QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#332071 | #7737. Extending Distance | 275307894a | WA | 0ms | 4124kb | C++14 | 3.2kb | 2024-02-19 07:47:08 | 2024-02-19 07:47:09 |
Judging History
answer
#include<bits/stdc++.h>
#define Gc() getchar()
#define Me(x,y) memset(x,y,sizeof(x))
#define Mc(x,y) memcpy(x,y,sizeof(x))
#define d(x,y) ((m)*(x-1)+(y))
#define R(n) (rnd()%(n)+1)
#define Pc(x) putchar(x)
#define LB lower_bound
#define UB upper_bound
#define fi first
#define se second
#define eb emplace_back
using namespace std;using ll=long long;using db=double;using lb=long db;using ui=unsigned;using ull=unsigned long long;using pii=pair<int,int>;
const int N=500+5,M=N*N+5,K=1000+5,mod=998244353,Mod=mod-1;const db eps=1e-9;const int INF=1e9+7;mt19937 rnd(263082);
#define Tp template<typename T>
#define Ts template<typename T,typename... Ar>
namespace Debug{
Tp void _debug(char* f,T t){cerr<<f<<'='<<t<<endl;}
Ts void _debug(char* f,T x,Ar... y){while(*f!=',') cerr<<*f++;cerr<<'='<<x<<",";_debug(f+1,y...);}
#define gdb(...) _debug((char*)#__VA_ARGS__,__VA_ARGS__)
}using namespace Debug;
int n,m,k;
struct yyy{int to,w,g,z;};struct ljb{int head,h[N];yyy f[N*10];void add(int x,int y,int w,int g){f[++head]=(yyy){y,w,g,h[x]};h[x]=head;}}s;
void con(int x,int y,int w,int g){s.add(x,y,w,g);s.add(y,x,-w,0);}
int S,T;
namespace Dicnic{
int d[N];
int bfs(){
queue<int> q;Me(d,0x3f);d[S]=0;q.emplace(S);
while(!q.empty()){
int x=q.front();q.pop();yyy tmp;//gdb(x,d[x]);
for(int i=s.h[x];i;i=tmp.z){
tmp=s.f[i];if(!tmp.g||d[tmp.to]<=d[x]+tmp.w) continue;
d[tmp.to]=d[x]+tmp.w;q.emplace(tmp.to);
}
}
return d[T]<=INF;
}
int vis[N];
ll dfs(int x,ll sum){//gdb(x,sum);
if(x==T) return sum;ll tot=0;yyy tmp;vis[x]=1;
for(int i=s.h[x];i;i=tmp.z){
tmp=s.f[i];if(!tmp.g||d[tmp.to]!=d[x]+tmp.w||vis[tmp.to]) continue;
ll k=dfs(tmp.to,min(sum,1ll*tmp.g));s.f[i].g-=k;s.f[i^1].g+=k;sum-=k;tot+=k;if(!sum) break;
}
vis[x]=0;
return tot;
}
ll calc(){
ll ans=0;int ti=k;
while(bfs()&&ti){
if(!d[T]) dfs(S,1e18);
else{
int g=dfs(S,ti);
ti-=g;ans+=g*d[T];
}
}
return ans;
}
}
int getid(int x,int y){
if(!x) return 0;if(x==n) return T;
return (x-1)*(m-1)+y;
}
int a1[N][N],a2[N][N];
void Solve(){
int i,j;scanf("%d%d%d",&n,&m,&k);
fill(s.h,s.h+n*m+3,0);s.head=1;
S=0;T=(n-1)*(m-1)+1;
for(i=1;i<=n;i++) for(j=1;j<m;j++){
int x;scanf("%d",&x);a1[i][j]=x;
int ix=getid(i-1,j),iy=getid(i,j);
con(ix,iy,0,x);con(iy,ix,0,x);
con(ix,iy,1,k);con(iy,ix,1,k);
}
for(i=1;i<n;i++) for(j=1;j<=m;j++){
int x;scanf("%d",&x);a2[i][j]=x;
if(j==1||j==m) continue;
int ix=getid(i,j-1),iy=getid(i,j);
con(ix,iy,0,x);con(iy,ix,0,x);
con(ix,iy,1,k);con(iy,ix,1,k);
}
printf("%lld\n",Dicnic::calc());
for(i=1;i<n;i++) for(j=1;j<m;j++){
int id=getid(i,j);yyy tmp;
for(int p=s.h[id];p;p=tmp.z){
tmp=s.f[p];if(tmp.w<=0) continue;
if(tmp.to==getid(i,j-1)&&j^1) a2[i][j]+=k-tmp.g;
if(tmp.to==getid(i,j+1)&&j^m-1) a2[i][j+1]+=k-tmp.g;
if(tmp.to==getid(i-1,j)) a1[i][j]+=k-tmp.g;
if(tmp.to==getid(i+1,j)) a1[i+1][j]+=k-tmp.g;
}
}
for(i=1;i<=n;i++) for(j=1;j<m;j++) printf("%d%c",a1[i][j]," \n"[j==m-1]);
for(i=1;i<n;i++) for(j=1;j<=m;j++) printf("%d%c",a2[i][j]," \n"[j==m]);
}
int main(){
int t=1;
scanf("%d",&t);
while(t--) Solve();
cerr<<clock()*1.0/CLOCKS_PER_SEC<<'\n';
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 0
Wrong Answer
time: 0ms
memory: 4124kb
input:
2 3 4 6 2 1 15 7 1 9 13 3 2 3 6 1 2 5 2 15 3 3 3 3 1 1 2 2 3 3 1 1 1 2 2 2
output:
9 2 1 15 8 1 9 13 3 5 3 6 6 2 5 2 15 3 4 1 1 2 3 3 3 1 1 1 2 2 2
result:
wrong answer The output T doesn't match number of operations. (test case 2)