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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#316130#8129. Binary Sequenceucup-team134#AC ✓231ms75872kbC++174.1kb2024-01-27 17:38:062024-01-27 17:38:07

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你现在查看的是最新测评结果

  • [2024-01-27 17:38:07]
  • 评测
  • 测评结果:AC
  • 用时:231ms
  • 内存:75872kb
  • [2024-01-27 17:38:06]
  • 提交

answer

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/rope>

#define ll long long
#define pb push_back
#define f first
#define s second
#define sz(x) (int)(x).size()
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define ios ios_base::sync_with_stdio(false);cin.tie(NULL)
#define ld long double
#define li __int128

using namespace std;
using namespace __gnu_pbds;
using namespace __gnu_cxx;

mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; ///find_by_order(),order_of_key()
template<int D, typename T>struct vec : public vector<vec<D - 1, T>> {template<typename... Args>vec(int n = 0, Args... args) : vector<vec<D - 1, T>>(n, vec<D - 1, T>(args...)) {}};
template<typename T>struct vec<1, T> : public vector<T> {vec(int n = 0, T val = T()) : vector<T>(n, val) {}};
template<class T1,class T2> ostream& operator<<(ostream& os, const pair<T1,T2>& a) { os << '{' << a.f << ", " << a.s << '}'; return os; }
template<class T> ostream& operator<<(ostream& os, const vector<T>& a){os << '{';for(int i=0;i<sz(a);i++){if(i>0&&i<sz(a))os << ", ";os << a[i];}os<<'}';return os;}
template<class T> ostream& operator<<(ostream& os, const deque<T>& a){os << '{';for(int i=0;i<sz(a);i++){if(i>0&&i<sz(a))os << ", ";os << a[i];}os<<'}';return os;}
template<class T> ostream& operator<<(ostream& os, const set<T>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const set<T,greater<T> >& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const multiset<T>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const multiset<T,greater<T> >& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T1,class T2> ostream& operator<<(ostream& os, const map<T1,T2>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
int ri(){int x;scanf("%i",&x);return x;}
void rd(int&x){scanf("%i",&x);}
void rd(long long&x){scanf("%lld",&x);}
void rd(double&x){scanf("%lf",&x);}
void rd(long double&x){scanf("%Lf",&x);}
void rd(string&x){cin>>x;}
void rd(char*x){scanf("%s",x);}
template<typename T1,typename T2>void rd(pair<T1,T2>&x){rd(x.first);rd(x.second);}
template<typename T>void rd(vector<T>&x){for(T&p:x)rd(p);}
template<typename C,typename...T>void rd(C&a,T&...args){rd(a);rd(args...);}
//istream& operator>>(istream& is,__int128& a){string s;is>>s;a=0;int i=0;bool neg=false;if(s[0]=='-')neg=true,i++;for(;i<s.size();i++)a=a*10+s[i]-'0';if(neg)a*=-1;return is;}
//ostream& operator<<(ostream& os,__int128 a){bool neg=false;if(a<0)neg=true,a*=-1;ll high=(a/(__int128)1e18);ll low=(a-(__int128)1e18*high);string res;if(neg)res+='-';if(high>0){res+=to_string(high);string temp=to_string(low);res+=string(18-temp.size(),'0');res+=temp;}else res+=to_string(low);os<<res;return os;}

const int N=1e6+5,L=40;
vector<bool> bin[N];
vector<bool> ans[L];
vector<bool> nxt(vector<bool> a){
	vector<bool> ans;
	ans.reserve(sz(a));
	int last=0,cnt=0;
	for(auto p:a){
		if(p==last){
		}
		else{
			if(cnt!=0){
				for(auto p:bin[cnt]){
					ans.pb(p);
				}
				ans.pb(last);
			}
			last=p;
			cnt=0;
		}
		cnt++;
	}
	if(cnt!=0){
		for(auto p:bin[cnt]){
			ans.pb(p);
		}
		ans.pb(last);
	}
	return ans;
}
int main()
{
	for(int i=1;i<N;i++){
		int tr=i;
		while(tr){
			bin[i].pb(tr&1);
			tr/=2;
		}
		reverse(all(bin[i]));
	}
	vector<bool> tr={1};
	ans[1]={1};
	for(int i=2;i<L;i++){
		ans[i]=nxt(ans[i-1]);
	}
	int t=ri();
	while(t--){
		ll n,m;
		rd(n,m);
		if(n>=L){
			ll diff=(n-(L-1));
			if(diff&1)n=L-2;
			else n=L-1;
		}
		if(m>=sz(ans[n])){
			printf("0\n");
		}
		else{
			printf("%i\n",ans[n][sz(ans[n])-1-m]?1:0);
		}
	}
	return 0;
}

这程序好像有点Bug,我给组数据试试?

详细

Test #1:

score: 100
Accepted
time: 205ms
memory: 75872kb

input:

10
4 0
4 1
4 2
4 3
4 4
4 5
4 6
6 3
6 7
118999881999119725 3

output:

1
1
0
1
1
1
0
1
1
0

result:

ok 10 numbers

Test #2:

score: 0
Accepted
time: 201ms
memory: 75716kb

input:

10
28 69772
10 7908
4 3198
4 85913
14 52729
3 20445
9 88912
17 23743
25 37356
2 97697

output:

0
0
0
0
0
0
0
0
0
0

result:

ok 10 numbers

Test #3:

score: 0
Accepted
time: 214ms
memory: 75740kb

input:

100
29 110358
18 13645
18 590344
36 550462
11 133055
8 769352
11 265432
7 158530
12 29189
2 830361
11 584395
31 693707
7 879812
19 25069
21 616926
3 85158
31 675739
17 118385
24 315535
29 59615
10 33445
17 609235
8 738138
20 209540
4 287616
32 522302
26 959741
5 453537
27 74313
28 296289
28 857972
2...

output:

0
0
0
1
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
1
0
0
0
0
0
0
0
0
0
0
0
0
1
0
0
0
1
0
0
0
1
0
0
0
0
0
0
0
0
0
0
0
0
0
1
0
0
0
0
0
0
0
0
1
1
0
0
0
0
1
0
0
0
0
0
1
0
1
0
1
0
1
0
0
0
0
0
0
0
0
0
0
0
0
1
0
0
1
0
0

result:

ok 100 numbers

Test #4:

score: 0
Accepted
time: 231ms
memory: 75740kb

input:

100000
702433635413308636 962533
864089450531108488 538792
262747333715821506 454514
859830947243984718 105219
365621373252206174 447331
890829905503831899 507146
116987306031929573 154370
157986473366693144 364746
502917586764426513 49981
874588963478161584 594867
467219058104100510 790503
11034861...

output:

1
1
1
1
1
1
1
0
1
0
1
0
1
1
1
1
0
1
1
1
1
1
0
1
0
0
0
0
1
1
1
0
0
1
1
0
0
1
0
1
1
1
1
0
0
0
0
1
1
0
0
1
0
0
1
0
1
1
1
1
1
1
1
0
1
1
1
0
0
0
1
1
1
0
1
1
1
1
1
1
0
1
0
1
1
1
0
0
0
1
0
0
1
0
1
1
1
1
1
1
0
0
0
0
0
0
0
1
0
0
1
0
1
0
1
0
1
1
0
1
1
0
1
0
0
0
1
1
0
1
1
0
0
1
1
1
1
1
0
0
0
0
0
0
1
1
1
0
0
1
...

result:

ok 100000 numbers

Extra Test:

score: 0
Extra Test Passed