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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#332371 | #1286. Ternary String Counting | Tokido_Saya | TL | 45ms | 199508kb | C++14 | 3.2kb | 2024-02-19 14:57:42 | 2024-02-19 14:57:42 |
Judging History
answer
// Sea, You & Me
#include<bits/stdc++.h>
#define LL long long
#define DB double
#define MOD 1000000007
#define ls(x) (x << 1)
#define rs(x) (x << 1 | 1)
#define lowbit(x) ((-x) & x)
#define MP make_pair
#define MT make_tuple
#define VI vector<int>
#define VL vector<LL>
#define VII VI::iterator
#define VLI VL::iterator
#define all(x) x.begin(), x.end()
#define EB emplace_back
#define PII pair<int, int>
#define SI set<int>
#define SII SI::iterator
#define fi first
#define se second
using namespace std;
template<typename T> void chkmn(T &a, const T b) { (a > b) && (a = b); }
template<typename T> void chkmx(T &a, const T b) { (a < b) && (a = b); }
void Inc(int &a, const int &b) { ((a += b) >= MOD) && (a -= MOD); }
void Dec(int &a, const int &b) { ((a -= b) < 0) && (a += MOD); }
void Mul(int &a, const int &b) { a = 1LL * a * b % MOD; }
void Sqr(int &a) { a = 1LL * a * a % MOD; }
int inc(const int &a, const int &b) { return (a + b >= MOD) ? a + b - MOD : a + b; }
int dec(const int &a, const int &b) { return (a - b < 0) ? a - b + MOD : a - b; }
int mul(const int &a, const int &b) { return 1LL * a * b % MOD; }
int sqr(const int &a) { return 1LL * a * a % MOD; }
int qwqmi(int x, int k = MOD - 2)
{
int res = 1;
while(k)
{
if(k & 1) Mul(res, x);
k >>= 1, Sqr(x);
}
return res;
}
template<typename T> void read(T &x)
{
x = 0;
int f = 1;
char ch = getchar();
while(!isdigit(ch))
{
if(ch == '-')
f = -1;
ch = getchar();
}
while(isdigit(ch))
{
x = (x << 1) + (x << 3) + (ch ^ 48);
ch = getchar();
}
x = x * f;
}
const int N = 5e3 + 5;
int T, n, m;
int jl[N], jr[N], kl[N], kr[N];
int f[2][N][N];
void work()
{
read(n), read(m);
for(int i = 1; i <= n; ++i)
{
jl[i] = kl[i] = 0;
jr[i] = kr[i] = i - 1;
}
for(int i = 1; i <= m; ++i)
{
int l, r, x;
read(l), read(r), read(x);
if(x == 1) chkmn(jr[r], l - 1), chkmn(kr[r], l - 1);
if(x == 2) chkmx(jl[r], l), chkmn(kr[r], l - 1);
if(x == 3) chkmx(jl[r], l), chkmx(kl[r], l);
}
for(int i = 2; i <= n; ++i)
{
chkmx(jl[i], jl[i - 1]);
chkmx(kl[i], kl[i - 1]);
}
for(int i = n; i >= 2; --i)
{
chkmn(jr[i - 1], jr[i]);
chkmn(kr[i - 1], kr[i]);
}
for(int i = 1; i <= n; ++i)
if(jl[i] > jr[i] || kl[i] > kr[i])
return puts("0"), void();
// for(int i = 1; i <= n; ++i)
// cerr << jl[i] << ' ' << jr[i] << ' ' << kl[i] << ' ' << kr[i] << '\n';
int now = 0, lst = 1;
for(int j = 0; j < n; ++j)
for(int k = 0; k <= j; ++k)
f[now][j][k] = 0;
f[now][0][0] = 3;
for(int i = 1; i < n; ++i)
{
swap(now, lst);
// cerr << jl[i] << ' ' << jr[i] << '\n';
// cerr << kl[i] << ' ' << kr[i] << '\n';
memset(f[now], 0, sizeof(f[now]));
for(int j = jl[i]; j <= jr[i]; ++j)
for(int k = kl[i]; k <= kr[i] && (k < j || k == 0); ++k)
{
Inc(f[now][i][j], f[lst][j][k]);
Inc(f[now][i][k], f[lst][j][k]);
Inc(f[now][j][k], f[lst][j][k]);
}
}
int ans = 0;
for(int j = jl[n]; j <= jr[n]; ++j)
for(int k = kl[n]; k <= kr[n]; ++k)
Inc(ans, f[now][j][k]);
printf("%d\n", ans);
}
int main()
{
read(T);
while(T--)
work();
return 0;
}
/* sample
4
1 0
2 0
3 0
5 2
1 3 3
4 5 1
ans :
3
9
27
18
*/
詳細信息
Test #1:
score: 100
Accepted
time: 45ms
memory: 199508kb
input:
4 1 0 2 0 3 0 5 2 1 3 3 4 5 1
output:
3 9 27 18
result:
ok 4 tokens
Test #2:
score: -100
Time Limit Exceeded
input:
741 5 3 1 5 3 3 4 2 1 4 3 4 3 2 4 2 1 4 1 2 3 3 10 3 9 10 2 3 6 3 1 9 1 3 4 2 3 2 1 3 2 2 3 3 1 3 3 10 4 6 6 1 9 10 2 4 8 3 4 10 3 6 3 1 4 3 2 4 2 2 2 2 4 3 1 4 1 1 1 2 2 3 1 5 3 4 5 2 4 5 1 1 4 3 9 3 2 3 2 1 9 2 2 4 2 4 3 1 3 3 2 3 2 1 2 3 8 4 5 8 1 4 8 1 3 5 3 1 3 3 9 3 4 5 1 1 5 3 3 8 2 8 3 5 7 2...