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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#333404#8057. Best Carry Player 4xuqinWA 13ms5824kbC++142.1kb2024-02-19 21:27:362024-02-19 21:27:36

Judging History

你现在查看的是最新测评结果

  • [2024-02-19 21:27:36]
  • 评测
  • 测评结果:WA
  • 用时:13ms
  • 内存:5824kb
  • [2024-02-19 21:27:36]
  • 提交

answer

#include<cstdio>
#include<cstring>
#include<algorithm>
#include<utility>
#include<ctime>
#include<vector>
#include<queue>
#include<iostream>
#include<set>
#include<random>
#include<cassert>
#include<string>
#include<cmath>
#include<bitset>
#include<chrono>
#include<map>
#include<unordered_map>
#define eb emplace_back

using namespace std;
const int maxn=5e5+10, maxm=1.2e4+10, inf=2e9+12;
typedef long long LL;
typedef unsigned long long ULL;
const LL INF=4e18;
typedef pair<int, int> pii;
typedef pair<LL, int> pli;
typedef pair<int, LL> pil;

inline int read() {
    int x=0, f=1; char c=getchar();
    for(; c<'0'||c>'9'; c=getchar()) if(c=='-') f=0;
    for(; c>='0'&&c<='9'; c=getchar()) x=x*10+c-'0';
    return f?x:-x;
}
int P=1e9;
inline int add(int x, int y) {x+=y; return x>=P?x-P:x;}
inline int del(int x, int y) {x-=y; return x<0?x+P:x;}
inline int ksm(int x, int y) {
    int s=1; for(; y; y>>=1, x=1LL*x*x%P) if(y&1) s=1LL*s*x%P; return s;
}
mt19937 rnd((unsigned)chrono::steady_clock::now().time_since_epoch().count());
int gcd(int x, int y) {return y?gcd(y, x%y):x;}


LL a[maxn], b[maxn];
int main() {
    int T=read();
    while(T--) {
        int m=read();
        LL suma=0, sumb=0;
        for(int i=0; i<m; ++i) a[i]=read(), suma+=a[i];
        for(int i=0; i<m; ++i) b[i]=read(), sumb+=b[i];
        if(suma<sumb) a[0]+=sumb-suma; else b[0]+=suma-sumb;
        int mxa=0, mxb=0;
        for(int i=0; i<m; ++i) if(a[i]>0) mxa=i;
        for(int i=0; i<m; ++i) if(b[i]>0) mxb=i;
        if(mxa+mxb<m) {printf("0\n"); continue;}
        LL c=0; int t=m-1, fl=0, mna=1e9, mnb=1e9;
        for(int i=0; i<m; ++i) {
            while(t>=m-i-1) {
                LL tmp=min(a[i], b[t]);
                if(tmp>0) {
                    if(i+t>=m) fl=1;
                    mna=min(mna, i);
                    mnb=min(mnb, t);
                }
                c+=tmp; a[i]-=tmp; b[t]-=tmp;
                if(b[t]==0) --t;
                if(a[i]==0) break;
            }
        }
        if(fl) printf("%lld\n", c);
            else printf("%lld\n", c-1);

    }
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 5824kb

input:

5
2
1 2
3 4
3
1 0 1
0 1 0
4
1 0 0 1
1 1 1 1
5
123456 114514 1919810 233333 234567
20050815 998244353 0 0 0
10
5 3 5 3 2 4 2 4 1 5
9 9 8 2 4 4 3 5 3 0

output:

5
1
2
467900
29

result:

ok 5 number(s): "5 1 2 467900 29"

Test #2:

score: -100
Wrong Answer
time: 13ms
memory: 5824kb

input:

100000
5
0 1 1 1 1
0 0 1 0 0
5
0 0 0 0 0
1 1 1 0 0
5
0 0 2 1 1
0 2 1 0 1
5
0 0 0 0 0
1 2 1 0 0
5
0 1 0 1 1
0 0 1 1 1
5
2 0 0 0 1
1 0 0 0 3
5
2 0 0 1 1
0 2 1 1 1
5
0 0 0 0 2
0 0 0 0 1
5
0 0 0 0 0
0 1 1 0 0
5
4 0 0 0 0
0 0 0 1 0
5
0 0 0 0 1
2 1 1 0 0
5
0 2 3 0 0
0 0 0 1 0
5
1 1 1 0 1
1 0 1 0 1
5
0 0 0...

output:

1
0
4
0
3
3
3
2
0
0
1
0
2
0
3
0
0
0
0
0
0
0
4
0
4
1
0
2
3
3
1
5
0
0
2
0
0
1
1
0
0
3
5
3
2
2
1
0
0
2
2
2
0
3
0
2
1
1
0
1
0
4
0
0
2
2
0
3
3
0
2
0
1
0
0
1
1
2
0
3
4
0
2
5
0
1
1
0
0
0
2
1
3
0
1
0
4
3
3
0
2
2
0
1
3
1
1
0
0
0
1
0
3
2
2
0
1
0
1
0
1
0
0
2
4
1
2
3
2
2
2
0
1
0
0
2
3
1
3
0
0
2
2
3
0
1
2
0
1
1
...

result:

wrong answer 1st numbers differ - expected: '2', found: '1'