QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#349526#8339. Rooted Treeucup-team2894#TL 182ms3952kbC++203.1kb2024-03-10 02:40:272024-03-10 02:40:27

Judging History

你现在查看的是最新测评结果

  • [2024-03-10 02:40:27]
  • 评测
  • 测评结果:TL
  • 用时:182ms
  • 内存:3952kb
  • [2024-03-10 02:40:27]
  • 提交

answer

#include <bits/stdc++.h>
#define fr first
#define sc second
#define all(a) (a).begin(), (a).end()
#define unique(a) a.resize(unique(a.begin(), a.end()) - a.begin())

using namespace std;

#ifdef ONPC
mt19937 rnd(223);
#else
mt19937 rnd(chrono::high_resolution_clock::now()
			.time_since_epoch().count());
#endif

#define TIME (clock() * 1.0 / CLOCKS_PER_SEC)

using ll = long long;
using ld = double;

const int maxn = 1e5 + 100, inf = 1e9 + 100;

// если модуль подается на вход, убрать все <> и раскомментировать нужные строки
using uint = unsigned int;
using ull = unsigned long long;
template <uint MD> struct ModInt {
    using M = ModInt;
    // static int MD;
    uint v;
    ModInt(ll _v = 0) { set_v(uint(_v % MD + MD)); }
    M& set_v(uint _v) {
        v = (_v < MD) ? _v : _v - MD;
        return *this;
    }
    explicit operator bool() const { return v != 0; }
    M operator-() const { return M() - *this; }
    M operator+(const M& r) const { return M().set_v(v + r.v); }
    M operator-(const M& r) const { return M().set_v(v + MD - r.v); }
    M operator*(const M& r) const { return M().set_v(uint((ull)v * r.v % MD)); }
    M operator/(const M& r) const { return *this * r.inv(); }
    M& operator+=(const M& r) { return *this = *this + r; }
    M& operator-=(const M& r) { return *this = *this - r; }
    M& operator*=(const M& r) { return *this = *this * r; }
    M& operator/=(const M& r) { return *this = *this / r; }
    bool operator==(const M& r) const { return v == r.v; }
    bool operator!=(const M& r) const { return v != r.v; }
    M inv() const;
    friend istream& operator>>(istream& is, M& r) { ll x; is >> x; r = M(x); return is; }
    friend ostream& operator<<(ostream& os, const M& r) { return os << r.v; }
};

template<uint MD>
ModInt<MD> pow(ModInt<MD> x, ll n) {
    ModInt<MD> r = 1;
    while (n) {
        if (n & 1) r *= x;
        x *= x;
        n >>= 1;
    }
    return r;
}

template<uint MD>
ModInt<MD> ModInt<MD>::inv() const { return pow(*this, MD - 2); }
// or copy egcd and {return egcd(MD, v, 1).second;}

// if MD is from input
// this line is necessary, read later as you wish
// int ModInt::MD;

using Mint = ModInt<int(1e9 + 9)>;
// using Mint = double;

//fail for b = 1
typedef unsigned long long ul; typedef __uint128_t L;
namespace MF {
    int b;
    ul m;

    void init(int b_) {
        b = b_;
        m = (ul((L(1) << 64) / b));
    }

    int reduce(ul a) {
        ul q = (ul)((L(m)*a)>>64);
        int r = a-q*b;
        return r>=b?r-b:r;
    }
};


void solve() {
    int m, k;
    cin >> m >> k;
    Mint s = 0, l = 0, c = 1;
    for (int i = 0; i < k; i++) {
        s = s + (l / c + 1) * m;
        l = l + (l / c + 1) * m - l /c;
        c = c + m - 1;
    }
    cout << s << '\n';
}

int main() {
#ifdef ONPC
    freopen("../a.in", "r", stdin);
//    freopen("../a.out", "w", stdout);
#endif
    ios::sync_with_stdio(0);
    cin.tie(0);
    cout << fixed;
    cout.precision(20);
    solve();
    cerr << "\n\nConsumed " << TIME << endl;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3920kb

input:

6 2

output:

18

result:

ok 1 number(s): "18"

Test #2:

score: 0
Accepted
time: 1ms
memory: 3952kb

input:

2 6

output:

600000038

result:

ok 1 number(s): "600000038"

Test #3:

score: 0
Accepted
time: 182ms
memory: 3884kb

input:

83 613210

output:

424200026

result:

ok 1 number(s): "424200026"

Test #4:

score: -100
Time Limit Exceeded

input:

48 6713156

output:


result: