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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#356194#1067. TOLLparlimoos16 3ms11492kbC++144.4kb2024-03-17 16:38:122024-11-07 12:40:53

Judging History

你现在查看的是最新测评结果

  • [2024-11-07 12:40:53]
  • 管理员手动重测本题所有提交记录
  • 测评结果:16
  • 用时:3ms
  • 内存:11492kb
  • [2024-03-17 16:38:13]
  • 评测
  • 测评结果:100
  • 用时:2ms
  • 内存:9744kb
  • [2024-03-17 16:38:12]
  • 提交

answer

//Be Name KHODA
#pragma GCC optimize("Ofast")
#include<bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef long double ld;
#define pb push_back
#define pp pop_back
#define lb lower_bound
#define ub upper_bound
#define cl clear
#define bg begin
#define arr(x) array<int , x>
#define endl '\n'

int n , m , k;
vector<arr(3)> mst;
vector<int> a;
vector<arr(2)> adds , g[100000];
ll dsuc[100000] , bckc[1000000] , mem[100000];
int dsuinx = -1 , dsucnt = 0 , cnds[21][3] , uss[21][2] , uns[21][3];
int dsuv[100000] , bckv[1000000][2];
bool iscnd[100000] , bckms[100000];

void init(){
    for(int v = 0 ; v < n ; v++) dsuv[v] = -1 , dsuc[v] = a[v];
}
void svDsu(int v){
    if(!bckms[v]) bckv[dsucnt][0] = v , bckv[dsucnt][1] = dsuv[v] , bckc[dsucnt++] = dsuc[v] , bckms[v] = 1;
}
int findDsu(int v){
    if(dsuv[v] == -1) return v;
    if(dsuinx != -1) svDsu(v);
    return (dsuv[v] = findDsu(dsuv[v]));
}
void uDsu(int b , int a){
    a = findDsu(a) , b = findDsu(b);
    if(a == b) return;
    if(dsuinx != -1) svDsu(a) , svDsu(b);
    dsuc[a] += dsuc[b] , dsuv[b] = a;
}
void clDsu(){
    for(int i = dsucnt - 1 ; i >= dsuinx ; i--) dsuv[bckv[i][0]] = bckv[i][1] , dsuc[bckv[i][0]] = bckc[i] , bckms[bckv[i][0]] = 0;
    dsucnt = dsuinx;
}
void getCnds(){
    for(auto &e : adds) uDsu(e[0] , e[1]);
    int cnt = 0;
    for(int e = 0 ; e < n - 1 ; e++){
        if(findDsu(mst[e][1]) == findDsu(mst[e][2])) cnds[cnt][0] = mst[e][0] , cnds[cnt][1] = mst[e][1] , cnds[cnt++][2] = mst[e][2] , iscnd[e] = 1;
        else uDsu(mst[e][1] , mst[e][2]);
    }
    cnds[cnt][0] = -1;
    init();
    for(int e = 0 ; e < n - 1 ; e++){
        if(!iscnd[e]) uDsu(mst[e][1] , mst[e][2]);
    }
    dsuinx = 0;
}
int bs(int e , int msk){
    dsuinx = dsucnt;
    for(int i = 0 ; i < k ; i++){
        if(i == e or !((msk >> i) & 1)) continue;
        uDsu(adds[i][0] , adds[i][1]);
    }
    int res = 0;
    for(int i = 0 ; uns[i][0] != -1 ; i++){
        if(findDsu(adds[e][0]) == findDsu(adds[e][1])) break;
        res = uns[i][0] , uDsu(uns[i][1] , uns[i][2]);
    }
    clDsu() , dsuinx = 0;
    return res;
}
ll dfs1(int v , int p){
    ll res = 0;
    mem[v] = dsuc[v];
    for(auto &e : g[v]){
        int u = e[0] - v;
        if(u == p) continue;
        res += dfs1(u , v) , mem[v] += mem[u];
        res += (1ll * e[1]) * mem[u];
    }
    return res;
}
ll getCst(int msk){
    ll res;
    for(int e = 0 ; e < k ; e++){
        if(!((msk >> e) & 1)) continue;
        int r1 = findDsu(adds[e][0]) , r2 = findDsu(adds[e][1]);
        if(r1 == r2){
            clDsu();
            return 0;
        }
        uDsu(r1 , r2);
    }
    int c1 = 0 , c2 = 0;
    for(int i = 0 ; cnds[i][0] != -1 ; i++){
        int r1 = findDsu(cnds[i][1]) , r2 = findDsu(cnds[i][2]);
        if(r1 == r2) uns[c1][0] = cnds[i][0] , uns[c1][1] = cnds[i][1] , uns[c1++][2] = cnds[i][2];
        else uDsu(r1 , r2) , uss[c2][0] = cnds[i][1] , uss[c2++][1] = cnds[i][2];
    }
    uns[c1][0] = -1 , uss[c2][0] = -1;
    clDsu();
    for(int i = 0 ; uss[i][0] != -1 ; i++) uDsu(uss[i][0] , uss[i][1]);
    for(int i = 0 ; i < dsucnt ; i++) bckms[bckv[i][0]] = 0;
    for(int e = 0 ; e < k ; e++){
        if(((msk >> e) & 1)){
            int r1 = findDsu(adds[e][0]) , r2 = findDsu(adds[e][1]) , d = bs(e , msk);
            g[r1].pb({r1 + r2 , d}) , g[r2].pb({r1 + r2 , d});
        }
    }
    res = dfs1(findDsu(0) , -1);
    for(int e = 0 ; e < k ; e++) if(((msk >> e) & 1)) g[findDsu(adds[e][0])].pp() , g[findDsu(adds[e][1])].pp();
    clDsu();
    return res;
}
ll f(){
    ll res = 0;
    for(int msk = 1 ; msk < (1 << k) ; msk++){
        res = max(res , getCst(msk));
    }
    return res;
}

int main(){
    ios::sync_with_stdio(0);
    cin.tie(0);

    cin >> n >> m >> k;
    vector<arr(3)> es;
    for(int i = 0 ; i < m ; i++){
        int v , u , c;
        cin >> v >> u >> c;
        v-- , u--;
        es.pb({c , v , u});
    }
    for(int i = 0 ; i < k ; i++){
        int v , u;
        cin >> v >> u;
        adds.pb({v - 1 , u - 1});
    }
    for(int i = 0 ; i < n ; i++){
        int d;
        cin >> d;
        a.pb(d);
    }
    init();
    sort(es.bg() , es.end());
    for(auto e : es){
        if(findDsu(e[1]) == findDsu(e[2])) continue;
        mst.pb(e) , uDsu(e[1] , e[2]);
    }
    init() , getCnds();
    cout << f();
}

Details

Tip: Click on the bar to expand more detailed information

Subtask #1:

score: 16
Accepted

Test #1:

score: 16
Accepted
time: 0ms
memory: 11492kb

input:

10 20 1
9 10 378587
3 10 283693
10 1 276961
8 1 828871
6 3 814717
3 5 701468
4 8 116841
7 5 859891
2 5 973550
9 2 460881
6 5 260184
8 9 895822
3 8 864166
10 4 746770
6 9 818592
7 1 748443
6 2 308698
6 7 170433
6 1 854347
2 10 641070
8 2
739814 240233 280283 628215 946109 596323 536584 590185 294679 ...

output:

909864568000

result:

ok single line: '909864568000'

Test #2:

score: 16
Accepted
time: 3ms
memory: 10976kb

input:

8 20 1
7 2 707898
6 4 739797
6 1 921019
7 3 739954
2 6 26438
5 4 242350
8 5 147225
7 6 53026
2 5 18161
5 1 319852
8 1 928770
6 5 291033
6 8 870601
3 5 596483
4 8 769617
1 4 516480
3 8 960359
2 3 672639
7 8 951165
3 4 911419
7 5
485318 528016 310567 880656 812984 803814 654959 289193

output:

34729855934

result:

ok single line: '34729855934'

Subtask #2:

score: 0
Runtime Error

Dependency #1:

100%
Accepted

Test #3:

score: 0
Runtime Error

input:

26 50 10
10 16 402572
16 17 883196
13 26 698082
5 16 96211
11 16 642512
16 22 44910
5 2 928962
3 24 834337
2 12 56104
18 1 851938
4 14 441768
6 21 793020
25 7 341805
7 22 664203
25 19 671175
8 7 362800
7 6 377915
21 20 975066
8 4 264657
4 26 445906
9 26 821755
18 9 285249
3 17 120207
11 15 816139
23...

output:


result:


Subtask #3:

score: 0
Skipped

Dependency #1:

100%
Accepted

Dependency #2:

0%

Subtask #4:

score: 0
Skipped

Dependency #1:

100%
Accepted

Dependency #2:

0%

Subtask #5:

score: 0
Skipped

Dependency #1:

100%
Accepted

Dependency #2:

0%

Subtask #6:

score: 0
Skipped

Dependency #1:

100%
Accepted

Dependency #2:

0%