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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#351754 | #6429. Let's Play Curling | PorNPtree# | AC ✓ | 333ms | 12352kb | C++17 | 1.1kb | 2024-03-12 14:22:44 | 2024-03-12 14:22:44 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 5;
int a[N], b[N];
map<int, int> M;
signed main()
{
int T;
scanf("%d", &T);
while (T--) {
int n, m;
scanf("%d%d", &n, &m);
for (int i = 1; i <= n; ++i) {
scanf("%d", &a[i]);
}
set<int> S;
for (int i = 1, x; i <= m; ++i) {
scanf("%d", &x);
S.insert(x);
}
M.clear();
for (int i = 1; i <= n; ++i) {
if (S.lower_bound(a[i]) != S.end() && *S.lower_bound(a[i]) == a[i]) {
continue;
}
int R = (S.lower_bound(a[i]) == S.end() ? 2.1e9 : (a[i] + *S.lower_bound(a[i])));
int L = (S.lower_bound(a[i]) == S.begin() ? -2.1e9 : (a[i] + *--S.lower_bound(a[i])));
++M[L];
--M[R];
}
int s = 0, res = 0;
for (auto [x, y] : M) {
s += y;
res = max(res, s);
}
if (!res) {
puts("Impossible");
} else {
printf("%d\n", res);
}
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3756kb
input:
3 2 2 2 3 1 4 6 5 2 5 3 7 1 7 3 4 3 1 10 1 1 7 7
output:
2 3 Impossible
result:
ok 3 lines
Test #2:
score: 0
Accepted
time: 333ms
memory: 12352kb
input:
5553 12 19 8 8 11 18 12 9 15 38 6 32 30 30 17 28 33 2 37 20 11 38 36 18 18 30 20 33 13 31 33 37 8 12 6 7 12 14 2 19 2 17 7 4 20 1 13 7 18 23 22 1 16 8 7 5 2 4 2 4 5 8 12 13 16 6 6 5 16 11 5 7 5 13 3 8 3 11 6 9 11 13 8 11 17 19 944782509 244117333 140979583 661724696 617847780 321687699 418677763 725...
output:
1 3 4 3 4 8 11 4 2 4 5 2 4 1 11 3 2 4 2 3 5 4 1 4 9 1 3 9 2 2 1 4 5 12 2 3 4 5 4 4 11 4 5 7 3 5 4 4 5 1 3 2 4 5 5 2 6 8 3 4 3 2 2 7 2 5 3 4 1 2 5 3 6 5 1 4 1 1 2 3 4 7 9 1 2 3 16 5 5 4 3 4 3 4 3 1 2 3 3 2 2 2 5 2 7 1 1 2 4 7 2 3 7 12 1 1 1 5 3 4 1 3 2 4 3 2 3 5 4 8 10 6 2 6 2 1 6 1 3 6 2 1 9 8 1 2 3...
result:
ok 5553 lines