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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#345093 | #7954. Special Numbers | juancs | WA | 0ms | 3880kb | C++14 | 4.0kb | 2024-03-06 05:53:52 | 2024-03-06 05:53:52 |
Judging History
answer
#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#define el '\n'
#define pb push_back
#define forn(i, n) for(int i = 0; i < (int)n; ++i)
#define for1(i, n) for(int i = 1; i <= (int)n; ++i)
#define fore(i,l,r ) for(int i = l; i<= r; ++i)
#define ford(i, n) for(int i = (int)n - 1; i >= 0; --i)
#define sz(a) (int) a.size()
#define fi first
#define se second
#define d(x) cerr << #x << ' ' << x << el
#define all(x) x.begin(), x.end()
using namespace std;
using namespace __gnu_pbds;
typedef pair<int, int> ii;
typedef long long ll;
typedef vector<int> vi;
typedef __int128_t i128;
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;
typedef array<ll, 7> a7;
const int mod = 1e9 + 7;
struct mint{
ll x;
mint(): x(0){}
mint(int x): x(x){}
mint operator+(mint b){
int ans = x + b.x;
if(ans >= mod)ans -= mod;
return mint(ans);
}
mint operator-(mint b){
int ans = x - b.x;
if(ans < 0)ans += mod;
return mint(ans);
}
mint operator*(mint b){
return 1LL*x*b.x%mod;
}
};
ll cnts[4];
ll trans[10][4];
map<a7, mint> dp;
string l, r, cr;
mint go(a7 st){
if(st[0] == sz(cr)){
if(st[2] == 1)return 0;
forn(i, 4){
if(st[i + 3] != cnts[i])return 0;
}
return 1;
}
if(dp.count(st))return dp[st];
mint& ans = dp[st];
ans = 0;
ll e = !st[1] ? 9 : cr[st[0]] - '0';
if(st[2]){
a7 cur = st;
++cur[0];
cur[1] = false;
ans = ans + go(cur);
}
for1(i, e){
a7 cur = st;
++cur[0];
cur[1] = st[1] && i == e;
cur[2] = false;
forn(j, 4){
cur[j + 3] += trans[i][j];
cur[j + 3] = min(cur[j + 3], cnts[j]);
}
ans = ans + go(cur);
}
return ans;
}
mint binpow(mint b, ll e){
mint ans = 1;
for(; e; b = b * b, e /= 2){
if(e&1)ans = ans * b;
}
return ans;
}
mint inv(mint x){
return binpow(x, mod - 2);
}
mint cnt(){
mint ans = 0;
mint iten = inv(10);
mint inine = inv(9);
forn(i, sz(cr)){
mint pt = binpow(10, sz(cr) - i - 1);
mint pn = binpow(9, sz(cr) - i - 1);
if(i != 0){
ans = ans + (mint(9)*(pt - pn));
pt = pt * iten;
pn = pn * inine;
continue;
}
fore(j, i, sz(cr) - 1){
if(cr[j] == '0'){
if(cr[i] == '0')break;
mint num = 0;
fore(k, j + 1, sz(cr) - 1){
num = num + (pt*mint(cr[k] - '0'));
pt = pt * iten;
}
ans = ans + num + 1;
break;
}
mint dj = cr[j] - '1';
ans = ans + (dj*(pt - pn));
pt = pt * iten;
pn = pn * inine;
}
}
return ans;
}
int main(){
ios_base::sync_with_stdio(0);
cin.tie(NULL);
ll k;
cin >> k >> l >> r;
vector<ll> primes = {2, 3, 5, 7};
ll tk = k;
forn(i, 4){
ll& p = primes[i];
while(tk % p == 0){
++cnts[i];
tk /=p;
}
}
if(tk != 1){
cout << 0 << el;
return 0;
}
for1(i, 9){
int ti = i;
forn(j, 4){
ll& p = primes[j];
while(ti % p == 0){
trans[i][j]++;
ti /= p;
}
}
}
cr = r;
a7 st = {0, 1, 1, 0, 0, 0, 0};
mint rans = go(st);
rans = rans + cnt();
dp.clear();
cr = l;
// cout << "####" << el;
mint lans = go(st);
lans = lans + cnt();
// d(rans.x);
// d(lans.x);
i128 cl = 1;
ford(i, sz(l)){
char& c = l[i];
cl *= (c - '0');
}
// d(ll(cl));
mint ans = rans - (lans - mint(cl % k == 0));
cout << ans.x << el;
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 3588kb
input:
5 1 20
output:
4
result:
ok single line: '4'
Test #2:
score: 0
Accepted
time: 0ms
memory: 3616kb
input:
5 50 100
output:
19
result:
ok single line: '19'
Test #3:
score: 0
Accepted
time: 0ms
memory: 3880kb
input:
15 11 19
output:
0
result:
ok single line: '0'
Test #4:
score: 0
Accepted
time: 0ms
memory: 3512kb
input:
1 100 100000
output:
99901
result:
ok single line: '99901'
Test #5:
score: 0
Accepted
time: 0ms
memory: 3880kb
input:
1 1 1
output:
1
result:
ok single line: '1'
Test #6:
score: -100
Wrong Answer
time: 0ms
memory: 3652kb
input:
10 800 43021
output:
22759
result:
wrong answer 1st lines differ - expected: '23570', found: '22759'