;i<=n;++i)for(int j=1;j<=n;++j)if(s[i][j]!='.'){
int t=ans+rev(i,j);
Ans=(1ll*Ans*B+t)%P;
}
printf("%d\n",Ans);
}
int main(){
scanf("%d",&T);
while(T--)solve();
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 3ms
memory: 72184kb
input:
3 2 .o .. 3 .x. xoo ox. 2 oo oo
output:
0 870527216 485539347
result:
ok 3 number(s): "0 870527216 485539347"
Test #2:
score: -100
Wrong Answer
time: 3ms
memory: 71456kb
input:
2 4 xoxx oxo. oo.o oo.x 6 .o.xox oox..x o.xxxo o..xxo xxo.o. xo...o
output:
248401442 250916587
result:
wrong answer 1st numbers differ - expected: '409509910', found: '248401442'