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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#330089 | #8057. Best Carry Player 4 | ucup-team3099# | WA | 49ms | 3844kb | C++20 | 4.5kb | 2024-02-17 12:13:23 | 2024-02-17 12:13:23 |
Judging History
answer
#ifdef LOCAL
#define _GLIBCXX_DEBUG 1
#define dbg(...) cerr << "LINE(" << __LINE__ << ") -> [" << #__VA_ARGS__ << "]: [", DBG(__VA_ARGS__)
#else
#define dbg(...) 0
#endif
#if 0
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
template<class T>
using ordered_set = __gnu_pbds::tree<T, __gnu_pbds::null_type, std::less<T>, __gnu_pbds::rb_tree_tag,
__gnu_pbds::tree_order_statistics_node_update>;
#endif
#include <vector>
#include <list>
#include <map>
#include <set>
#include <queue>
#include <stack>
#include <bitset>
#include <algorithm>
#include <numeric>
#include <utility>
#include <sstream>
#include <iostream>
#include <iomanip>
#include <cstdio>
#include <cmath>
#include <cstdlib>
#include <ctime>
#include <cstring>
#include <random>
#include <chrono>
#include <cassert>
using namespace std;
#define rep(i, a, b) for(int i = a; i < (b); ++i)
#define sz(x) (int)(x).size()
#define all(x) begin(x), end(x)
#define FOR(i,a,b) for (int i = (a); i < (b); ++i)
#define F0R(i,a) FOR(i,0,a)
#define REP(i,n) for(int (i)=0;(i)<(int)(n);(i)++)
#define each(a,x) for (auto& a: x)
#define tcT template<class T
#define tcTU tcT, class U
#define tcTUU tcT, class ...U
template<class T> using V = vector<T>;
template<class T, size_t SZ> using AR = array<T,SZ>;
typedef string str;
typedef long long ll;
typedef pair<int, int> pii;
typedef vector<int> vi;
typedef vector<vi> vvi;
template<typename T, typename U> T &ctmax(T &x, const U &y){ return x = max<T>(x, y); }
template<typename T, typename U> T &ctmin(T &x, const U &y){ return x = min<T>(x, y); }
mt19937 rng((unsigned)chrono::steady_clock::now().time_since_epoch().count());
#define ts to_string
str ts(char c) { return str(1,c); }
str ts(bool b) { return b ? "true" : "false"; }
str ts(const char* s) { return (str)s; }
str ts(str s) { return s; }
str ts(vector<bool> v) { str res = "{"; F0R(i,sz(v)) res += char('0'+v[i]); res += "}"; return res; }
template<size_t SZ> str ts(bitset<SZ> b) { str res = ""; F0R(i,SZ) res += char('0'+b[i]); return res; }
template<class A, class B> str ts(pair<A,B> p);
template<class T> str ts(T v) { bool fst = 1; str res = "{"; for (const auto& x: v) {if (!fst) res += ", "; fst = 0; res += ts(x);} res += "}"; return res;}
template<class A, class B> str ts(pair<A,B> p) {return "("+ts(p.first)+", "+ts(p.second)+")"; }
template<class A> void pr(A x) { cout << ts(x); }
template<class H, class... T> void pr(const H& h, const T&... t) { pr(h); pr(t...); }
void ps() { pr("\n"); }
template<class H, class... T> void ps(const H& h, const T&... t) { pr(h); if (sizeof...(t)) pr(" "); ps(t...); }
void DBG() { cerr << "]" << endl; }
template<class H, class... T> void DBG(H h, T... t) {cerr << ts(h); if (sizeof...(t)) cerr << ", "; DBG(t...); }
tcTU> void re(pair<T,U>& p);
tcT> void re(V<T>& v);
tcT, size_t SZ> void re(AR<T,SZ>& a);
tcT> void re(T& x) { cin >> x; }
void re(double& d) { str t; re(t); d = stod(t); }
void re(long double& d) { str t; re(t); d = stold(t); }
tcTUU> void re(T& t, U&... u) { re(t); re(u...); }
tcTU> void re(pair<T,U>& p) { re(p.first,p.second); }
tcT> void re(V<T>& x) { each(a,x) re(a); }
tcT, size_t SZ> void re(AR<T,SZ>& x) { each(a,x) re(a); }
tcT> void rv(int n, V<T>& x) { x.rsz(n); re(x); }
constexpr bool multitest() {return 1;}
void solve();
int main() {
ios_base::sync_with_stdio(false); cin.tie(NULL);
int t = 1;
if (multitest()) cin >> t;
for (; t; t--) solve();
}
void solve() {
int m; re(m);
vector<ll> a(m), b(m); re(a,b);
ll totA = 0, totB = 0;
for (ll x : a) totA += x;
for (ll x : b) totB += x;
a[0] += max(0ll, totB-totA);
b[0] += max(0ll, totA-totB);
ll ans = 0;
int mA = 0, mB = 0;
for (int i = 0; i < m; i++) {
if (a[i]) mA = i;
if (b[i]) mB = i;
}
int at = 0;
bool ok = false;
for (int i = m-1; i >= 0; i--) {
while (at < m && i+at < m-1) at++;
while (a[i] && at < m) {
ll tak = min(a[i], b[at]);
a[i] -= tak;
b[at] -= tak;
if (i + at >= m) ok = true;
ans += tak;
if (b[at] == 0) at++;
}
}
if (ok) {
ps(ans);
return;
}
for (int i = 0; i < m; i++) {
if (i + mB >= m && a[i]) {
ps(ans);
return;
}
if (i + mA >= m && b[i]) {
ps(ans);
return;
}
}
if (mA + mB >= m) {
ps(ans-1);
return;
}
ps(0);
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 0ms
memory: 3764kb
input:
5 2 1 2 3 4 3 1 0 1 0 1 0 4 1 0 0 1 1 1 1 1 5 123456 114514 1919810 233333 234567 20050815 998244353 0 0 0 10 5 3 5 3 2 4 2 4 1 5 9 9 8 2 4 4 3 5 3 0
output:
5 1 2 467900 29
result:
ok 5 number(s): "5 1 2 467900 29"
Test #2:
score: -100
Wrong Answer
time: 49ms
memory: 3844kb
input:
100000 5 0 1 1 1 1 0 0 1 0 0 5 0 0 0 0 0 1 1 1 0 0 5 0 0 2 1 1 0 2 1 0 1 5 0 0 0 0 0 1 2 1 0 0 5 0 1 0 1 1 0 0 1 1 1 5 2 0 0 0 1 1 0 0 0 3 5 2 0 0 1 1 0 2 1 1 1 5 0 0 0 0 2 0 0 0 0 1 5 0 0 0 0 0 0 1 1 0 0 5 4 0 0 0 0 0 0 0 1 0 5 0 0 0 0 1 2 1 1 0 0 5 0 2 3 0 0 0 0 0 1 0 5 1 1 1 0 1 1 0 1 0 1 5 0 0 0...
output:
2 0 4 0 3 3 3 2 0 0 1 1 3 0 3 1 1 0 0 0 0 0 4 1 4 1 0 2 3 3 1 5 0 0 2 0 1 1 1 0 1 3 5 3 2 2 2 0 1 2 2 2 0 3 1 2 1 1 0 1 0 4 2 2 2 2 0 3 3 0 2 0 1 0 1 2 1 2 0 3 4 0 2 5 0 2 1 1 1 0 3 2 3 0 2 0 4 3 3 0 2 2 0 1 3 1 1 0 1 0 1 0 3 2 2 0 2 1 1 1 2 0 0 2 4 1 3 3 2 2 2 0 2 0 0 2 3 1 3 1 0 2 2 3 0 1 2 0 1 1 ...
result:
wrong answer 16th numbers differ - expected: '0', found: '1'