QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#357843 | #6534. Peg Solitaire | PorNPtree# | WA | 0ms | 3704kb | C++20 | 951b | 2024-03-19 13:50:22 | 2024-03-19 13:50:23 |
Judging History
answer
#include<bits/stdc++.h>
#define LL long long
#define P pair<int,int>
#define fi first
#define se second
#define fr(x) freopen(#x".in","r",stdin);freopen(#x".out","w",stdout);
using namespace std;
const int N=15,dx[]={0,0,1,-1},dy[]={1,-1,0,0};
int T,n,m,K,a[N][N],ans;
inline bool chk(int x,int y){return 1<=x&&x<=n&&1<=y&&y<=m;}
void dfs()
{
int cnt=0;
for(int i=1;i<=n;i++) for(int j=1;j<=m;j++) if(a[i][j]) cnt++;ans=min(ans,cnt);
for(int i=1;i<=n;i++) for(int j=1;j<=m;j++) if(a[i][j])
{
for(int k=0;k<4;k++)
{
int nx=i+dx[k],ny=j+dy[k],Nx=nx+dx[k],Ny=ny+dy[k];
if(!a[nx][ny]||a[Nx][Ny]||!chk(Nx,Ny)) continue;
a[i][j]=a[nx][ny]=0;a[Nx][Ny]=1;
dfs();
a[i][j]=a[nx][ny]=0;a[Nx][Ny]=1;
}
}
}
int main()
{
ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);cin>>T;
while(T--)
{
cin>>n>>m>>K;ans=K;
for(int i=1,x,y;i<=K;i++) cin>>x>>y,a[x][y]=1;
dfs();cout<<ans<<"\n";
}
return 0;
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 0ms
memory: 3644kb
input:
3 3 4 5 2 2 1 2 1 4 3 4 1 1 1 3 3 1 1 1 2 1 3 2 1 1 2 1
output:
2 3 1
result:
ok 3 number(s): "2 3 1"
Test #2:
score: -100
Wrong Answer
time: 0ms
memory: 3704kb
input:
20 2 1 2 1 1 2 1 5 1 3 3 1 2 1 4 1 3 3 6 1 2 2 2 1 1 2 3 3 1 3 2 4 4 4 2 3 3 1 3 2 1 2 1 1 1 1 1 5 2 6 3 2 4 1 2 1 5 2 2 2 5 1 1 3 1 1 2 1 5 1 1 5 4 6 5 4 6 4 4 2 3 4 3 1 6 6 6 3 2 4 1 3 2 1 2 2 2 2 1 1 1 5 3 4 2 2 5 1 4 3 3 2 6 5 6 5 5 6 5 2 4 2 1 3 4 1 4 2 6 5 1 6 2 1 1 4 2 3 1 3 3 5 6 2 1 3 3 1 5...
output:
2 2 3 1 1 3 1 1 4 3 2 4 3 4 2 2 2 1 6 2
result:
wrong answer 6th numbers differ - expected: '2', found: '3'