QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#357401#5460. Sum of NumberslouziyangTL 11ms73192kbC++142.1kb2024-03-18 21:00:422024-03-18 21:00:44

Judging History

你现在查看的是最新测评结果

  • [2024-03-18 21:00:44]
  • 评测
  • 测评结果:TL
  • 用时:11ms
  • 内存:73192kb
  • [2024-03-18 21:00:42]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
const int MAXN=2e5+7;
struct node{
	string str;
}a,tot,minx,it,vis[11][MAXN];
int l1[MAXN],l2[MAXN],l3[MAXN],n,k,len;
node minu(node x,node y)
{
	if(x.str.size()<y.str.size())
		return x;
	if(x.str.size()>y.str.size())
		return y;
	if(x.str<y.str)
		return x;
	else
		return y;
}
bool operator == (const node &x,const node &y)
{
	return x.str==y.str;
}
node operator + (const node &x,const node &y)
{
	if(x.str.size()==0)
		return y;
	if(y.str.size()==0)
		return x;
	node ans;
	ans.str="";
	int len1=x.str.size(),len2=y.str.size(),len3;
	for(int i(1);i<=len1;++i)
		l1[len1-i+1]=x.str[i-1]-'0';
	for(int i(1);i<=len2;++i)
		l2[len2-i+1]=y.str[i-1]-'0';
	len3=max(len1,len2);
	for(int i(1);i<=len3+2;++i)
		l3[i]=0;
	for(int i(1);i<=max(len1,len2);++i)
	{
		if(i>len1)
		l1[i]=0;
		if(i>len2)
		l2[i]=0;
		l3[i]+=(l1[i]+l2[i])%10;
		l3[i+1]+=(l1[i]+l2[i])/10;
	}
	for(int i(1);i<=len3;++i)
	{
		l3[i+1]+=l3[i]/10;
		l3[i]%=10;
		if(l3[i+1])
			len3=max(i+1,len3);
	}
	for(int i(len3);i>=1;--i)
		ans.str+=l3[i]+'0';
	return ans;
}
void dfs(node s,int x,int l,int cnt)
{
	if(l==0||l>=n)
		return ;
	if(x>=n||cnt>k)
		return ;
	if(vis[cnt][x].str.size()==0)
		vis[cnt][x]=s;
	else
	{
		if(minu(vis[cnt][x],s)==vis[cnt][x])
			return ;
		vis[cnt][x]=s;
	}
	if(cnt==k)
	{
		it.str=a.str.substr(x,n-x);
		minx=minu(minx,it+s);
		return ;
	}
	it.str=a.str.substr(x,l-1);
	dfs(s+it,x+l-1,l-1,cnt+1);
	it.str=a.str.substr(x,l);
	dfs(s+it,x+l,l,cnt+1);
	it.str=a.str.substr(x,l+1);
	dfs(s+it,x+l+1,l+1,cnt+1);
	return ;
}
int main()
{
	ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
	int t;
	cin>>t;
	while(t--)
	{
		cin>>n>>k;
		cin>>a.str;
		minx.str=a.str;
		len=n/(k+1);
		for(int i(1);i<=k+1;++i)
			for(int j(0);j<=n;++j)
				vis[i][j].str="";
		for(int i(1);i<=len;++i)
		{
			tot.str=a.str.substr(0,i);
			dfs(tot,i,i,1);
		}
//		tot.str=a.str.substr(0,len);
//		dfs(tot,len,len,1);
//		tot.str=a.str.substr(0,len+1);
//		dfs(tot,len+1,len+1,1);
		cout<<minx.str<<endl;
	}
	return 0;
 } 

详细

Test #1:

score: 100
Accepted
time: 11ms
memory: 73192kb

input:

2
8 1
45455151
2 1
42

output:

9696
6

result:

ok 2 lines

Test #2:

score: -100
Time Limit Exceeded

input:

10
1301 6
56328399613959594774559774218276494124991536454496431869449134772679831477279356599352619469813771742358572734317965823527349354276551857226632977613336815474383422853946661428822284645652423563864641261338984158269966469425994769486371736593879954275146732544891889693921182364554588732946...

output:

3636733938342862284777290619398546887683961166197063357533275680300947575804595063814840014749117946250672724491502190322946481853515966096183519240978624493356281380857186769171673750050

result: