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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#344572#4793. QnpKevin5307TL 7ms44624kbC++201.2kb2024-03-04 19:55:022024-03-04 19:55:03

Judging History

你现在查看的是最新测评结果

  • [2024-03-04 19:55:03]
  • 评测
  • 测评结果:TL
  • 用时:7ms
  • 内存:44624kb
  • [2024-03-04 19:55:02]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
#define sz(v) (int)((v).size())
using ll=long long;
using i128=__int128_t;
const ll thres=1e12+10;
vector<ll> vC[70007];
ll C(int n,int k)
{
	k=min(k,n-k);
	return k>=sz(vC[n])?thres:vC[n][k];
}
ll mul(ll a,ll b)
{
	return min((i128)(thres),(i128)(a)*b);
}
int main()
{
	ios::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);
	for(int i=0;i<70007;i++)
	{
		vC[i].resize(min(70,i+1));
		vC[i][0]=1;
		for(int j=1;j<sz(vC[i]);j++)
			if(j==i)
				vC[i][j]=1;
			else
				vC[i][j]=min(thres,vC[i-1][j]+vC[i-1][j-1]);
	}
	int q;
	cin>>q;
	while(q--)
	{
		static int c[12];
		for(int i=0;i<10;i++)
			cin>>c[i];
		ll k;
		cin>>k;
		const ll mod=1e9+7;
		ll ans=0;
		while(true)
		{
			int sum=accumulate(c,c+10,0);
			if(!sum) break;
			int cur=0;
			while(cur<10)
			{
				if(!c[cur])
				{
					cur++;
					continue;
				}
				ll ways=1;
				c[cur]--;
				int tmp=sum-1;
				for(int i=0;i<10;i++)
				{
					ways=mul(ways,C(tmp,c[i]));
					tmp-=c[i];
				}
				c[cur]++;
				if(ways<k)
				{
					k-=ways;
					cur++;
				}
				else break;
			}
			ans=(ans*10+cur)%mod;
			c[cur]--;
		}
		cout<<ans<<'\n';
	}
	return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 7ms
memory: 44624kb

input:

6
1 1 0 0 0 0 0 0 0 0 1
1 1 0 0 0 0 0 0 0 0 2
1 1 1 0 0 0 0 0 0 0 1
1 1 1 0 0 0 0 0 0 0 2
1 1 1 0 0 0 0 0 0 0 5
1 2 0 0 0 0 0 0 0 0 2

output:

1
10
12
21
201
101

result:

ok 6 numbers

Test #2:

score: -100
Time Limit Exceeded

input:

5000
7142 6835 7022 6981 6929 7008 7038 7015 6885 7145 659213485437
7015 7033 6963 7136 7053 7072 6847 6923 6953 7005 82053183749
7013 7003 6969 7000 7011 7137 7030 6823 7021 6993 817812793310
6893 7008 6963 7086 7012 6922 7128 7094 7028 6866 143084249211
7020 7021 6997 6961 7017 7032 7013 7028 6987...

output:


result: