// Judges with GCC >= 12 only needs Ofast
// #pragma GCC optimize("O3,no-stack-protector,fast-math,unroll-loops,tree-vectorize")
// MLE optimization
// #pragma GCC optimize("conserve-stack")
// Old judges
// #pragma GCC target("sse4.2,popcnt,lzcnt,abm,mmx,fma,bmi,bmi2")
// New judges. Test with assert(__builtin_cpu_supports("avx2"));
// #pragma GCC target("avx2,popcnt,lzcnt,abm,bmi,bmi2,fma,tune=native")
// Atcoder
// #pragma GCC target("avx2,popcnt,lzcnt,abm,bmi,bmi2,fma")
/*
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> ordered_set;
- insert(x),erase(x)
- find_by_order(k): return iterator to the k-th smallest element
- order_of_key(x): the number of elements that are strictly smaller
*/
#include<bits/stdc++.h>
using namespace std;
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
uniform_real_distribution<> pp(0.0,1.0);
#define int long long
#define ld long double
#define pii pair<int,int>
#define piii pair<int,pii>
#define mpp make_pair
#define fi first
#define se second
const int inf=1e18;
const int mod=1000;
const int maxn=200005;
const int bl=650;
const int maxs=655;
const int maxm=200005;
const int maxq=1000005;
const int maxl=25;
const int maxa=1000000;
const int root=3;
int power(int a,int n){
    int res=1;
    while(n){
        if(n&1) res=res*a%mod;
        a=a*a%mod;n>>=1;
    }
    return res;
}
const int iroot=power(3,mod-2);
const int base=101;

int p[1005];
int f(int x){
    return x%30;
}

void solve(){
    string s;cin >> s;
    p[0]=1;
    for(int i=1;i<1000;i++) p[i]=p[i-1]*base%30;
    if(s!="Clara"){
        string res;
        for(int i=0;i<100;i++){
            string x;cin >> x;
            vector<int> d(30,0);
            for(int j=0;j<1000;j++) d[f(j)]^=(x[j]-'0');
            for(int j=0;j<30;j++) res=res+char(d[j]+'0');
        }
        cout << res << '\n';
    }
    else{
        string A,B;cin >> A >> B;
        vector<int> a(100,0),b(100,0);
        for(int i=0;i<100;i++){
            for(int j=29;j>=0;j--){
                a[i]=a[i]<<1|(A[i*30+j]-'0');
                b[i]=b[i]<<1|(B[i*30+j]-'0');
            }
        }
        for(int i=0;i<100;i++){
            string x;cin >> x;
            int num=0;
            for(int j=0;j<1000;j++) num=num^((x[j]-'0')<<f(j));
            int px=-1,py=-1;
            for(int j=0;j<100;j++) for(int k=0;k<100;k++) if(!(a[j]^b[k]^num)) px=j,py=k;
            cout << px+1 << ' ' << py+1 << '\n';
        }
    }
}

signed main(){
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);cout.tie(NULL);
    int test=1;//cin >> test;
    while(test--) solve();
}