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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#34110#1964. Stock Price Predictionwater233#Compile Error//C++3.0kb2022-06-05 16:46:252022-06-05 16:46:27

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2022-06-05 16:46:27]
  • 评测
  • [2022-06-05 16:46:25]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
constexpr int maxn = 2e4 + 5, mod = 998244353, B = 1307;
mt19937 hua(512);
inline int add(int a, int b) {return (a += b) >= mod ? a - mod : a;}
inline int mul(int a, int b) {return 1ll * a * b % mod;}
inline int fpw(int a, int b) {
	int ans = 1;
	for(; b; b >>= 1, a = mul(a, a)) if(b & 1) ans = mul(ans, a);
	return ans;a
}
int pwr[maxn], prepwr[maxn];
struct Fhq {
	int rnd[maxn], ls[maxn], rs[maxn], sz[maxn], tag[maxn];
	int val[maxn], pos[maxn], sum[maxn], rt;
	vector<int> rollback;
	int cnt;
	Fhq() {	cnt = rt = 0;}
	int newnode(int x, int k) {
		int u;
		if(rollback.size()) u = rollback.back(), rollback.pop_back();
		else u = ++ cnt;
		val[u] = x, pos[u] = k, rnd[u] = hua() % mod, ls[u] = rs[u] = 0;
		sum[u] = k, tag[u] = 0, sz[u] = 1;
		return u;
	}
	void up(int u) {
		sz[u] = sz[ls[u]] + sz[rs[u]] + 1;
		sum[u] = add(sum[ls[u]], add(mul(pwr[sz[ls[u]]], pos[u]), mul(pwr[sz[ls[u]] + 1], sum[rs[u]])));
	}
	void seta(int u, int k) {
		pos[u] -= k, tag[u] += k, sum[u] = add(sum[u], mod - mul(k, prepwr[sz[u] - 1]));
	}
	void dw(int u) {
		if(tag[u]) {
			seta(ls[u], tag[u]);
			seta(rs[u], tag[u]);
			tag[u] = 0;
		}
	}
	void split(int u, int &x, int &y, int k, int p) {
		if(!u) return x = y = 0, void();
		dw(u);
		if(val[u] < k || val[u] == k && pos[u] <= p) x = u, split(rs[u], rs[x], y, k, p);
		else y = u, split(ls[u], x, ls[y], k, p);
		up(u); 
	}
	int merge(int u, int v) {
		if(!u || !v) return u + v;
		dw(u), dw(v);
		if(rnd[u] < rnd[v]) {
			rs[u] = merge(rs[u], v), up(u);
			return u;
		}
		else {
			ls[v] = merge(u, ls[v]), up(v);
			return v;
		}
	}
	void ins(int x, int k) {
		int A, B;
		split(rt, A, B, x, k);
		rt = merge(A, merge(newnode(x, k), B));
	}
	void del(int x, int k) {
		int A, B, C;
		split(rt, A, B, x - 1, k);
		split(B, B, C, x, k);
		rollback.emplace_back(B);
		rt = merge(A, C);
	}
	int qry() {
		return sum[rt];
	}
	void dfs(int u) {
		if(!u) return;
		dw(u);
		dfs(ls[u]), cout << u << ' '  << val[u] << ' ' << pos[u] << ' ' << sz[u] << ' ' << sum[u] << '\n', dfs(rs[u]);
		up(u);
	}
};
void init() {
	pwr[0] = prepwr[0] = 1;
	for(int i = 1; i < maxn; i ++) pwr[i] = mul(pwr[i - 1], B), prepwr[i] = add(prepwr[i - 1], pwr[i]);
}
int main() {
//	freopen("in.txt", "r", stdin);
	ios::sync_with_stdio(false);
	cin.tie(0), cout.tie(0);
	init();
	int n, m;
	Fhq t1, t2;
	cin >> m >> n;
	vector<int> a(m), b(n);
	for(int i = 0; i < m; i ++) cin >> a[i];
	for(int i = 0; i < n; i ++) cin >> b[i];
	for(int i = 0; i < m; i ++) {
		// cout << a[i] << ' ' << i << '\n';
		t1.ins(a[i], i + 1);
		// cout << "------------\n";
		// t1.dfs(t1.rt);
	}
	int ret = t1.qry();
	for(int i = 0; i < m - 1; i ++) {
		t2.ins(b[i], i + 1);
	}
	int flag = 0;
	for(int i = m - 1; i < n; i ++) {
		t2.ins(b[i], m);
		// cout << t2.qry() << " ------------\n";
		// t2.dfs(t2.rt);
		if(t2.qry() == ret) cout << i - m + 2 << ' ', flag = 1;
		t2.del(b[i - m + 1], 1);
		t2.seta(t2.rt, 1);
	}
	if(!flag) cout << 0 << '\n';
	return 0;
}

详细

answer.code: In function ‘int fpw(int, int)’:
answer.code:10:21: error: expected ‘;’ before ‘}’ token
   10 |         return ans;a
      |                     ^
      |                     ;
   11 | }
      | ~