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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#359715 | #6560. Broken Minimum Spanning Tree | nkamzabek# | WA | 1ms | 3620kb | C++23 | 2.2kb | 2024-03-20 20:13:24 | 2024-03-20 20:13:25 |
Judging History
answer
#include <bits/stdc++.h>
#define f first
#define s second
#define sz(s) (int)s.size()
#define pb push_back
using namespace std;
using vi = vector<int>;
const int N = (int)5e3 + 100;
int n, m, u[N], v[N], w[N];
int up[N][20];
pair<int, int> mx[N][20];
vector<int> g[N];
bool mst[N];
int tin[N], tout[N], timer;
bool is_par(int u, int v){
return tin[u] <= tin[v] && tout[v] <= tout[u];
}
void dfs(int x, int par = 0, int ind = 0){
up[x][0] = par;
mx[x][0] = {w[ind], ind};
tin[x] = ++timer;
for(int i = 1; i < 20; i++){
up[x][i] = up[up[x][i - 1]][i - 1];
mx[x][i] = max(mx[x][i - 1], mx[up[x][i - 1]][i - 1]);
}
for(auto i : g[x]){
int to = (v[i] ^ u[i] ^ x);
if(to == par)
continue;
dfs(to, x, i);
}
tout[x] = timer;
}
int lca(int u, int v){
if(is_par(u, v)) return u;
if(is_par(v, u)) return v;
for(int i = 19; i >= 0; i--)
if(up[v][i] && !is_par(up[v][i], u))
v = up[v][i];
return up[v][0];
}
pair<int, int> get_max(int u, int v){
int l = lca(u, v);
pair<int, int> m = {0, 0};
for(int i = 19; i >= 0; i--){
if(up[u][i]){
if(is_par(l, up[u][i])){
u = up[u][i];
m = max(m, mx[u][i]);
}
}
if(up[v][i]){
if(is_par(l, up[v][i])){
v = up[v][i];
m = max(m, mx[v][i]);
}
}
}
return m;
}
main(){
ios_base :: sync_with_stdio(0);
cin.tie(0); cout.tie(0);
cin >> n >> m;
for(int i = 1; i <= m; i++){
cin >> u[i] >> v[i] >> w[i];
if(i < n) mst[i] = 1;
}
vector<pair<int, int> > ans;
while(1){
for(int i = 1; i <= n; i++) g[i].clear();
vector<int> ord;
bool found = 0;
for(int i = 1; i <= m; i++){
if(mst[i]){
g[u[i]].push_back(i);
g[v[i]].push_back(i);
}else{
ord.push_back(i);
}
}
dfs(1);
sort(ord.begin(), ord.end(), [&](int i, int j){
return w[i] < w[j];
});
for(int i : ord){
int a = u[i], b = v[i];
auto [val, j] = get_max(a, b);
if(w[j] > w[i]){
mst[i] = 1;
mst[j] = 0;
found = 1;
ans.push_back({j, i});
break;
}
}
if(!found)
break;
}
cout << sz(ans) << '\n';
for(auto [x, y] : ans)
cout << x << " " << y << "\n";
}
详细
Test #1:
score: 100
Accepted
time: 1ms
memory: 3592kb
input:
4 4 1 2 10 2 3 3 3 4 1 1 4 4
output:
1 1 4
result:
ok correct!
Test #2:
score: -100
Wrong Answer
time: 0ms
memory: 3620kb
input:
6 8 1 2 10 2 3 10 3 4 10 4 5 10 5 6 10 6 1 10 1 3 1 4 6 1
output:
1 3 8
result:
wrong answer not a spanning tree after swap 1