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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#357043#5418. Color the TreeInexhaustible#WA 14ms17396kbC++142.9kb2024-03-18 17:43:582024-03-18 17:43:59

Judging History

你现在查看的是最新测评结果

  • [2024-03-18 17:43:59]
  • 评测
  • 测评结果:WA
  • 用时:14ms
  • 内存:17396kb
  • [2024-03-18 17:43:58]
  • 提交

answer

#include <set>
#include <map>
#include <list>
#include <queue>
#include <cmath>
#include <time.h>
#include <random>
#include <bitset>
#include <vector>
#include <cstdio>
#include <stdio.h>
#include <assert.h>
#include <stdlib.h>
#include <memory.h>
#include <string.h>
#include <iostream>
#include <algorithm>
#include <unordered_map>

using namespace std;

typedef long long ll;
typedef unsigned long long ull;

#define mk make_pair
#define fi first
#define se second

inline int read(){
	int t = 0,f = 1;
	register char c = getchar();
	while (c < 48 || c > 57) f = (c == '-') ? (-1) : (f),c = getchar();
	while (c >= 48 && c <= 57) t = (t << 1) + (t << 3) + (c ^ 48),c = getchar();
	return f * t;
}

const int N = 1e5 + 10,LOGN = 17 + 1;
int T,n,idcnt,a[N],id[N],dep[N],mxdep[N],son[N],top[N],fa[N],dwn[N],lst[N];
int mlg[1 << LOGN],mn[LOGN][N];
ll dp[N];

vector <int> G[N];

void init(){
	mlg[0] = -1;
	for (int i = 1;i <= n;i++) mlg[i] = mlg[i >> 1] + 1;
	for (int i = 0;i < n;i++) mn[0][i] = a[i];
	for (int i = 1;i < LOGN;i++){
		for (int j = 0;j < n;j++){
			mn[i][j] = mn[i - 1][j];
			if (j + (1 << (i - 1)) < n) mn[i][j] = min(mn[i][j],mn[i - 1][j + (1 << (i - 1))]);
		}
	}
}

inline int getmn(int l,int r){
	int t = mlg[r - l + 1];
	return min(mn[t][l],mn[t][r - (1 << t) + 1]);
}

void dfs0(int u,int f){
	mxdep[u] = dep[u] = dep[f] + 1,fa[u] = f;
	son[u] = 0;
	for (int v : G[u]){
		if (v == f) continue;
		dfs0(v,u),mxdep[u] = max(mxdep[u],mxdep[v]);
		if (mxdep[v] > mxdep[son[u]]) son[u] = v;
	}
}

void dfs1(int u,int t){
	id[u] = ++idcnt,top[u] = t,dwn[t] = max(dwn[t],id[u]);
	if (son[u]) dfs1(son[u],t);
	for (int v : G[u]){
		if (v == fa[u] || v == son[u]) continue;
		dfs1(v,v);
	}
}

void upd(int u,int d){
	if (lst[u] >= d) return ;
	ll v = getmn(lst[u] + 1,d);
	dp[u] = min(dp[u],v);
	lst[u] = d;
}

void DP(int u){
	for (int v : G[u]){
		if (v == fa[u]) continue;
		DP(v);
	}
	dp[id[u]] = a[0],lst[id[u]] = 0;
	int mxd = 0;
	for (int v : G[u]){
		if (v == fa[u] || v == son[u]) continue;
		mxd = max(mxd,mxdep[v]);
	}
	for (int v : G[u]){
		if (v == fa[u] || v == son[u]) continue;
		for (int i = id[v];i <= dwn[v];i++){
			dp[id[u] + i - id[v] + 1] += dp[i];
		}
	}
	for (int i = id[u];i <= id[u] + mxd - dep[u];i++){
		upd(i,i - id[u]);
	}
}

void solve(){
	n = read();
	for (int i = 0;i < n;i++) a[i] = read();
	init();
	for (int i = 1;i <= n;i++) G[i].clear(),dwn[i] = 0;
	for (int i = 1;i < n;i++){
		int u = read(),v = read();
		G[u].emplace_back(v),G[v].emplace_back(u);
	}
	idcnt = 0;
	dfs0(1,0);
	dfs1(1,1);
	DP(1);
	ll ans = 0;
	for (int i = id[1];i <= dwn[1];i++){
		upd(i,i - id[1]);
		ans += dp[i];
	}
	printf("%lld\n",ans);
}

int main(){
#ifndef ONLINE_JUDGE
	freopen("in.in","r",stdin);
	// freopen("out.out","w",stdout);
#endif
	T = read();
	while (T--) solve();
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 3ms
memory: 17396kb

input:

3
4
10 15 40 1
1 2
2 3
2 4
5
10 5 1 100 1000
1 2
2 3
2 4
4 5
4
1000 200 10 8
1 2
2 3
3 4

output:

35
17
1218

result:

ok 3 number(s): "35 17 1218"

Test #2:

score: -100
Wrong Answer
time: 14ms
memory: 15972kb

input:

3000
54
43 44 11 49 17 14 7 30 35 12 34 14 15 8 29 47 30 31 39 17 26 23 26 45 34 50 49 13 35 18 29 15 13 44 47 5 22 20 19 46 30 22 26 13 47 46 43 27 48 48 13 14 30 44
1 2
1 3
2 4
3 5
4 6
2 7
4 8
1 9
3 10
1 11
8 12
2 13
9 14
1 15
1 16
15 17
15 18
7 19
1 20
19 21
13 22
10 23
17 24
9 25
9 26
24 27
8 28...

output:

180
134
222
222
156
255
225
126
100
79
139
73
140
127
143
119
228
179
131
171
128
171
78
282
195
286
152
200
119
188
209
213
88
252
207
206
160
179
184
144
109
148
180
169
226
210
182
85
162
59
56
31
115
216
201
144
155
212
53
155
189
134
173
134
216
106
163
255
80
339
156
133
129
156
219
269
148
22...

result:

wrong answer 2nd numbers differ - expected: '168', found: '134'