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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#345250 | #3420. Jingle Balls | PetroTarnavskyi# | AC ✓ | 33ms | 20192kb | C++20 | 1.6kb | 2024-03-06 17:53:35 | 2024-03-06 17:53:35 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define FOR(i, a, b) for(int i = (a); i < (b); i++)
#define RFOR(i, a, b) for(int i = (a) - 1; i >= (b); i--)
#define SZ(a) int(a.size())
#define ALL(a) a.begin(), a.end()
#define PB push_back
#define MP make_pair
#define F first
#define S second
typedef long long LL;
typedef vector<int> VI;
typedef pair<int, int> PII;
typedef double db;
const int N = 1 << 11;
template<typename T>
void updMin(T& a, T b)
{
a = min(a, b);
}
string s;
VI g[N];
int ball[N];
int dp[N][N];
int totBalls;
int sz[N];
void dfs(int v)
{
if (g[v].empty())
{
sz[v] = 1;
FOR(i, 0, 2)
{
dp[v][i] = max(0, i - ball[v]);
}
return;
}
assert(SZ(g[v]) == 2);
int u1 = g[v][0], u2 = g[v][1];
dfs(u1);
dfs(u2);
sz[v] = sz[u1] + sz[u2];
FOR(k, 0, sz[v] + 1)
{
FOR(k1, k / 2, (k + 1) / 2 + 1)
{
int k2 = k - k1;
updMin(dp[v][k], dp[u1][k1] + dp[u2][k2]);
}
}
}
void solve()
{
int n = min(N, SZ(s));
FOR(i, 0, n)
{
g[i].clear();
ball[i] = 0;
sz[i] = 0;
}
totBalls = 0;
stack<int> st;
int v = 0;
for (char c : s)
{
if (c == '(')
{
if (!st.empty())
g[st.top()].PB(v);
st.push(v);
v++;
}
else if (c == ')')
{
st.pop();
}
else
{
assert(c == 'B');
ball[st.top()] = 1;
totBalls++;
}
}
FOR(i, 0, n)
FOR(j, 0, n)
dp[i][j] = N;
dfs(0);
if (dp[0][totBalls] == N)
cout << "impossible\n";
else
cout << dp[0][totBalls] << "\n";
}
int main()
{
ios::sync_with_stdio(0);
cin.tie(0);
while (cin >> s)
solve();
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3904kb
input:
((B)()) ((((B)(B))((B)()))(B)) (()(((B)(B))(B)))
output:
0 impossible 1
result:
ok 3 lines
Test #2:
score: 0
Accepted
time: 33ms
memory: 20192kb
input:
(()()) (()(B)) ((B)(B)) (((B)(B))(B)) (()((B)(B))) ((()((B)(B)))(B)) ((()())((B)(B))) (((B)((B)(B)))(B)) (()(((B)((B)(B)))())) (((B)(B))(()((B)(B)))) ((B)(((B)((B)()))(B))) ((((((B)(B))(()(((B)(B))())))(((B)((B)(B)))((()())(()()))))((((()(B))((B)()))(((((B)(B))((B)(()(B))))())(B)))((((B)())())((B)(B...
output:
0 0 0 0 1 1 1 impossible 2 1 impossible 6 56 2 1 impossible 2 2 2 0 1 1 impossible 0 2 impossible 2 1 impossible 25 18 11 0 8 1 impossible 6 7 impossible 2 1 impossible 250 231 222 0 8 1 impossible 15 20 impossible 2 1 impossible 6 3 2 0 8 1 impossible 2 1 impossible 2 1 impossible 62 53 54 0 8 1 im...
result:
ok 78 lines