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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#360106#5160. Kebab Pizzakevinyang#RE 11ms48356kbC++173.1kb2024-03-21 12:05:222024-03-21 12:05:22

Judging History

你现在查看的是最新测评结果

  • [2024-03-21 12:05:22]
  • 评测
  • 测评结果:RE
  • 用时:11ms
  • 内存:48356kb
  • [2024-03-21 12:05:22]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
#define int long long
struct DisjointSet{
	vector<int>parent,sz,mn,mx;
	int size;
	void init(int n){
		size = n;
		parent.resize(n+1); sz.resize(n+1); mx.resize(n+1); mn.resize(n+1);
		for(int i = 1; i<=n; i++){
			parent[i] = i;
			sz[i] = 1;
			mx[i] = i;
			mn[i] = i;
		}
	}
	int find(int x){
		if(parent[x]==x)return x;
		return find(parent[x]);
	}
	void Union(int x, int y){
		x = find(x); y = find(y);
		if(x==y)return;
		if(sz[x]<sz[y]){
			parent[x] = y;
			mx[y] = max(mx[y],mx[x]);
			mn[y] = min(mn[y],mn[x]);
			sz[y]+=sz[x];
		}
		else{
			parent[y] = x;
			sz[x]+=sz[y];
			mx[x] = max(mx[x],mx[y]);
			mn[x] = min(mn[x],mn[y]);
		}
	}
};
/*
condition:
when multi edges are removed and self edges are removed 

if there is a cycle, there can only be one and all nodes are adjacent to the cycle

if there is a forest, then everything touches the diameter of the tree
*/
int mxn = 200005;
vector<vector<int>>adj(mxn); int ln = 20;
vector<vector<int>>dp(mxn,vector<int>(ln));
vector<int>lvl(mxn);
void dfs(int u, int p){
	lvl[u] = lvl[p]+1;
	dp[u][0] = p;
	for(int i = 1; i<ln; i++){
		dp[u][i] = dp[dp[u][i-1]][i-1];
	}
	for(int nxt: adj[u]){
		if(nxt==p)continue;
		dfs(nxt,u);
	}
}
int lca(int x, int y){
	if(lvl[x]<lvl[y])swap(x,y);
	int dif = lvl[x]-lvl[y];
	for(int i = 0; i<ln; i++){
		if((1<<i)&dif){
			x = dp[x][i];
		}
	}
	if(x==y)return x;
	for(int i = ln-1; i>=0; i--){
		if(dp[x][i]!=dp[y][i]){
			x = dp[x][i]; y = dp[y][i];
		}
	}
	return dp[x][0];
}
int dist(int x, int y){
	int u = lca(x,y);
	return lvl[x]+lvl[y]-2*lvl[u];
}
signed main(){
	cin.tie(nullptr)->sync_with_stdio(false);
	int n,k;
	cin >> n >> k;
	DisjointSet ds;
	ds.init(k+1);
	int cnt = 0;
	map<pair<int,int>,int>hm;
	pair<int,int>p = {0,0};
	set<int>s;
	vector<int>bad(k+1);
	for(int i = 1; i<=n; i++){
		int x,y;
		cin >> x >> y;
		if(x>y)swap(x,y);
		s.insert(x);
		s.insert(y);
		if(x==y){
			bad[x] = 1;
		}
		if(x==y || hm[{x,y}])continue;
		hm[{x,y}] = 1;
		if(ds.find(x)==ds.find(y)){
			cnt++;
			p = {x,y};
		}
		else{
			ds.Union(x,y);
			adj[x].push_back(y);
			adj[y].push_back(x);
		}
	}
	assert((int)s.size() == k);
	if(cnt > 1){
		cout << "impossible\n";
		return 0;
	}
	if(cnt == 1){
		vector<int>cycle(k+1);
		int x = p.first;
		int y = p.second;
		dfs(x,0);
		int u = lca(x,y);
		cycle[u] = 1;
		while(x!=u){
			cycle[x] = 1;
			x = dp[x][0];
		}
		while(y!=u){
			cycle[y] = 1;
			y = dp[y][0];
		}
		for(int i = 1; i<=k; i++){
			bool good = false;
			if(cycle[i])continue;
			if(bad[i]){
				cout << "impossible\n";
				return 0;
			}
			for(int nxt: adj[i]){
				if(cycle[nxt])good = true;
			}
			if(!good){
				cout << "impossible\n";
				return 0;
			}
		}
		cout << "possible\n";
		return 0;
	}
	for(int i = 1; i<=k; i++){
		int cnt = 0;
		for(int nxt: adj[i]){
			if(bad[nxt] || adj[nxt].size()>=2)cnt++; 
		}
		if(cnt>2){
			cout << "impossible\n";
			return 0;
		}
	}
	cout << "possible\n";
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 7ms
memory: 48312kb

input:

7 6
2 2
3 6
1 1
1 5
4 5
6 6
6 5

output:

possible

result:

ok single line: 'possible'

Test #2:

score: 0
Accepted
time: 7ms
memory: 48300kb

input:

5 5
1 3
1 5
2 3
2 5
3 4

output:

possible

result:

ok single line: 'possible'

Test #3:

score: 0
Accepted
time: 3ms
memory: 48228kb

input:

6 7
1 2
2 3
3 4
4 5
3 6
6 7

output:

impossible

result:

ok single line: 'impossible'

Test #4:

score: 0
Accepted
time: 11ms
memory: 48208kb

input:

8 4
1 1
1 2
2 1
2 2
3 3
3 4
4 3
4 4

output:

possible

result:

ok single line: 'possible'

Test #5:

score: 0
Accepted
time: 3ms
memory: 48320kb

input:

4 4
1 2
2 1
3 4
4 3

output:

possible

result:

ok single line: 'possible'

Test #6:

score: 0
Accepted
time: 11ms
memory: 48224kb

input:

5 4
1 1
1 4
2 2
2 4
3 4

output:

possible

result:

ok single line: 'possible'

Test #7:

score: 0
Accepted
time: 8ms
memory: 48264kb

input:

6 4
1 1
1 4
2 2
2 4
3 3
3 4

output:

impossible

result:

ok single line: 'impossible'

Test #8:

score: 0
Accepted
time: 3ms
memory: 48296kb

input:

4 5
1 2
3 4
4 5
5 3

output:

impossible

result:

ok single line: 'impossible'

Test #9:

score: 0
Accepted
time: 3ms
memory: 48356kb

input:

4 4
1 1
2 3
3 4
4 2

output:

impossible

result:

ok single line: 'impossible'

Test #10:

score: -100
Runtime Error

input:

3 4
1 2
2 3
3 1

output:


result: