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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#32223 | #2571. Aidana and Pita | RobeZH# | WA | 1979ms | 136848kb | C++ | 1.5kb | 2022-05-18 06:09:35 | 2022-05-18 06:09:36 |
Judging History
answer
#include<bits/stdc++.h>
#define rep(i,n) for(int i=1;i<=n;++i)
#define st first
#define nd second
using namespace std;
typedef long long ll;
typedef pair<int,int> pr;
const int N=30;
int a[N],n;
int dp[1<<25],to[1<<25],iss[1<<25],sum=0;
int ot[N];
int main() {
for(int i=0;i<25;++i)iss[1<<i]=i;
//scanf("%d",&n);
n=25;
rep(i,n){
//scanf("%d",a+i);
a[i]=i*i;
sum+=a[i];
}
ot[n]=3;
--n;
for(int mk=1;mk<1<<n;++mk){
dp[mk]=sum;
for(int tmp=mk,j=iss[tmp&-tmp];tmp;tmp-=1<<j,j=iss[tmp&-tmp]){
int now=dp[mk-(1<<j)];
if(now<0)now+=a[j+1];else now-=a[j+1];
if(abs(now)<abs(dp[mk])){
dp[mk]=now;
to[mk]=j;
}
}
}
int ans=sum+1,is=0;
for(int mk=0;mk<1<<n;++mk){
int s=0;
for(int tmp=mk,j=iss[tmp&-tmp];tmp;tmp-=1<<j,j=iss[tmp&-tmp]){
s+=a[j+1];
}
int u=s+a[n+1],v=(sum-s-dp[(1<<n)-1-mk])/2,w=(sum-s+dp[(1<<n)-1-mk])/2;
int nw=max(abs(u-v),max(abs(v-w),abs(w-u)));
if(ans>nw){
ans=nw;
is=(1<<n)-1-mk;
}
}
for(int j=0;j<n;++j)if(!(is&(1<<j)))ot[j+1]=3;
while(is>0){
int nxt=is-(1<<to[is]);
ot[to[is]+1]=(dp[nxt]<0?1:2);
is=nxt;
}
//printf("%d\n",ans);
rep(i,n+1)printf("%d%c",ot[i]," \n"[i==n+1]);
return 0;
}
/*
20
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
*/
詳細信息
Test #1:
score: 0
Wrong Answer
time: 1979ms
memory: 136848kb
input:
5 2 3 1 4 2
output:
1 3 1 3 1 2 3 3 3 3 3 3 3 3 3 3 1 2 2 1 2 1 1 2 3
result:
wrong answer expected 0, found 7