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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#330261#8057. Best Carry Player 4ucup-team133#WA 97ms3536kbC++176.8kb2024-02-17 14:08:242024-02-17 14:08:25

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你现在查看的是最新测评结果

  • [2024-02-17 14:08:25]
  • 评测
  • 测评结果:WA
  • 用时:97ms
  • 内存:3536kb
  • [2024-02-17 14:08:24]
  • 提交

answer

// -fsanitize=undefined,
//#define _GLIBCXX_DEBUG


#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")

#include <iostream>
#include <vector>
#include <string>
#include <map>
#include <set>
#include <queue>
#include <algorithm>
#include <cmath>
#include <iomanip>
#include <random>
#include <stdio.h>
#include <fstream>
#include <functional>
#include <cassert>
#include <unordered_map>
#include <bitset>
#include <chrono>

#include <algorithm>

#ifdef _MSC_VER
#include <intrin.h>
#endif

namespace atcoder {

namespace internal {

// @param n `0 <= n`
// @return minimum non-negative `x` s.t. `n <= 2**x`
int ceil_pow2(int n) {
    int x = 0;
    while ((1U << x) < (unsigned int)(n)) x++;
    return x;
}

// @param n `1 <= n`
// @return minimum non-negative `x` s.t. `(n & (1 << x)) != 0`
int bsf(unsigned int n) {
#ifdef _MSC_VER
    unsigned long index;
    _BitScanForward(&index, n);
    return index;
#else
    return __builtin_ctz(n);
#endif
}

}  // namespace internal

}  // namespace atcoder

#include <cassert>
#include <vector>

namespace atcoder {

template <class S, S (*op)(S, S), S (*e)()> struct segtree {
  public:
    segtree() : segtree(0) {}
    segtree(int n) : segtree(std::vector<S>(n, e())) {}
    segtree(const std::vector<S>& v) : _n(int(v.size())) {
        log = internal::ceil_pow2(_n);
        size = 1 << log;
        d = std::vector<S>(2 * size, e());
        for (int i = 0; i < _n; i++) d[size + i] = v[i];
        for (int i = size - 1; i >= 1; i--) {
            update(i);
        }
    }

    void set(int p, S x) {
        assert(0 <= p && p < _n);
        p += size;
        d[p] = x;
        for (int i = 1; i <= log; i++) update(p >> i);
    }

    S get(int p) {
        assert(0 <= p && p < _n);
        return d[p + size];
    }

    S prod(int l, int r) {
        assert(0 <= l && l <= r && r <= _n);
        S sml = e(), smr = e();
        l += size;
        r += size;

        while (l < r) {
            if (l & 1) sml = op(sml, d[l++]);
            if (r & 1) smr = op(d[--r], smr);
            l >>= 1;
            r >>= 1;
        }
        return op(sml, smr);
    }

    S all_prod() { return d[1]; }

    template <bool (*f)(S)> int max_right(int l) {
        return max_right(l, [](S x) { return f(x); });
    }
    template <class F> int max_right(int l, F f) {
        assert(0 <= l && l <= _n);
        assert(f(e()));
        if (l == _n) return _n;
        l += size;
        S sm = e();
        do {
            while (l % 2 == 0) l >>= 1;
            if (!f(op(sm, d[l]))) {
                while (l < size) {
                    l = (2 * l);
                    if (f(op(sm, d[l]))) {
                        sm = op(sm, d[l]);
                        l++;
                    }
                }
                return l - size;
            }
            sm = op(sm, d[l]);
            l++;
        } while ((l & -l) != l);
        return _n;
    }

    template <bool (*f)(S)> int min_left(int r) {
        return min_left(r, [](S x) { return f(x); });
    }
    template <class F> int min_left(int r, F f) {
        assert(0 <= r && r <= _n);
        assert(f(e()));
        if (r == 0) return 0;
        r += size;
        S sm = e();
        do {
            r--;
            while (r > 1 && (r % 2)) r >>= 1;
            if (!f(op(d[r], sm))) {
                while (r < size) {
                    r = (2 * r + 1);
                    if (f(op(d[r], sm))) {
                        sm = op(d[r], sm);
                        r--;
                    }
                }
                return r + 1 - size;
            }
            sm = op(d[r], sm);
        } while ((r & -r) != r);
        return 0;
    }

  private:
    int _n, size, log;
    std::vector<S> d;

    void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }
};

}  // namespace atcoder





using namespace std;
using namespace atcoder;




#define rep(i,n) for (int i=0;i<n;i+=1)
#define rrep(i,n) for (int i=n-1;i>-1;i--)
#define pb push_back
#define all(x) (x).begin(), (x).end()

#define debug(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << " )\n";

template<class T>
using vec = vector<T>;
template<class T>
using vvec = vec<vec<T>>;
template<class T>
using vvvec = vec<vvec<T>>;
using ll = long long;
using pii = pair<int,int>;
using pll = pair<ll,ll>;


template<class T>
bool chmin(T &a, T b){
  if (a>b){
    a = b;
    return true;
  }
  return false;
}

template<class T>
bool chmax(T &a, T b){
  if (a<b){
    a = b;
    return true;
  }
  return false;
}

template<class T>
T sum(vec<T> x){
  T res=0;
  for (auto e:x){
    res += e;
  }
  return res;
}

template<class T>
void printv(vec<T> x){
  for (auto e:x){
    cout<<e<<" ";
  }
  cout<<endl;
}



template<class T,class U>
ostream& operator<<(ostream& os, const pair<T,U>& A){
  os << "(" << A.first <<", " << A.second << ")";
  return os;
}

template<class T>
ostream& operator<<(ostream& os, const set<T>& S){
  os << "set{";
  for (auto a:S){
    os << a;
    auto it = S.find(a);
    it++;
    if (it!=S.end()){
      os << ", ";
    }
  }
  os << "}";
  return os;
}

template<class T>
ostream& operator<<(ostream& os, const vec<T>& A){
  os << "[";
  rep(i,A.size()){
    os << A[i];
    if (i!=A.size()-1){
      os << ", ";
    }
  }
  os << "]" ;
  return os;
}

struct S{
  ll a_rest,b_rest,match;
};

S op(S a,S b){
  S res;
  ll new_match = min(a.b_rest,b.a_rest);

  res.match = a.match + b.match + new_match;
  res.a_rest = a.a_rest + b.a_rest - new_match;
  res.b_rest = a.b_rest + b.b_rest - new_match;
  return res;
}

S e(){
  return {0,0,0};
}

const ll INF = 1e15;


ll solve_sub(int m,vec<ll> A,vec<ll> B,int which_inf){

  if (which_inf){
    A[0] = INF;
  }
  else{
    B[0] = INF;
  }

  reverse(all(B));

  

  segtree<S,op,e> seg(m);

  auto set_val = [&](int i,ll a,ll b){
    S val;
    val.a_rest = a - min(a,b);
    val.b_rest = b - min(a,b);
    val.match = min(a,b);
    seg.set(i,val);
  };


  rep(i,m){
    set_val(i,A[i],B[i]);
  }


  ll res = 0;
  rep(i,m){
    if (i == 0) continue;
    if (A[i] && B[i-1]){
      set_val(i,A[i]-1,B[i]);
      set_val(i-1,A[i-1],B[i-1]-1);
      chmax(res,1ll+seg.all_prod().match);

      set_val(i,A[i],B[i]);
      set_val(i-1,A[i-1],B[i-1]);
    }
  }

  return res;
}

void solve(){
  int m;
  cin>>m;
  vec<ll> A(m),B(m);
  rep(i,m) cin>>A[i];
  rep(i,m) cin>>B[i];

  cout << max(solve_sub(m,A,B,0),solve_sub(m,A,B,1)) << "\n";
}

  
  







int main(){
  ios::sync_with_stdio(false);
  std::cin.tie(nullptr);

  
  int T;
  cin>>T;
  while (T--){
    solve();
  }

}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3484kb

input:

5
2
1 2
3 4
3
1 0 1
0 1 0
4
1 0 0 1
1 1 1 1
5
123456 114514 1919810 233333 234567
20050815 998244353 0 0 0
10
5 3 5 3 2 4 2 4 1 5
9 9 8 2 4 4 3 5 3 0

output:

5
1
2
467900
29

result:

ok 5 number(s): "5 1 2 467900 29"

Test #2:

score: -100
Wrong Answer
time: 97ms
memory: 3536kb

input:

100000
5
0 1 1 1 1
0 0 1 0 0
5
0 0 0 0 0
1 1 1 0 0
5
0 0 2 1 1
0 2 1 0 1
5
0 0 0 0 0
1 2 1 0 0
5
0 1 0 1 1
0 0 1 1 1
5
2 0 0 0 1
1 0 0 0 3
5
2 0 0 1 1
0 2 1 1 1
5
0 0 0 0 2
0 0 0 0 1
5
0 0 0 0 0
0 1 1 0 0
5
4 0 0 0 0
0 0 0 1 0
5
0 0 0 0 1
2 1 1 0 0
5
0 2 3 0 0
0 0 0 1 0
5
1 1 1 0 1
1 0 1 0 1
5
0 0 0...

output:

2
0
4
0
3
0
3
0
0
0
1
1
3
0
3
0
0
0
0
0
0
0
4
0
4
0
0
2
3
3
0
5
0
0
2
0
0
1
1
0
0
3
5
3
2
2
2
0
1
0
0
2
0
0
0
2
0
1
0
1
0
4
0
0
0
2
0
3
3
0
2
0
0
0
0
1
1
2
0
0
4
0
2
5
0
2
1
0
0
0
3
2
3
0
2
0
4
3
3
0
0
2
0
1
3
1
1
0
0
0
0
0
3
2
0
0
0
0
1
0
1
0
0
0
4
1
0
0
2
0
2
0
2
0
0
0
3
0
3
1
0
2
0
3
0
1
2
0
0
1
...

result:

wrong answer 6th numbers differ - expected: '3', found: '0'