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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#341678#906. 强连通分量MiniLong#WA 3ms52472kbC++143.1kb2024-02-29 20:30:112024-02-29 20:30:12

Judging History

你现在查看的是最新测评结果

  • [2024-02-29 20:30:12]
  • 评测
  • 测评结果:WA
  • 用时:3ms
  • 内存:52472kb
  • [2024-02-29 20:30:11]
  • 提交

answer

#include <bits/stdc++.h>
#define _rep(i, x, y) for(int i = x; i <= y; ++i)
#define _req(i, x, y) for(int i = x; i >= y; --i)
#define _rev(i, u) for(int i = head[u]; i; i = e[i].nxt)
#define pb push_back
#define fi first
#define se second
#define mst(f, i) memset(f, i, sizeof f)
using namespace std;
#ifdef ONLINE_JUDGE
#define debug(...) 0
#else
#define debug(...) fprintf(stderr, __VA_ARGS__), fflush(stderr)
#endif
typedef long long ll;
typedef pair<int, int> PII;
namespace fastio{
    char ibuf[50007],*p1 = ibuf, *p2 = ibuf;
    #ifdef ONLINE_JUDGE
    #define get() p1 == p2 && (p2 = (p1 = ibuf) + fread(ibuf, 1, 50007, stdin), p1 == p2) ? EOF : *p1++
    #else
    #define get() getchar()
    #endif
    template<typename T> inline void read(T &t){
        T x = 0, f = 1;
        char c = getchar();
        while(!isdigit(c)){
            if(c == '-') f = -f;
            c = getchar();
        }
        while(isdigit(c)) x = x * 10 + c - '0', c = getchar();
        t = x * f;
    }
    template<typename T, typename ... Args> inline void read(T &t, Args&... args){
        read(t);
        read(args...);
    }
    template<typename T> void write(T t){
        if(t < 0) putchar('-'), t = -t;
        if(t >= 10) write(t / 10);
        putchar(t % 10 + '0');
    }
    template<typename T, typename ... Args> void write(T t, Args... args){
        write(t), putchar(' '), write(args...);
    }
    template<typename T> void writeln(T t){
        write(t);
        puts("");
    }
    template<typename T> void writes(T t){
        write(t), putchar(' ');
    }
    #undef get
};
using namespace fastio;
#define multitest() int T; read(T); _rep(tCase, 1, T)
namespace Calculation{
    const ll mod = 998244353;
    ll ksm(ll p, ll h){ll base = p % mod, res = 1; while(h){if(h & 1ll) res = res * base % mod; base = base * base % mod, h >>= 1ll;} return res;}
    void dec(ll &x, ll y){x = ((x - y) % mod + mod) % mod;}
    void add(ll &x, ll y){x = (x + y) % mod;}
    void mul(ll &x, ll y){x = x * y % mod;}
    ll sub(ll x, ll y){return ((x - y) % mod + mod) % mod;}
    ll pls(ll x, ll y){return ((x + y) % mod + mod) % mod;}
    ll mult(ll x, ll y){return x * y % mod;}
}
using namespace Calculation;
const int N = 1e6 + 5;
int n, m, num;
vector<int> G[N];
int id, dfn[N], low[N];
int top, st[N];
bool vis[N];
vector<int> v[N];
void tarjan(int u){
    dfn[u] = low[u] = ++id, st[++top] = u, vis[u] = 1;
    for(auto &v : G[u]){
        if(!dfn[v]){
            tarjan(v);
            low[u] = min(low[u], low[v]);
        }else if(vis[v]) low[u] = min(low[u], dfn[v]);
    }
    if(low[u] == dfn[u]){
        num++;
        for(int x = -1; x != u; top--){
            x = st[top];
            v[num].pb(x), vis[x] = 0;
        }
    }
}
int main(){
    read(n, m);
    _rep(i, 1, m){
        int u, v; read(u, v);
        G[u].pb(v);
    }
    _rep(i, 0, n - 1) if(!dfn[i]) tarjan(i);
    writeln(num);
    _rep(i, 1, num){
        writes(v[i].size());
        for(auto &j : v[i]) writes(j);
        puts("");
    }
    return 0;
}

详细

Test #1:

score: 0
Wrong Answer
time: 3ms
memory: 52472kb

input:

6 7
1 4
5 2
3 0
5 5
4 1
0 3
4 2

output:

4
2 3 0 
1 2 
2 4 1 
1 5 

result:

wrong answer 5 is later than 2, but there is an edge (5, 2)