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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#352957 | #4234. Tic Tac Toe Counting | PetroTarnavskyi# | WA | 0ms | 3632kb | C++20 | 2.6kb | 2024-03-13 18:58:14 | 2024-03-13 18:58:18 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define FOR(i, a, b) for(int i = (a); i < (b); i++)
#define RFOR(i, a, b) for(int i = (a) - 1; i >= (b); i--)
#define SZ(a) int(a.size())
#define ALL(a) a.begin(), a.end()
#define PB push_back
#define MP make_pair
#define F first
#define S second
typedef long long LL;
typedef vector<int> VI;
typedef pair<int, int> PII;
typedef double db;
const int N = 47;
struct Segtree
{
int n;
vector<multiset<PII>> t;
void init(int _n)
{
n = 1;
while (n < _n) n *= 2;
t.assign(2 * n - 1, multiset<PII>());
}
void upd(int v, int tl, int tr, int i, int y, int h)
{
t[v].insert({y, h});
if (tl + 1 == tr)
return;
int tm = (tl + tr) / 2;
if (i < tm)
upd(2 * v + 1, tl, tm, i, y, h);
else
upd(2 * v + 2, tm, tr, i, y, h);
}
void upd(int i, int y, int h)
{
upd(0, 0, n, i, y, h);
}
pair<bool, multiset<PII>> query(int v, int tl, int tr, int l, int r, int ly, int ry)
{
if (l <= tl && tr <= r)
{
auto it = t[v].lower_bound({ly, -1});
auto it2 = t[v].upper_bound({ry + 1, -1});
multiset<PII> s(it, it2);
if (SZ(s) > N)
return {true, multiset<PII>()};
return {false, s};
}
if (l >= tr || tl >= r)
return {false, multiset<PII>()};
int tm = (tl + tr) / 2;
auto r1 = query(v * 2 + 1, tl, tm, l, r, ly, ry);
auto r2 = query(v * 2 + 2, tm, tr, l, r, ly, ry);
if (r1.F || r2.F)
return {true, multiset<PII>()};
r1.S.insert(ALL(r2.S));
if (SZ(r1.S) > N)
return {true, multiset<PII>()};
return r1;
}
pair<bool, multiset<PII>> query(int l, int r, int ly, int ry)
{
return query(0, 0, n, l, r, ly, ry);
}
};
int main()
{
ios::sync_with_stdio(0);
cin.tie(0);
int n, q;
cin >> n >> q;
Segtree st;
st.init(n + 1);
vector<int> x;
vector<pair<int, PII>> v(n);
FOR (i, 0, n)
{
cin >> v[i].F >> v[i].S.F >> v[i].S.S;
x.PB(v[i].F);
}
sort(ALL(x));
x.resize(unique(ALL(x)) - x.begin());
FOR (i, 0, n)
{
int j = lower_bound(ALL(x), v[i].F) - x.begin();
st.upd(j, v[i].S.F, v[i].S.S);
}
FOR (it, 0, q)
{
int lx, ly, rx, ry;
cin >> lx >> ly >> rx >> ry;
int Lx = lower_bound(ALL(x), lx)- x.begin();
int Rx = upper_bound(ALL(x), rx)- x.begin();
auto res = st.query(Lx, Rx, ly, ry);
if (res.F)
cout << 1 << '\n';
else
{
VI a;
for (auto [y, len] : res.S)
a.PB(len);
sort(ALL(a));
bool ok = false;
FOR (i, 0, SZ(a) - 2)
{
if (a[i] + a[i + 1] > a[i + 2])
{
ok = true;
break;
}
}
cout << ok << '\n';
}
}
return 0;
}
詳細信息
Test #1:
score: 0
Wrong Answer
time: 0ms
memory: 3632kb
input:
4 XX..O.... X...OX... OOOX.X.X. OOOXXX...
output:
result:
wrong answer 1st lines differ - expected: '191 194', found: ''