QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#340599#4437. Link with RunningTerac#TL 0ms0kbC++142.6kb2024-02-29 10:37:292024-02-29 10:37:30

Judging History

你现在查看的是最新测评结果

  • [2024-02-29 10:37:30]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:0kb
  • [2024-02-29 10:37:29]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
#define int long long
namespace IO {
	#if ONLINE_JUDGE
	#define getc() (IS == IT && (IT = (IS = ibuf) + fread(ibuf, 1, IL, stdin), IS == IT) ? EOF : *IS++)
	#else
	#define getc() getchar()
	#endif
	const int IL = 1 << 21, OL = 1 << 21;
	int olen = 0;
	char ibuf[IL], *IS = ibuf, *IT = ibuf, obuf[OL];
	inline int read() {
		register char ch = getc(); register int x = 0, f = 1;
		while(!isdigit(ch)) { if(ch == '-') f = -1; ch = getc(); }
		while(isdigit(ch)) x = x * 10 + ch - 48, ch = getc();
		return x * f;
	}
	inline double readdb() {
		register char ch = getc(); register double x = 0, f = 1;
		while(!isdigit(ch)) { if(ch == '-') f = -1; ch = getc(); }
		while(isdigit(ch)) x = x * 10 + ch - 48, ch = getc();
		if(ch == '.') {
			register double b = 0.1;
			ch = getc();
			while(isdigit(ch)) x += (ch - 48) * b, b *= 0.1, ch = getc();
		}
		return x * f;
	}
	inline int readstr(char *s) {
		register char ch = getc(); register int len = 0;
		while(!isalpha(ch)) ch = getc();
		while(isalpha(ch)) s[++len] = ch, ch = getc();
		return len;
	}
	inline void flush() { fwrite(obuf, 1, olen, stdout); olen = 0; }
	inline void putc(register char ch) { obuf[olen++] = ch; }
	template<class T>
	inline void write(register T x) {
		if(x < 0) obuf[olen++] = '-', x = -x;
		if(x > 9) write(x / 10);
		obuf[olen++] = x % 10 + 48;
	}
} using namespace IO;
const int N = 3e5 + 10;
int n, m;
struct edge {
	int to, w, c, nxt;
} e[N];
int head[N], ecnt;
void addedge(int u, int v, int w, int c) {
	e[++ecnt] = {v, w, c, head[u]};
	head[u] = ecnt;
}
int dis[N], dis2[N];
struct node {
	int dis, dis2, u;
	bool operator < (const node &y) const {
		return dis == y.dis ? dis2 < y.dis2 : dis > y.dis;
	}
};
bool vis[N];
void spfa() {
	memset(vis, 0, sizeof(vis));
	memset(dis, 0x3f, sizeof(dis));
	memset(dis2, 0, sizeof(dis2));
	queue<int> q;
	q.push(1);
	dis[1] = 0;
	while(!q.empty()) {
		int u = q.front();
		q.pop();
		vis[u] = 0;
		for(int i = head[u], v; i; i = e[i].nxt) {
			v = e[i].to;
			if(dis[v] > dis[u] + e[i].w || dis[v] == dis[u] + e[i].w && dis2[v] < dis2[u] + e[i].c) {
				dis[v] = dis[u] + e[i].w;
				dis2[v] = dis2[u] + e[i].c;
				if(!vis[v]) vis[v] = 1, q.push(v);
			}
		}
	}
}
void MAIN() {
	n = read(), m = read();
	ecnt = 0;
	memset(head, 0, sizeof(head));
	for(int i = 1, u, v, e, p; i <= m; i++)
		u = read(), v = read(), e = read(), p = read(), addedge(u, v, e, p);
	spfa();
	printf("%lld %lld\n", dis[n], dis2[n]);
}
signed main() {
	int T = read();
	while(T--) MAIN();
	return 0;
}

詳細信息

Test #1:

score: 0
Time Limit Exceeded

input:

12
100000 200000
1 2 838279516 902819511
1 3 293478832 513256010
2 4 682688353 204481674
2 5 360092507 651108247
5 6 519851939 323803002
6 7 675439277 205804465
7 8 419167205 386168059
6 9 140767493 382483305
9 10 558115401 613738466
9 11 902235661 744659643
9 12 851394758 1720015
12 13 635355827 46...

output:


result: