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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#340631 | #996. 割点 | FISHER_# | WA | 3ms | 5620kb | C++14 | 750b | 2024-02-29 10:51:48 | 2024-02-29 10:51:49 |
Judging History
answer
#include <bits/stdc++.h>
#define PB push_back
#define EB emplace_back
using namespace std;
const int maxn = 20000;
vector<int> g[maxn + 5];
vector<int> out;
int dfn[maxn + 5], low[maxn + 5], stamp;
void tarjan(int u, int fa) {
dfn[u] = low[u] = ++stamp;
for (int v : g[u])
if (v != fa) {
if (!dfn[v]) {
tarjan(v, u);
low[u] = min(low[u], low[v]);
} else low[u] = min(low[u], dfn[v]);
}
if (low[u] == dfn[u]) out.PB(u);
}
int main() {
int n, m;
scanf("%d%d", &n, &m);
for (int i = 1; i <= m; i++) {
int u, v;
scanf("%d%d", &u, &v);
g[u].PB(v), g[v].PB(u);
}
for (int i = 1; i <= n; i++)
if (!dfn[i]) tarjan(i, 0);
sort(out.begin(), out.end());
for (int x : out) printf("%d\n", x);
}
詳細信息
Test #1:
score: 0
Wrong Answer
time: 3ms
memory: 5620kb
input:
12783 21968 4933 7832 8238 2739 3628 7841 9169 6390 7850 8797 8120 8710 5306 9807 10166 2063 2666 5157 5015 4651 4790 12586 10366 7137 12440 7218 6330 3670 2735 8492 1968 2750 6237 1112 6578 9221 743 3820 7155 4583 2537 9747 11331 9916 4454 5631 2978 10340 5293 1803 4944 4296 11800 2742 7903 2018 10...
output:
1 9 14 23 24 27 28 29 30 33 36 38 39 56 82 93 109 111 112 116 119 120 123 124 129 131 136 142 147 151 154 155 160 166 175 181 183 185 197 201 207 239 265 270 289 293 295 302 313 316 318 319 328 336 347 358 371 373 378 383 387 389 393 400 419 424 440 451 453 471 485 489 494 500 502 511 520 526 530 53...
result:
wrong answer 1st numbers differ - expected: '1440', found: '1'