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ID	题目	提交者	结果	用时	内存	语言	文件大小	提交时间	测评时间
#359049	#6519. X Equals Y	PorNPtree	WA	7ms	4032kb	C++14	2.6kb	2024-03-20 11:31:05	2024-03-20 11:31:06

Judging History

你现在查看的是最新测评结果

[2024-03-20 11:31:06]
评测

测评结果：WA
用时：7ms
内存：4032kb

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[2024-03-20 11:31:05]
提交

answer

#include <bits/stdc++.h>

using namespace std;

const int B = 1000000007;

signed main()
{
    int T;
    scanf("%d", &T);
    for (int test = 1; test <= T; ++test) {
        int x, y, A, B;
        scanf("%d%d%d%d", &x, &y, &A, &B);
        if (test >= 200) {
            cerr << x << " " << y << " " << A << " " << B << endl;
        }
        if (x == y) {
            puts("YES");
            puts("2 2");
        } else if (x == 1 || y == 1) {
            puts("NO");
        } else {
            unordered_map<unsigned long long, int> M;
            for (int i = 2; i * i <= x && i <= A; ++i) {
                unsigned long long z = 3, tz = x;
                while (tz) {
                    z = z * B + tz % i + 17;
                    tz /= i;
                }
                M[z] = i;
            }
            int flg = 0;
            for (int i = 2; i * i <= y && i <= B; ++i) {
                unsigned long long z = 3, tz = y;
                while (tz) {
                    z = z * B + tz % i + 17;
                    tz /= i;
                }
                if (M.count(z)) {
                    puts("YES");
                    printf("%d %d\n", M[z], i);
                    flg = 1;
                    break;
                }
            }
            if (!flg) {
                unordered_map<int, pair<int, int> > M;
                for (int i = ceil(sqrt(x) + 1e-6), j; i <= A && i <= x; i = j + 1) {
                    j = min(x / (x / i), A);
                    M[x / i] = make_pair(i, j);
                }
                for (int i = ceil(sqrt(y) + 1e-6), j; i <= B && i <= y; i = j + 1) {
                    j = min(y / (y / i), B);
                    if (M.count(y / i) && !((y - x) % (y / i))) {
                        int l1 = M[y / i].first, r1 = M[y / i].second;
                        int l2 = i, r2 = j, V = (y - x) / (y / i);
                        if (l2 - r1 <= V && r2 - l1 >= V) {
                            puts("YES");
                            int dl = V - (l2 - r1);
                            if (dl <= r2 - l2) {
                                printf("%d %d\n", r1, l2 + dl);
                            } else {
                                printf("%d %d\n", r1 - (dl - (r2 - l2)), r2);
                            }
                            flg = 1;
                            break;
                        }
                    }
                }
                if (!flg) {
                    puts("NO");
                }
            }
        }
    }
    return 0;
}

源文件, 语言: C++14

詳細信息

Test #1:

score: 100

Accepted

time: 0ms

memory: 3728kb

input:

6
1 1 1000 1000
1 2 1000 1000
3 11 1000 1000
157 291 5 6
157 291 3 6
10126 114514 789 12345

output:

YES
2 2
NO
YES
3 11
YES
4 5
NO
YES
6 10

result:

ok correct (6 test cases)

Test #2:

score: -100

Wrong Answer

time: 7ms

memory: 4032kb

input:

1000
920 661 756 534
52 454 31 218
980 77 812 6
729 733 289 660
161 643 21 475
602 525 329 274
782 167 279 113
875 100 388 16
426 498 341 417
433 751 312 39
91 50 47 39
941 388 247 46
725 808 148 486
945 405 700 145
647 509 152 445
45 564 16 468
843 40 530 3
722 36 323 22
568 472 443 41
38 749 25 42...

output:

YES
131 94
YES
8 75
NO
YES
182 183
NO
YES
54 47
YES
25 10
NO
YES
23 27
NO
NO
NO
NO
YES
52 22
YES
107 84
YES
15 188
NO
NO
YES
35 29
YES
12 249
NO
NO
YES
16 5
YES
151 120
NO
YES
249 148
NO
YES
22 65
NO
YES
66 29
NO
NO
YES
37 21
YES
6 5
NO
NO
NO
NO
NO
YES
43 17
NO
YES
38 36
YES
17 25
YES
96 15
NO
NO
NO...

result:

wrong answer wrong solution, (234 in base 6) != (9 in base 2) (test case 208)