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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#357408#3047. Wind of ChangeHarry27182TL 0ms0kbC++142.9kb2024-03-18 21:04:092024-03-18 21:04:10

Judging History

你现在查看的是最新测评结果

  • [2024-03-18 21:04:10]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:0kb
  • [2024-03-18 21:04:09]
  • 提交

answer

#include<bits/stdc++.h>
#define int long long
using namespace std;
int n,u,v,w,ans[250005];vector<int>now;
struct Tree
{
	struct edge{int v,w,nxt;}e[500005];
	int cnt,h[250005],siz[250005],mx[250005],rt,S,p[250005];
	int dep[250005],f[250005][20],vis[250005];vector<int>g[250005];
	void add(int u,int v,int w){e[++cnt]={v,w,h[u]};h[u]=cnt;}
	void find(int u,int fa)
	{
		siz[u]=1;mx[u]=0;
		for(int i=h[u];i;i=e[i].nxt)
		{
			int v=e[i].v;
			if(v==fa||vis[v])continue;
			find(v,u);siz[u]+=siz[v];mx[u]=max(mx[u],siz[v]);
		}
		mx[u]=max(mx[u],S-siz[u]);
		if(mx[u]<mx[rt])rt=u;
	}
	int get(int u,int fa)
	{
		int res=1;
		for(int i=h[u];i;i=e[i].nxt)
		{
			int v=e[i].v;
			if(v==fa||vis[v])continue;
			res+=get(v,u);
		}
		return res;
	}
	void solve(int u)
	{
		vis[u]=1;
		for(int i=h[u];i;i=e[i].nxt)
		{
			int v=e[i].v;
			if(vis[v])continue;
			mx[rt=0]=0x3f3f3f3f;S=get(v,u);find(v,u);
			p[rt]=u;g[u].emplace_back(rt);solve(rt);
		}
	}
	void main()
	{
		mx[rt=0]=0x3f3f3f3f;S=n;find(1,0);solve(rt);
	}
	void dfs(int u)
	{
		now.emplace_back(u);
		for(int i=0;i<g[u].size();i++)dfs(g[u][i]);
	}
	void init(int u,int fa)
	{
		f[u][0]=fa;
		for(int i=1;(1<<i)<=n;i++)f[u][i]=f[f[u][i-1]][i-1];
		for(int i=h[u];i;i=e[i].nxt)
		{
			int v=e[i].v;
			if(v==fa)continue;
			dep[v]=dep[u]+e[i].w;init(v,u);
		}
	}
	int lca(int u,int v)
	{
		if(dep[u]<dep[v])swap(u,v);
		for(int i=18;i>=0;i--)if(dep[f[u][i]]>=dep[v])u=f[u][i];
		if(u==v)return u;
		for(int i=18;i>=0;i--)if(f[u][i]!=f[v][i])u=f[u][i],v=f[v][i];
		return f[u][0];
	}
	int dis(int u,int v){return dep[u]+dep[v]-2*dep[lca(u,v)];}
}T1,T2;
struct node{int w,x;}mn[250005][2];
bool operator ==(node x,node y){return x.w==y.w&&x.x==y.x;}
bool operator <(node x,node y){return x.w<y.w;}
signed main()
{
	cin.tie(0)->sync_with_stdio(0);
	cin>>n;
	for(int i=1;i<n;i++)
	{
		cin>>u>>v>>w;
		T1.add(u,v,w);T1.add(v,u,w);
	}
	for(int i=1;i<n;i++)
	{
		cin>>u>>v>>w;
		T2.add(u,v,w);T2.add(v,u,w);
	}
	T1.init(1,0);T2.init(1,0); 
	T1.main();T2.main();
	for(int i=1;i<=n;i++)mn[i][0]=mn[i][1]={0x3f3f3f3f3f3f3f3f,0},ans[i]=0x3f3f3f3f3f3f3f3f;
	for(int i=1;i<=n;i++)
	{
		now.clear();now.shrink_to_fit();
		T1.dfs(i);
		for(int j=0;j<now.size();j++)
		{
			int x=now[j];
			for(int k=x;k;k=T2.p[k])
			{
				node now={T1.dis(x,i)+T2.dis(x,k),x};
				if(now<mn[k][0])mn[k][1]=mn[k][0],mn[k][0]=now;
				else if(now<mn[k][1])mn[k][1]=now;
			}
		}
		for(int j=0;j<now.size();j++)
		{
			int x=now[j];
			for(int k=x;k;k=T2.p[k])
			{
				node now={T1.dis(x,i)+T2.dis(x,k),x};
				if(mn[k][0]==now)ans[x]=min(ans[x],mn[k][1].w+now.w);
				else ans[x]=min(ans[x],mn[k][0].w+now.w);
			}
		}
		for(int j=0;j<now.size();j++)
		{
			int x=now[j];
			for(int k=x;k;k=T2.p[k])mn[k][0]=mn[k][1]={0x3f3f3f3f3f3f3f3f,0};
		}
	}
	for(int i=1;i<=n;i++)cout<<ans[i]<<'\n';
	return 0;
}

详细

Test #1:

score: 0
Time Limit Exceeded

input:

250000
137466 116241 624409157
188961 163586 148491970
13958 122239 46409636
186120 44010 919858866
72320 102560 92679302
158544 236582 882613876
22331 114267 646741536
210782 42861 679450428
56693 45397 898958944
71188 114724 904191407
15203 225401 210626781
31071 144225 278121829
110354 83972 4557...

output:


result: