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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#329593 | #5071. Check Pattern is Good | Watware | WA | 69ms | 3808kb | C++17 | 3.1kb | 2024-02-16 22:26:55 | 2024-02-16 22:26:55 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
constexpr int M = 120, E = 4010, S = 1, T = 2, inf = 1000000;
char c;
int t, n, m, mp[M][M], id[M][M], dep[M], x[M], y[M];
int to[E], nxt[E], val[E], head[M], cur[M], tot;
inline void add(int u, int v, int w) {
to[tot] = v, val[tot] = w, nxt[tot] = head[u], head[u] = tot++;
}
inline void add1(int u, int v) { add(u, v, 1), add(v, u, 0); }
inline void add2(int u, int v) { add(u, v, inf), add(v, u, inf); }
inline bool bfs() {
queue<int> q;
memset(dep, -1, sizeof(dep)), dep[S] = 0, q.push(S);
while (!q.empty()) {
int p = q.front();
q.pop();
for (int i = head[p]; i; i = nxt[i])
if (val[i] && dep[to[i]] == -1) dep[to[i]] = dep[p] + 1, q.push(to[i]);
}
return dep[T] != -1;
}
int dfs(int n, int fl) {
if (n == T) return fl;
int lf = fl;
for (int &i = cur[n]; i; i = nxt[i])
if (dep[to[i]] == dep[n] + 1 && val[i]) {
int g = dfs(to[i], min(fl, val[i]));
lf -= g, val[i] -= g, val[i ^ 1] += g;
if (!lf) return fl;
}
return fl - lf;
}
inline int dinic() {
int result = 0;
while (bfs()) memcpy(cur, head, sizeof(head)), result += dfs(S, inf);
return result;
}
inline void solve() {
assert(scanf("%d%d", &n, &m));
memset(head, 0, sizeof(head)), tot = id[0][0] = 2;
for (int i = 1; i <= n; i++)
for (int j = 1; j <= m; j++) {
assert(scanf(" %c", &c));
if (c == '?') mp[i][j] = -1;
else mp[i][j] = ((i + j) & 1) ^ (c == 'W');
}
int ans = 0;
for (int i = 1; i < n; i++)
for (int j = 1; j < m; j++) id[i][j] = ++id[0][0], x[id[0][0]] = i, y[id[0][0]] = j;
for (int i = 1; i < n; i++)
for (int j = 1; j < m; j++) {
bool e0 = false, e1 = false;
for (int u = i; u <= i + 1; u++)
for (int v = j; v <= j + 1; v++)
if (mp[u][v] == 1) e1 = true;
else if (mp[u][v] == 0) e0 = true;
if (!e1) add1(S, id[i][j]), ans++;
if (!e0) add1(id[i][j], T), ans++;
}
for (int i = 1; i < n; i++)
for (int j = 1; j < m; j++) {
if (i + 1 < n) add2(id[i][j], id[i + 1][j]);
if (j + 1 < m) add2(id[i][j], id[i][j + 1]);
if (i + 1 < n && j + 1 < m) add2(id[i][j], id[i + 1][j + 1]);
if (i + 1 < n && j - 1 >= 1) add2(id[i][j], id[i + 1][j - 1]);
}
printf("%d\n", ans - dinic());
bfs();
for (int i = 1; i < n; i++)
for (int j = 1; j < m; j++) {
int t = dep[id[i][j]] != -1 ? 0 : 1;
for (int u = i; u <= i + 1; u++)
for (int v = j; v <= j + 1; v++)
if (mp[u][v] == -1) mp[u][v] = t;
}
for (int i = 1; i <= n; i++, printf("\n"))
for (int j = 1; j <= m; j++) {
// if (mp[i][j] == -1) mp[i][j] = 0;
mp[i][j] ^= (i + j) & 1;
putchar(mp[i][j] ? 'W' : 'B');
}
}
int main() {
assert(scanf("%d", &t));
while (t--) solve();
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3800kb
input:
3 2 2 ?? ?? 3 3 BW? W?B ?BW 3 3 BW? W?W ?W?
output:
1 WB BW 1 BWW WWB WBW 4 BWB WBW BWB
result:
ok ok (3 test cases)
Test #2:
score: -100
Wrong Answer
time: 69ms
memory: 3808kb
input:
10000 9 2 BB BW WW WW ?W ?B B? W? BB 6 2 ?? ?B B? BW WW ?? 10 7 WBBBW?? ???BWWW ???BWWB ??WWBW? BBWBBWB WWB?WW? BWBW??? WWWWBBW BBWBB?W B?W?W?B 4 7 ??WBWWB ?BBWWWB ?W?BBB? BBBWBBB 10 1 B W ? B B W W W B ? 10 4 ??WW W?W? WWW? ???W ?W?? ?W?W W?W? ?W?W ???W ???W 8 3 WBW W?? ??? ??? W?W W?W ??? ?W? 4 1 ...
output:
3 BB BW WW WW BW WB BW WB BB 2 BW WB BW BW WW WB 9 WBBBWBW BWBBWWW WBWBWWB BWWWBWB BBWBBWB WWBWWWB BWBWWBW WWWWBBW BBWBBBW BWWWWWB 4 WBWBWWB BBBWWWB WWWBBBW BBBWBBB 0 B W W B B W W W B W 13 WBWW WWWW WWWB BWBW WWWB BWBW WBWB BWBW WBWW BWBW 8 WBW WWB WBW BWB WBW WWW WBW BWB 0 W B W W 1 WBWB WWBB 3 BW...
result:
wrong answer ans finds a larger answer (test case 4)