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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#367073#6744. SquareprovenAC ✓16ms3668kbC++201.4kb2024-03-25 17:24:452024-03-25 17:24:45

Judging History

你现在查看的是最新测评结果

  • [2024-03-25 17:24:45]
  • 评测
  • 测评结果:AC
  • 用时:16ms
  • 内存:3668kb
  • [2024-03-25 17:24:45]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
#define fs first
#define endl '\n'
#define sc second
#define pb push_back
#define int long long
#define bit(x) (1ll << (x))
#define sz(x) (int)(x).size()
#define al(x) (x).begin(),(x).end()
#define all(x) (x).begin() + 1,(x).end()
using LL = long long;
using VI = vector <int>;
using VS = vector <string>;
using PII = pair <int, int>;
using I64 = unsigned long long;
using VVI = vector < vector<int> >;
template<LL N> using AL = array<LL, N>;
template<int N> using AI = array<int, N>;
const int inf = bit(60);

void solve() {
    int x, y;
    cin >> x >> y;
    if(x >= y) {
        cout << x - y << endl;
        return;
    }
    int idx = (int)(sqrt(2 * x) + 1.5) - 1;
    int idy = (int)(sqrt(2 * y) + 1.5) - 1;
    int posx = (idx * (idx + 1) / 2) - x + 1;
    int posy = (idy * (idy + 1) / 2) - y + 1;
    if(posx == posy) {
        cout << idy - idx << endl;
    }
    else if(posx < posy) {
        cout << posy - posx + idy - idx << endl;
    }
    else {
        int ans1 = inf;
        int d = idy + 1;
        ans1 = min(ans1, d - idx + d - posx + posy);
        ans1 = min(ans1, idy - posx + posy + idy - (idy - 1));
        cout << ans1 << endl;
    }
}

signed main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    cout.tie(nullptr);
    cout << fixed << setprecision(10);
    int T = 1;
    cin >> T;
    while(T--) solve();

    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3668kb

input:

2
5 1
1 5

output:

4
3

result:

ok 2 number(s): "4 3"

Test #2:

score: 0
Accepted
time: 16ms
memory: 3636kb

input:

100000
1 1
1 2
1 3
1 4
1 5
1 6
1 7
1 8
1 9
1 10
1 11
1 12
1 13
1 14
1 15
1 16
1 17
1 18
1 19
1 20
1 21
1 22
1 23
1 24
1 25
1 26
1 27
1 28
1 29
1 30
1 31
1 32
1 33
1 34
1 35
1 36
1 37
1 38
1 39
1 40
1 41
1 42
1 43
1 44
1 45
1 46
1 47
1 48
1 49
1 50
1 51
1 52
1 53
1 54
1 55
1 56
1 57
1 58
1 59
1 60
1 ...

output:

0
2
1
4
3
2
6
5
4
3
8
7
6
5
4
10
9
8
7
6
5
12
11
10
9
8
7
6
14
13
12
11
10
9
8
7
16
15
14
13
12
11
10
9
8
18
17
16
15
14
13
12
11
10
9
20
19
18
17
16
15
14
13
12
11
10
22
21
20
19
18
17
16
15
14
13
12
11
24
23
22
21
20
19
18
17
16
15
14
13
12
26
25
24
23
22
21
20
19
18
1
0
2
2
1
3
4
3
2
4
6
5
4
3
5
...

result:

ok 100000 numbers