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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#357175 | #7103. Red Black Tree | arnold518 | AC ✓ | 957ms | 27484kb | C++17 | 2.0kb | 2024-03-18 19:02:38 | 2024-03-18 19:02:40 |
Judging History
answer
#include <bits/stdc++.h>
#define ff first
#define ss second
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
const int MAXN = 1e5;
int TC, N, M, Q;
int R[MAXN+10];
int P[MAXN+10];
ll D[MAXN+10];
vector<pii> adj[MAXN+10];
int par[MAXN+10][30], dep[MAXN+10];
void dfs(int now, int bef, ll d, int d2, int root)
{
par[now][0]=bef;
dep[now]=d2;
if(R[now]) root=now, d=0;
P[now]=root;
D[now]=d;
for(auto [nxt, w] : adj[now])
{
if(nxt==bef) continue;
dfs(nxt, now, d+w, d2+1, root);
}
}
int lca(int u, int v)
{
if(dep[u]>dep[v]) swap(u, v);
for(int i=20; i>=0; i--) if(dep[par[v][i]]>=dep[u]) v=par[v][i];
if(u==v) return u;
for(int i=20; i>=0; i--) if(par[u][i]!=par[v][i]) u=par[u][i], v=par[v][i];
return par[u][0];
}
int main() {
cin.tie(0); ios_base::sync_with_stdio(0);
scanf("%d", &TC);
while(TC--)
{
scanf("%d%d%d", &N, &M, &Q);
for(int i=1; i<=M; i++)
{
int t;
scanf("%d", &t);
R[t]=1;
}
for(int i=1; i<N; i++)
{
int u, v, w;
scanf("%d%d%d", &u, &v, &w);
adj[u].push_back({v, w});
adj[v].push_back({u, w});
}
dfs(1, 1, 0, 1, 1);
for(int i=1; i<=20; i++) for(int j=1; j<=N; j++) par[j][i]=par[par[j][i-1]][i-1];
while(Q--)
{
int sz;
scanf("%d", &sz);
vector<int> V(sz);
for(auto &it : V) scanf("%d", &it);
int u=V[0];
for(int i=0; i<V.size(); i++) if(D[u]<D[V[i]]) u=V[i];
ll ansv=0, ans=0;
vector<int> VV;
for(int i=0; i<V.size(); i++)
{
ans=max(ans, D[V[i]]);
if(P[u]==P[V[i]]) VV.push_back(V[i]);
else ansv=max(ansv, D[V[i]]);
}
sort(VV.begin(), VV.end(), [&](const int &p, const int &q) { return D[p]>D[q]; });
int now=VV[0];
for(int i=0; i<VV.size(); i++)
{
now=lca(now, VV[i]);
ll t=0;
if(i+1<VV.size()) t=D[VV[i+1]];
ans=min(ans, max({D[VV[0]]-D[now], t, ansv}));
}
printf("%lld\n", ans);
}
for(int i=1; i<=N; i++)
{
adj[i].clear();
R[i]=0;
}
}
}
这程序好像有点Bug,我给组数据试试?
Details
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Test #1:
score: 100
Accepted
time: 1ms
memory: 7952kb
input:
2 12 2 4 1 9 1 2 1 2 3 4 3 4 3 3 5 2 2 6 2 6 7 1 6 8 2 2 9 5 9 10 2 9 11 3 1 12 10 3 3 7 8 4 4 5 7 8 4 7 8 10 11 3 4 5 12 3 2 3 1 2 1 2 1 1 3 1 1 1 2 1 2 3 1 2 3
output:
4 5 3 8 0 0 0
result:
ok 7 lines
Test #2:
score: 0
Accepted
time: 957ms
memory: 27484kb
input:
522 26 1 3 1 1 4 276455 18 6 49344056 18 25 58172365 19 9 12014251 2 1 15079181 17 1 50011746 8 9 2413085 23 24 23767115 22 2 26151339 26 21 50183935 17 14 16892041 9 26 53389093 1 20 62299200 24 18 56114328 11 2 50160143 6 26 14430542 16 7 32574577 3 16 59227555 3 15 8795685 4 12 5801074 5 20 57457...
output:
148616264 148616264 0 319801028 319801028 255904892 317070839 1265145897 1265145897 1072765445 667742619 455103436 285643094 285643094 285643094 317919339 0 785245841 691421476 605409472 479058444 371688030 303203698 493383271 919185207 910180170 919185207 121535083 181713164 181713164 181713164 181...
result:
ok 577632 lines
Extra Test:
score: 0
Extra Test Passed