QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#354353 | #6434. Paimon Sorting | PorNPtree | AC ✓ | 133ms | 4684kb | C++14 | 1.1kb | 2024-03-15 10:45:25 | 2024-03-15 10:45:27 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 5;
int n, vis[N], s[N];
void modify(int x)
{
for (; x <= n; x += x & -x) {
++s[x];
}
return;
}
int query(int x)
{
int res = 0;
for (; x; x -= x & -x) {
res += s[x];
}
return res;
}
signed main()
{
int T;
scanf("%d", &T);
while (T--) {
int z = 0, a1, t = 0;
scanf("%d", &n);
long long A = 0;
for (int i = 1; i <= n; ++i) {
vis[i] = s[i] = 0;
}
for (int i = 1, x; i <= n; ++i) {
scanf("%d", &x);
if (i == 1) {
a1 = x;
}
if (!vis[x]) {
modify(x);
vis[x] = 1;
}
if (i > 1 && x == a1) {
t = 1;
} else if (x > a1) {
A += z + 1;
z = t = 0;
swap(a1, x);
}
z += t;
A += query(n) - query(x);
printf("%lld%c", A, " \n"[i == n]);
}
}
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 1ms
memory: 3752kb
input:
3 5 2 3 2 1 5 3 1 2 3 1 1
output:
0 2 3 5 7 0 2 4 0
result:
ok 3 lines
Test #2:
score: 0
Accepted
time: 133ms
memory: 4684kb
input:
6107 19 10 13 8 8 11 18 12 9 15 19 6 13 11 11 17 9 14 2 18 12 1 8 10 2 10 2 6 1 5 9 5 7 16 14 4 2 15 12 14 10 3 2 9 15 4 12 9 5 15 10 3 2 5 6 7 8 6 1 6 4 18 6 5 12 12 11 2 10 10 5 10 13 15 13 10 17 7 11 2 1 1 2 1 1 3 2 1 2 17 11 15 3 10 7 15 15 10 5 17 3 3 14 13 11 11 2 3 2 2 3 7 6 1 7 5 3 5 1 7 2 1...
output:
0 2 4 6 7 9 11 16 17 19 28 31 36 41 43 51 55 67 68 0 2 4 6 6 8 10 14 17 18 22 25 0 1 3 5 7 8 11 16 22 26 26 31 33 37 42 42 0 1 3 5 7 9 11 17 19 23 0 1 3 3 4 8 10 12 16 18 27 29 30 34 36 42 46 55 0 0 0 0 1 1 0 2 4 6 9 9 9 11 15 21 27 33 35 38 42 46 55 0 0 3 0 1 3 5 8 10 14 0 1 3 4 6 9 9 0 1 1 3 7 11 ...
result:
ok 6107 lines