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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#353669#6426. Interested in SkiingPorNPtreeWA 0ms3948kbC++142.3kb2024-03-14 14:45:102024-03-14 14:45:11

Judging History

你现在查看的是最新测评结果

  • [2024-03-14 14:45:11]
  • 评测
  • 测评结果:WA
  • 用时:0ms
  • 内存:3948kb
  • [2024-03-14 14:45:10]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

const int N = 105;

int n, a[N], b[N], c[N], d[N];
pair<int, int> pr[N * 2];
double f[N * 2];
mt19937 rnd;

int ins(double a, double b, double c, double d, double e, double f, double g, double h)
{
    a += (double)rnd() / 1e15, b += (double)rnd() / 1e15, c += (double)rnd() / 1e15, d += (double)rnd() / 1e15;
    e += (double)rnd() / 1e15, f += (double)rnd() / 1e15, g += (double)rnd() / 1e15, h += (double)rnd() / 1e15;
    double k1 = (d - b) / (c - a), b1 = b - k1 * a;
    double k2 = (h - f) / (g - e), b2 = f - k2 * e;
    double ix = (b2 - b1) / (k1 - k2), iy = k1 * ix + b1;
    return ix > min(a, c) - 1e-5 && ix < max(a, c) + 1e-5 && ix > min(e, g) - 1e-5 && ix < max(e, g) + 1e-5 && iy > min(b, d) - 1e-5 && iy < max(b, d) + 1e-5 && iy > min(f, h) - 1e-5 && iy < max(f, h) + 1e-5 && fabs(ix - a) + fabs(iy - b) > 1e-5 && fabs(ix - c) + fabs(iy - d) > 1e-5 && fabs(ix - e) + fabs(iy - f) > 1e-5 && fabs(ix - g) + fabs(iy - h) > 1e-5;
}

int check(double a, double b, double c, double d)
{
    for (int i = 1; i <= n; ++i) {
        if (ins(a, b, c, d, ::a[i], ::b[i], ::c[i], ::d[i])) {
            return 0;
        }
    }
    return 1;
}

signed main()
{
    int m, V;
    scanf("%d%d%d", &n, &m, &V);
    for (int i = 1; i <= n; ++i) {
        scanf("%d%d%d%d", &a[i], &b[i], &c[i], &d[i]);
        pr[i * 2 - 1] = make_pair(b[i], a[i]);
        pr[i * 2] = make_pair(d[i], c[i]);
    }
    sort(pr + 1, pr + n + n + 1);
    double res = 1e10;
    for (int i = 1; i <= n + n; ++i) {
        f[i] = 1e10;
        if (pr[i].second <= -m || pr[i].second >= m) {
            continue;
        }
        if (check(pr[i].second, -20000, pr[i].second, pr[i].first)) {
            f[i] = 0;
        } else {
            for (int j = 1; j < i; ++j) {
                if (pr[i].first != pr[j].first && check(pr[j].second, pr[j].first, pr[i].second, pr[i].first)) {
                    f[i] = min(f[i], max(f[j], fabs((double)(pr[i].second - pr[j].second) / (pr[i].first - pr[j].first))));
                }
            }
        }
        if (check(pr[i].second, pr[i].first, pr[i].second, 20000)) {
            res = min(res, f[i]);
        }
    }
    if (res > 5e9) {
        puts("-1");
    } else {
        printf("%.10lf\n", res * V);
    }
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3948kb

input:

3 2 1
-2 0 1 0
-1 4 2 4
0 1 0 3

output:

1.0000000000

result:

ok found '1.0000000', expected '1.0000000', error '0.0000000'

Test #2:

score: 0
Accepted
time: 0ms
memory: 3624kb

input:

2 1 2
-1 0 1 0
1 1 0 1

output:

-1

result:

ok found '-1.0000000', expected '-1.0000000', error '-0.0000000'

Test #3:

score: 0
Accepted
time: 0ms
memory: 3912kb

input:

2 3 7
-3 0 2 2
3 1 -2 17

output:

1.8666666667

result:

ok found '1.8666667', expected '1.8666667', error '0.0000000'

Test #4:

score: 0
Accepted
time: 0ms
memory: 3852kb

input:

1 100 1
-100 0 99 0

output:

0.0000000000

result:

ok found '0.0000000', expected '0.0000000', error '-0.0000000'

Test #5:

score: 0
Accepted
time: 0ms
memory: 3944kb

input:

3 8 3
-8 -9 0 -9
-6 -6 6 6
8 9 0 9

output:

6.0000000000

result:

ok found '6.0000000', expected '6.0000000', error '0.0000000'

Test #6:

score: -100
Wrong Answer
time: 0ms
memory: 3880kb

input:

3 8 3
-8 9 0 9
-6 6 6 -6
8 -9 0 -9

output:

0.0000000000

result:

wrong answer 1st numbers differ - expected: '6.0000000', found: '0.0000000', error = '1.0000000'