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QOJ
| ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
|---|---|---|---|---|---|---|---|---|---|
| #340716 | #7782. Ursa Minor | goodier | RE | 0ms | 16108kb | C++17 | 6.1kb | 2024-02-29 11:30:17 | 2024-02-29 11:30:17 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 2e5 + 10, B = 450, T = 450;
const ll MOD = 998244353, base = 34261314;
int f[N][19], len[N], a[N], b[N], ba[N], n, m, q, ans[N], L[N], R[N], pos[N], t;
ll pw[N], spw[N], inv[N], s[N][2][2];
ll power(ll a, ll b)
{
ll c = 1;
while(b)
{
if(b & 1) c = c * a % MOD;
a = a * a % MOD;
b >>= 1;
}
return c;
}
struct Op{
int op, l, r, x, y, k;
}qr[N];
int read()
{
int x = 0, t = 1; char ch = getchar();
while(ch < '0' || ch > '9')
{
if(ch == '-') t = -1;
ch = getchar();
}
while(ch >= '0' && ch <= '9')
{
x = x * 10 + ch - '0';
ch = getchar();
}
return x * t;
}
void write1()
{
putchar('Y'), putchar('e'), putchar('s'), putchar('\n');
}
void write0()
{
putchar('N'), putchar('o'), putchar('\n');
}
int gcd(int a, int b)
{
while(b)
{
int c = a;
a = b, b = c % b;
}
return a;
}
int query(int l, int r)
{
int t = len[r - l + 1];
return gcd(f[l][t], f[r - (1 << t) + 1][t]);
}
void init()
{
for(int i = 2; i <= m; i++) len[i] = len[i >> 1] + 1;
for(int i = 1; i <= m; i++) f[i][0] = b[i];
for(int j = 1; j <= len[m]; j++)
{
for(int i = 1; i + (1 << j) - 1 <= m; i++)
{
f[i][j] = gcd(f[i][j - 1], f[i + (1 << (j - 1))][j - 1]);
}
}
pw[0] = 1; for(int i = 1; i <= n; i++) pw[i] = pw[i - 1] * (ll)base % MOD; spw[0] = 1; for(int i = 1; i <= n; i++) spw[i] = (spw[i - 1] + pw[i]) % MOD;
for(int i = 0; i <= n; i++) inv[i] = power(pw[i], MOD - 2);
t = n / B;
for(int i = 1; i <= t; i++)
{
L[i] = R[i - 1] + 1, R[i] = i * B;
for(int j = L[i]; j <= R[i]; j++) pos[j] = i;
}
if(R[t] < n)
{
t++;
L[t] = R[t - 1] + 1, R[t] = n;
for(int j = L[t]; j <= R[t]; j++) pos[j] = t;
}
}
void add1(int x, ll y, int c)
{
if(y < 0) y += MOD;
s[x][0][c] += y, s[pos[x]][1][c] += y;
if(s[x][0][c] >= MOD) s[x][0][c] -= MOD;
if(s[x][1][c] >= MOD) s[x][1][c] -= MOD;
}
void add2(int x, ll y, int c)
{
for(int i = x; i <= R[pos[x]]; i++)
{
s[i][0][c] += y;
if(s[i][0][c] >= MOD) s[i][1][c] -= MOD;
}
for(int i = pos[x]; i <= t; i++)
{
s[i][1][c] += y;
if(s[i][1][c] >= MOD) s[i][1][c] -= MOD;
}
}
ll ask2(int x, int c)
{
if(x == 0) return 0;
ll res = s[x][0][c] + s[pos[x] - 1][1][c];
if(res >= MOD) res -= MOD;
return res;
}
ll ask1(int x, int c)
{
if(x == 0) return 0;
ll res = 0;
for(int i = 1; i < pos[x]; i++)
{
res += s[i][1][c];
if(res >= MOD) res -= MOD;
}
for(int i = L[pos[x]]; i <= x; i++)
{
res += s[i][0][c];
if(res >= MOD) res -= MOD;
}
return res;
}
ll query1(int l, int r, int c)
{
return (ask1(r, c) - ask1(l - 1, c) + MOD) % MOD;
}
ll query2(int l, int r, int c)
{
ll res = ask2(r, c) - ask2(l - 1, c) + MOD;
if(res >= MOD) res -= MOD;
return res;
}
void solve1()
{
for(int k = 1; k <= T; k++)
{
for(int i = 1; i <= n; i++)
{
a[i] = ba[i]; s[i][0][0] = s[i][0][1] = s[i][1][0] = s[i][1][1] = 0;
}
for(int i = 1; i <= n; i++)
{
if(i % k == 0) add1(i, a[i], 0);
add1(i, (ll)a[i] * pw[i % k] % MOD, 1);
}
for(int i = 1; i <= q; i++)
{
if(qr[i].op == 1)
{
int x = qr[i].x, dt = qr[i].y - a[x];
if(x % k == 0) add1(x, dt, 0);
add1(x, (ll)dt * pw[x % k] % MOD, 1);
a[x] += dt;
}
else if(qr[i].k == k)
{
int l = qr[i].l, r = qr[i].r;
ans[i] = (query1(l, r, 0) * spw[k - 1] % MOD) == query1(l, r, 1);
}
}
}
}
void solve2()
{
for(int i = 1; i <= n; i++)
{
a[i] = ba[i]; s[i][0][0] = s[i][0][1] = s[i][1][0] = s[i][1][1] = 0;
}
for(int i = 1; i <= n; i++)
{
add2(i, (ll)a[i] * pw[i] % MOD, 0);
}
for(int i = 1; i <= q; i++)
{
if(qr[i].op == 1)
{
int x = qr[i].x, dt = qr[i].y - a[x];
add2(x, (ll)dt * pw[x], 0);
a[x] += dt;
}
else if(qr[i].k > T)
{
int k = qr[i].k, l = qr[i].l, r = qr[i].r;
ll res = 0;
for(int j = 1; j <= n; j += k)
{
int ll = j, rr = min(j + k - 1, n);
int LL = max(l, ll), RR = min(r, rr);
if(LL <= RR)
{
res += query2(LL, RR, 0) * inv[j] % MOD;
if(res >= MOD) res -= MOD;
}
}
ll s0 = 0;
for(int j = k; j <= n; j += k)
{
if(l <= j && j <= r)
{
s0 += a[j];
if(s0 >= MOD) s0 -= MOD;
}
}
ans[i] = (s0 * spw[k - 1] % MOD) == res;
}
}
}
int main()
{
//freopen("data.in", "r", stdin);
n = read(), m = read(), q = read();
for(int i = 1; i <= n; i++) ba[i] = a[i] = read();
for(int i = 1; i <= m; i++) b[i] = read();
init();
for(int i = 1; i <= q; i++)
{
char str[2]; scanf("%s", str);
if(str[0] == 'Q')
{
int l = read(), r = read(), x = read(), y = read();
qr[i] = Op({0, l, r, x, y, gcd(r - l + 1, query(x, y))});
}
else
{
int x = read(), y = read();
qr[i] = Op({1, 0, 0, x, y});
}
}
solve1();
solve2();
int cnt = 0;
for(int i = 1; i <= q; i++)
{
if(qr[i].op == 0)
{
cnt++;
if(cnt == 480) exit(qr[i].k <= T);
if(ans[i]) write1();
else write0();
}
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 16108kb
input:
6 4 5 1 1 4 5 1 4 3 3 2 4 Q 1 5 1 2 Q 2 5 3 4 U 5 2 Q 1 6 1 2 Q 2 5 3 4
output:
Yes No No Yes
result:
ok 4 tokens
Test #2:
score: 0
Accepted
time: 0ms
memory: 16040kb
input:
1 1 1 0 1 Q 1 1 1 1
output:
Yes
result:
ok "Yes"
Test #3:
score: -100
Runtime Error
input:
2000 2000 200000 1 1 2 0 0 2 0 2 0 0 0 0 0 2 2 1 2 0 0 2 2 2 1 0 1 2 1 2 0 0 1 1 1 2 0 0 2 2 2 2 0 2 0 0 2 1 2 0 0 1 2 2 1 0 2 0 0 0 1 2 2 1 2 2 0 0 1 1 1 0 0 2 0 0 1 1 0 2 2 2 1 0 0 1 0 1 2 2 2 1 1 2 2 1 2 1 0 2 2 3 1 3 2 3 1 0 1 2 0 1 1 1 0 2 2 3 2 0 3 2 3 3 1 2 3 1 2 0 1 0 3 1 0 0 2 0 1 2 1 3 2 2...
output:
Yes Yes No Yes Yes No No No Yes Yes Yes Yes Yes Yes Yes No Yes Yes Yes Yes Yes Yes Yes No Yes Yes Yes No Yes Yes No No No No No Yes No No No Yes Yes No Yes No Yes Yes Yes Yes Yes Yes Yes Yes Yes No Yes Yes No Yes Yes Yes No No Yes No Yes No No No Yes Yes Yes Yes Yes Yes Yes Yes Yes No Yes Yes Yes No...