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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#320472#8212. Football in Osijekucup-team088#RE 6ms12072kbC++177.3kb2024-02-03 17:10:432024-02-03 17:10:44

Judging History

你现在查看的是最新测评结果

  • [2024-02-03 17:10:44]
  • 评测
  • 测评结果:RE
  • 用时:6ms
  • 内存:12072kb
  • [2024-02-03 17:10:43]
  • 提交

answer

#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include<iostream>
#include<string>
#include<cstdio>
#include<vector>
#include<cmath>
#include<algorithm>
#include<functional>
#include<iomanip>
#include<queue>
#include<ciso646>
#include<random>
#include<map>
#include<set>
#include<bitset>
#include<stack>
#include<unordered_map>
#include<unordered_set>
#include<utility>
#include<cassert>
#include<complex>
#include<numeric>
#include<array>
#include<chrono>
using namespace std;

//#define int long long
typedef long long ll;

typedef unsigned long long ul;
typedef unsigned int ui;
//ll mod = 1;
//constexpr ll mod = 998244353;
constexpr ll mod = 1000000007;
const int mod17 = 1000000007;
const ll INF = (ll)mod17 * mod17;
typedef pair<int, int>P;

#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define Rep(i,sta,n) for(int i=sta;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define per1(i,n) for(int i=n;i>=1;i--)
#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)
#define all(v) (v).begin(),(v).end()
typedef pair<ll, ll> LP;

using ld = double;
typedef pair<ld, ld> LDP;
const ld eps = 1e-10;
const ld pi = acosl(-1.0);

template<typename T>
void chmin(T& a, T b) {
	a = min(a, b);
}
template<typename T>
void chmax(T& a, T b) {
	a = max(a, b);
}
template<typename T>
vector<T> vmerge(vector<T>& a, vector<T>& b) {
	vector<T> res;
	int ida = 0, idb = 0;
	while (ida < a.size() || idb < b.size()) {
		if (idb == b.size()) {
			res.push_back(a[ida]); ida++;
		}
		else if (ida == a.size()) {
			res.push_back(b[idb]); idb++;
		}
		else {
			if (a[ida] < b[idb]) {
				res.push_back(a[ida]); ida++;
			}
			else {
				res.push_back(b[idb]); idb++;
			}
		}
	}
	return res;
}
template<typename T>
void cinarray(vector<T>& v) {
	rep(i, v.size())cin >> v[i];
}
template<typename T>
void coutarray(vector<T>& v) {
	rep(i, v.size()) {
		if (i > 0)cout << " "; cout << v[i];
	}
	cout << "\n";
}
ll mod_pow(ll x, ll n, ll m = mod) {
	if (n < 0) {
		ll res = mod_pow(x, -n, m);
		return mod_pow(res, m - 2, m);
	}
	if (abs(x) >= m)x %= m;
	if (x < 0)x += m;
	//if (x == 0)return 0;
	ll res = 1;
	while (n) {
		if (n & 1)res = res * x % m;
		x = x * x % m; n >>= 1;
	}
	return res;
}
//mod should be <2^31
struct modint {
	int n;
	modint() :n(0) { ; }
	modint(ll m) {
		if (m < 0 || mod <= m) {
			m %= mod; if (m < 0)m += mod;
		}
		n = m;
	}
	operator int() { return n; }
};
bool operator==(modint a, modint b) { return a.n == b.n; }
bool operator<(modint a, modint b) { return a.n < b.n; }
modint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= (int)mod; return a; }
modint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += (int)mod; return a; }
modint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }
modint operator+(modint a, modint b) { return a += b; }
modint operator-(modint a, modint b) { return a -= b; }
modint operator*(modint a, modint b) { return a *= b; }
modint operator^(modint a, ll n) {
	if (n == 0)return modint(1);
	modint res = (a * a) ^ (n / 2);
	if (n % 2)res = res * a;
	return res;
}

ll inv(ll a, ll p) {
	return (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);
}
modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }
modint operator/=(modint& a, modint b) { a = a / b; return a; }
const int max_n = 1 << 20;
modint fact[max_n], factinv[max_n];
void init_f() {
	fact[0] = modint(1);
	for (int i = 0; i < max_n - 1; i++) {
		fact[i + 1] = fact[i] * modint(i + 1);
	}
	factinv[max_n - 1] = modint(1) / fact[max_n - 1];
	for (int i = max_n - 2; i >= 0; i--) {
		factinv[i] = factinv[i + 1] * modint(i + 1);
	}
}
modint comb(int a, int b) {
	if (a < 0 || b < 0 || a < b)return 0;
	return fact[a] * factinv[b] * factinv[a - b];
}
modint combP(int a, int b) {
	if (a < 0 || b < 0 || a < b)return 0;
	return fact[a] * factinv[a - b];
}

ll gcd(ll a, ll b) {
	a = abs(a); b = abs(b);
	if (a < b)swap(a, b);
	while (b) {
		ll r = a % b; a = b; b = r;
	}
	return a;
}
template<typename T>
void addv(vector<T>& v, int loc, T val) {
	if (loc >= v.size())v.resize(loc + 1, 0);
	v[loc] += val;
}
/*const int mn = 2000005;
bool isp[mn];
vector<int> ps;
void init() {
	fill(isp + 2, isp + mn, true);
	for (int i = 2; i < mn; i++) {
		if (!isp[i])continue;
		ps.push_back(i);
		for (int j = 2 * i; j < mn; j += i) {
			isp[j] = false;
		}
	}
}*/

//[,val)
template<typename T>
auto prev_itr(set<T>& st, T val) {
	auto res = st.lower_bound(val);
	if (res == st.begin())return st.end();
	res--; return res;
}

//[val,)
template<typename T>
auto next_itr(set<T>& st, T val) {
	auto res = st.lower_bound(val);
	return res;
}
using mP = pair<modint, modint>;
mP operator+(mP a, mP b) {
	return { a.first + b.first,a.second + b.second };
}
mP operator+=(mP& a, mP b) {
	a = a + b; return a;
}
mP operator-(mP a, mP b) {
	return { a.first - b.first,a.second - b.second };
}
mP operator-=(mP& a, mP b) {
	a = a - b; return a;
}
LP operator+(LP a, LP b) {
	return { a.first + b.first,a.second + b.second };
}
LP operator+=(LP& a, LP b) {
	a = a + b; return a;
}
LP operator-(LP a, LP b) {
	return { a.first - b.first,a.second - b.second };
}
LP operator-=(LP& a, LP b) {
	a = a - b; return a;
}

mt19937 mt(time(0));

const string drul = "DRUL";
string senw = "SENW";
//DRUL,or SENW
//int dx[4] = { 1,0,-1,0 };
//int dy[4] = { 0,1,0,-1 };

//------------------------------------



void solve() {
	int n; cin >> n;
	vector<int> a(n);
	rep(i, n) {
		cin >> a[i]; a[i]--;
	}
	vector<vector<int>> G(n);
	vector<int> cnt(n);
	queue<int> que;
	rep(i, n) {
		cnt[a[i]]++;
	}
	rep(i, n)if (cnt[i] == 0)que.push(i);
	vector<bool> isloop(n,true);
	while (!que.empty()) {
		int id = que.front(); que.pop();
		isloop[id] = false;
		cnt[a[id]]--;
		G[a[id]].push_back(id);
		if (cnt[a[id]] == 0) {
			que.push(a[id]);
		}
	}
	vector<bool> can(n + 1);
	vector<int> ads;
	vector<bool> used(n);
	function<int(int,int)> dfs = [&](int id,int v) {
		can[v] = true;
		int ma = 0;
		for (int to : G[id]) {
			int nex = dfs(to,v+1);
			if (ma >= nex)ads.push_back(nex);
			else ma = nex;
		}
		return ma + 1;
	};
	rep(i, n) {
		if (used[i])continue;
		if (!isloop[i])continue;
		vector<int> ids;
		int cur = i;
		while (!used[cur]) {
			ids.push_back(cur);
			used[cur] = true;
			cur = a[cur];
		}
		vector<int> vs;
		for (int id : ids) {
			int v = dfs(id,ids.size()); v--;
			vs.push_back(v);
		}
		sort(all(vs), greater<int>());
		ads.push_back(vs[0] + ids.size());
		for (int i = 1; i < vs.size();i++)ads.push_back(vs[i]);
	}
	int ma = 0;
	rep(i, n + 1)if (can[i])chmax(ma, i);
	vector<int> ans(n+1);
	sort(all(ads), greater<int>());
	assert(ma == ads[0]);
	rep1(i, ma) {
		if (can[i])ans[i] = 0;
		else ans[i] = 1;
	}
	int le = ads[0];
	for (int i = 1; i < ads.size(); i++) {
		for (int j = le + 1; j <= le + ads[i]; j++) {
			ans[j] = i;
		}
		le += ads[i];
	}
	assert(le == n);
	rep(i, n)assert(used[i] || !isloop[i]);
	ans.erase(ans.begin());
	coutarray(ans);
}




signed main() {
	ios::sync_with_stdio(false);
	cin.tie(0);
	//cout << fixed<<setprecision(10);
	//init_f();
	//init();
	//while(true)
	//expr();
	//int t; cin >> t; rep(i, t)
	solve();
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 5ms
memory: 11884kb

input:

5
2 3 1 3 5

output:

0 1 0 0 1

result:

ok 5 number(s): "0 1 0 0 1"

Test #2:

score: 0
Accepted
time: 0ms
memory: 12072kb

input:

1
1

output:

0

result:

ok 1 number(s): "0"

Test #3:

score: 0
Accepted
time: 2ms
memory: 11820kb

input:

2
2 2

output:

0 0

result:

ok 2 number(s): "0 0"

Test #4:

score: 0
Accepted
time: 0ms
memory: 11864kb

input:

10
4 7 2 8 4 3 4 9 7 3

output:

1 1 1 0 0 0 0 1 2 3

result:

ok 10 numbers

Test #5:

score: 0
Accepted
time: 6ms
memory: 11872kb

input:

10
8 7 4 8 3 4 2 5 3 7

output:

1 0 0 0 0 1 1 1 2 3

result:

ok 10 numbers

Test #6:

score: -100
Runtime Error

input:

10
7 1 4 1 6 1 1 10 5 7

output:


result: