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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#350630#4432. Jungle TrailstudentDLTL 0ms0kbC++143.3kb2024-03-10 22:12:132024-03-10 22:12:14

Judging History

你现在查看的是最新测评结果

  • [2024-03-10 22:12:14]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:0kb
  • [2024-03-10 22:12:13]
  • 提交

answer

#include<algorithm>
#include<cstdio>
#include<cstring>
#include<queue>
#define pii pair<int,int>
#define mk make_pair
#define ft first
#define se second
#define pb push_back
#define db double
#define ll long long
#define ull unsigned long long
#define INF 0x3f3f3f3f
#define inf 1e18
using namespace std;
#define LOCAL
namespace IO{
    #ifndef LOCAL
        #define SIZE 30000
        char in[SIZE],out[SIZE],*p1=in,*p2=in,*p3=out;
        #define getchar() (p1==p2&&(p2=(p1=in)+fread(in,1,SIZE,stdin),p1==p2)?EOF:*p1++)
        #define flush() (fwrite(p3=out,1,SIZE,stdout))
        #define putchar(ch) (p3==out+SIZE&&flush(),*p3++=(ch))
        class Flush{public:~Flush(){fwrite(out,1,p3-out,stdout);}}_;
    #endif
    template<typename type>
    inline void read(type &x){
        x=0;bool flag=0;char ch=getchar();
        while(ch<'0'||ch>'9') flag^=ch=='-',ch=getchar();
        while(ch>='0'&&ch<='9') x=(x<<1)+(x<<3)+(ch^48),ch=getchar();
        flag?x=-x:0;
    }
    template<typename type>
    inline void write(type x,char ch=0){
        x<0?x=-x,putchar('-'):0;static short Stack[50],top=0;
        do Stack[++top]=x%10,x/=10;while(x);
        while(top) putchar(Stack[top--]|48);
        if(ch) putchar(ch);
    }
}
using namespace IO;
#define M 2005
int n,m,d,dx[4]={0,0,-1,1},dy[4]={-1,1,0,0};
bool vis[M][M];
char mp[M][M],row[M],col[M],opr[M<<1];
bool check(){
    queue<pii> q;
    vis[1][1]=1,q.push(mk(1,1));
    while(!q.empty()){
        pii u=q.front();q.pop();
        for(int i=0;i<4;i++){
            int nx=u.ft+dx[i],ny=u.se+dy[i];
            if(nx>0&&nx<=n&&nx>0&&ny<=m&&!vis[nx][ny]){
                if(nx==n&&ny==m) return 1;
                vis[nx][ny]=1;q.push(mk(nx,ny));
            }
        }
    }
    return 0;
}
void flipRow(int rr){
    if(row[rr]=='N') row[rr]='T';
    else row[rr]='N';
    for(int i=1;i<=m;i++){
        if(mp[rr][i]=='O') mp[rr][i]='@';
        else if(mp[rr][i]=='@') mp[rr][i]='O';
    }
}
void flipCol(int cc){
    if(col[cc]=='N') col[cc]='T';
    else col[cc]='N';
    for(int i=1;i<=n;i++){
        if(mp[i][cc]=='O') mp[i][cc]='@';
        else if(mp[i][cc]=='@') mp[i][cc]='O';
    }
}
bool dfs(int x,int y){
    if(x==n&&y==m) return 1;
    if(x==n){
        if(mp[x][y+1]=='#') return 0;
        if(mp[x][y+1]=='@') flipCol(y+1);
        opr[++d]='P';
        return dfs(x,y+1);
    }
    if(y==m){
        if(mp[x+1][y]=='#') return 0;
        if(mp[x+1][y]=='@') flipRow(x+1);
        opr[++d]='D';
        return dfs(x+1,y);
    }
    if(mp[x][y+1]!='#'){
        if(mp[x][y+1]=='@') flipCol(y+1);
        opr[++d]='P';
        if(!dfs(x,y+1)) flipCol(y+1),d--;
        else return 1;
    }
    if(mp[x+1][y]!='#'){
        if(mp[x+1][y]=='@') flipRow(x+1);
        opr[++d]='D';
        if(!dfs(x+1,y)) flipRow(x+1),d--;
        else return 1;
    }
    return 0;
}
void solve(){
    read(n),read(m),d=0;
    for(int i=1;i<=n;i++) row[i]='N';
    for(int i=1;i<=m;i++) col[i]='N';
    for(int i=1;i<=n;i++){
        scanf("%s",mp[i]+1);
        for(int j=1;j<=m;j++) vis[i][j]=0;
    }
    if(!check()) puts("NIE");
    else{
        puts("TAK");
        dfs(1,1);
        printf("%s\n%s\n%s\n",row+1,col+1,opr+1);
    }
}
int main(){
    int T;read(T);
    while(T--) solve();
    return 0;
}

详细

Test #1:

score: 0
Time Limit Exceeded

input:

486
4 5
..#..
@@O@@
##@#O
..@.@
2 2
OO
OO
2 2
@@
@@
2 2
@@
#@
2 2
@O
#@
2 2
@@
OO
2 2
O#
@O
2 2
@#
#@
2 2
@.
.@
2 2
@#
.O
2 2
OO
.O
10 10
@O@O#O@@@#
OO#@#@@#OO
#@#@#O##O@
OO##@@O#@O
O##@@#@O#@
OO@OO@@@O@
@O#@#@O#@O
@OOOOO@##.
O@OOO##O@@
OO@@OOOO#@
10 10
@@#OOO#O@@
#@@OO@@.O@
#.O@@O#@@O
OO@@#O@#O@
.#...

output:

TAK
NTNT
NNTNN
PDPPPDD
TAK
NNNT
NNTNN
PDPPPDD
TAK
NNNT
NTTNN
PDPPPDD
TAK
NNNT
NTTNN
PDPPPDD
TAK
NTNT
NNTNN
PDPPPDD
TAK
NTNT
NTTNN
PDPPPDD
TAK
NTNT
NTTNN
DPPPPDD
TAK
NNNT
NNTNN
DPPPPDD
TAK
NTNT
NNTNN
PDPPPDD
TAK
NNNT
NNTNN
DPPPPDD
TAK
NNNT
NNTNN
PDPPPDD
TAK
NTNTNNNNNN
NTNTNNNNNN
DPDDDDD
TAK
NNTNNTTTT...

result: