QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#32618#866. Display of SpringsAutumnKiteTL 1ms3644kbC++171.9kb2022-05-22 13:26:102022-05-22 13:26:11

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2022-05-22 13:26:11]
  • 评测
  • 测评结果:TL
  • 用时:1ms
  • 内存:3644kb
  • [2022-05-22 13:26:10]
  • 提交

answer

#include <bits/stdc++.h>

const int LIM = 100000;

int compare(int i, int j, int x) {
  std::cout << "? " << i << " " << j << " " << x << std::endl;
  std::string tmp;
  std::cin >> tmp;
  if (tmp == "FIRST") {
    return 1;
  } else if (tmp == "SECOND") {
    return -1;
  } else {
    return 0;
  }
}

class lichao_tree {
  struct node {
    node *ls, *rs;
    int id;

    node(int t_id) : ls(), rs(), id(t_id) {}
  };

  node *rt;

  void insert(node *&u, int l, int r, int id) {
    if (u == nullptr) {
      u = new node(id);
      return;
    }
    if (l == r) {
      if (compare(id, u->id, l) > 0) {
        u->id = id;
        return;
      }
    }
    int mid = (l + r) >> 1;
    if (compare(id, u->id, mid) > 0) {
      std::swap(id, u->id);
    }
    if (compare(id, u->id, l) > 0) {
      insert(u->ls, l, mid, id);
    } else {
      insert(u->rs, mid + 1, r, id);
    }
  }

  int query(node *u, int l, int r, int x) {
    if (u == nullptr) {
      return -1;
    }
    if (l == r) {
      return u->id;
    }
    int mid = (l + r) >> 1;
    int res;
    if (x <= mid) {
      res = query(u->ls, l, mid, x);
    } else {
      res = query(u->rs, mid + 1, r, x);
    }
    if (res == -1 || compare(u->id, res, x) > 0) {
      return u->id;
    } else {
      return res;
    }
  }

public:
  lichao_tree(int n) : rt() {
    for (int i = 0; i < n; ++i) {
      insert(rt, 1, LIM, i);
    }
    std::cout << "!" << std::endl;
  }

  void query(int x) {
    int res = query(rt, 1, LIM, x);
    std::cout << "! " << res << std::endl;
  }
};

int main() {
  std::ios_base::sync_with_stdio(false);
  std::cin.tie(nullptr);

  int n;
  std::cin >> n;
  lichao_tree T(n);
  while (true) {
    std::string tmp;
    std::cin >> tmp;
    if (tmp == "FINISH") {
      return 0;
    }
    int x;
    std::cin >> x;
    T.query(x);
  }
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 3644kb

input:

3
FIRST
SECOND
FIRST
FIRST
QUESTION 2
SECOND
QUESTION 6
FIRST
FINISH

output:

? 1 0 50000
? 0 1 1
? 2 1 50000
? 1 2 1
!
? 2 1 2
! 1
? 2 1 6
! 2

result:

ok Correct answer

Test #2:

score: 0
Accepted
time: 0ms
memory: 3596kb

input:

6
FIRST
EQUAL
FIRST
FIRST
FIRST
FIRST
FIRST
FIRST
FIRST
FIRST
FIRST
FIRST
FIRST
FIRST
FIRST
FIRST
FIRST
FIRST
FIRST
FIRST
FIRST
FIRST
QUESTION 1
SECOND
SECOND
SECOND
SECOND
QUESTION 2
EQUAL
SECOND
SECOND
SECOND
QUESTION 3
FIRST
EQUAL
SECOND
SECOND
QUESTION 4
FIRST
FIRST
EQUAL
SECOND
QUESTION 5
FIRST...

output:

? 1 0 50000
? 0 1 1
? 2 1 50000
? 1 2 1
? 3 2 50000
? 2 3 1
? 2 1 25000
? 1 2 1
? 4 3 50000
? 3 4 1
? 3 2 25000
? 2 3 1
? 2 1 12500
? 1 2 1
? 5 4 50000
? 4 5 1
? 4 3 25000
? 3 4 1
? 3 2 12500
? 2 3 1
? 2 1 6250
? 1 2 1
!
? 2 1 1
? 3 1 1
? 4 1 1
? 5 1 1
! 1
? 2 1 2
? 3 1 2
? 4 1 2
? 5 1 2
! 1
? 2 1 3...

result:

ok Correct answer

Test #3:

score: -100
Time Limit Exceeded

input:

326
SECOND
SECOND
SECOND
FIRST
FIRST
FIRST
FIRST
FIRST
SECOND
FIRST
SECOND
FIRST
FIRST
SECOND
SECOND
SECOND
SECOND
SECOND
SECOND
FIRST
SECOND
SECOND
SECOND
FIRST
SECOND
SECOND
SECOND
SECOND
FIRST
SECOND
FIRST
SECOND
FIRST
SECOND
SECOND
SECOND
SECOND
SECOND
FIRST
SECOND
FIRST
SECOND
SECOND
SECOND
FIR...

output:

? 1 0 50000
? 1 0 1
? 2 0 50000
? 2 0 1
? 3 0 50000
? 0 3 1
? 0 2 25000
? 2 0 1
? 4 3 50000
? 4 3 1
? 4 0 25000
? 4 0 1
? 4 2 12500
? 2 4 1
? 5 3 50000
? 5 3 1
? 5 1 75000
? 5 1 50001
? 6 3 50000
? 6 3 1
? 6 0 25000
? 6 0 1
? 7 3 50000
? 7 3 1
? 7 0 25000
? 7 0 1
? 7 6 37500
? 7 6 25001
? 8 3 50000
...

result: