QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#325621#8209. Curly Palindromesucup-team134#WA 0ms3908kbC++173.9kb2024-02-11 18:03:022024-02-11 18:03:03

Judging History

This is the latest submission verdict.

  • [2024-02-11 18:03:03]
  • Judged
  • Verdict: WA
  • Time: 0ms
  • Memory: 3908kb
  • [2024-02-11 18:03:02]
  • Submitted

answer

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/rope>

#define ll long long
#define pb push_back
#define f first
#define s second
#define sz(x) (int)(x).size()
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define ios ios_base::sync_with_stdio(false);cin.tie(NULL)
#define ld long double
#define li __int128

using namespace std;
using namespace __gnu_pbds;
using namespace __gnu_cxx;

mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; ///find_by_order(),order_of_key()
template<int D, typename T>struct vec : public vector<vec<D - 1, T>> {template<typename... Args>vec(int n = 0, Args... args) : vector<vec<D - 1, T>>(n, vec<D - 1, T>(args...)) {}};
template<typename T>struct vec<1, T> : public vector<T> {vec(int n = 0, T val = T()) : vector<T>(n, val) {}};
template<class T1,class T2> ostream& operator<<(ostream& os, const pair<T1,T2>& a) { os << '{' << a.f << ", " << a.s << '}'; return os; }
template<class T> ostream& operator<<(ostream& os, const vector<T>& a){os << '{';for(int i=0;i<sz(a);i++){if(i>0&&i<sz(a))os << ", ";os << a[i];}os<<'}';return os;}
template<class T> ostream& operator<<(ostream& os, const deque<T>& a){os << '{';for(int i=0;i<sz(a);i++){if(i>0&&i<sz(a))os << ", ";os << a[i];}os<<'}';return os;}
template<class T> ostream& operator<<(ostream& os, const set<T>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const set<T,greater<T> >& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const multiset<T>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const multiset<T,greater<T> >& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T1,class T2> ostream& operator<<(ostream& os, const map<T1,T2>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
int ri(){int x;scanf("%i",&x);return x;}
void rd(int&x){scanf("%i",&x);}
void rd(long long&x){scanf("%lld",&x);}
void rd(double&x){scanf("%lf",&x);}
void rd(long double&x){scanf("%Lf",&x);}
void rd(string&x){cin>>x;}
void rd(char*x){scanf("%s",x);}
template<typename T1,typename T2>void rd(pair<T1,T2>&x){rd(x.first);rd(x.second);}
template<typename T>void rd(vector<T>&x){for(T&p:x)rd(p);}
template<typename C,typename...T>void rd(C&a,T&...args){rd(a);rd(args...);}
//istream& operator>>(istream& is,__int128& a){string s;is>>s;a=0;int i=0;bool neg=false;if(s[0]=='-')neg=true,i++;for(;i<s.size();i++)a=a*10+s[i]-'0';if(neg)a*=-1;return is;}
//ostream& operator<<(ostream& os,__int128 a){bool neg=false;if(a<0)neg=true,a*=-1;ll high=(a/(__int128)1e18);ll low=(a-(__int128)1e18*high);string res;if(neg)res+='-';if(high>0){res+=to_string(high);string temp=to_string(low);res+=string(18-temp.size(),'0');res+=temp;}else res+=to_string(low);os<<res;return os;}

int main()
{
	int n;
	cin >> n;
	vector<pair<int,int>> p;
	vector<char> c;
	for(int i=0;i<n;i++){
		int x,y;
		string s;
		cin >> x >> y >> s;
		p.pb({x,y});
		c.pb(s[0]);
	}
	if(n==1){
		printf("1\n");
		return 0;
	}
	for(int i=0;i<n;i++){
		for(int j=0;j<i;j++){
			for(int k=0;k<j;k++){
				if(c[i]==c[j]||c[i]==c[k]||c[j]==c[k]){
					pair<int,int> a={p[i].f-p[k].f,p[i].s-p[k].s};
					pair<int,int> b={p[j].f-p[k].f,p[j].s-p[k].s};
					ll cr=(ll)a.f*b.s-(ll)a.s*b.f;
					if(cr!=0){
						printf("Infinity\n");
						return 0;
					}
				}
			}
		}
	}
	printf("2\n");
	return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3908kb

input:

4
0 0 o
1 1 c
2 2 p
3 3 c

output:

2

result:

ok single line: '2'

Test #2:

score: 0
Accepted
time: 0ms
memory: 3684kb

input:

3
2 3 e
3 2 e
8 9 e

output:

Infinity

result:

ok single line: 'Infinity'

Test #3:

score: -100
Wrong Answer
time: 0ms
memory: 3676kb

input:

3
0 0 p
1 1 c
2 2 o

output:

2

result:

wrong answer 1st lines differ - expected: '1', found: '2'