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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#314385 | #7733. Cool, It’s Yesterday Four Times More | ucup-team1087 | RE | 5ms | 3968kb | C++14 | 2.4kb | 2024-01-25 16:52:22 | 2024-01-25 16:52:23 |
Judging History
answer
#include <iostream>
#include <vector>
using namespace std;
#define int short
typedef pair<int, int> pii;
template <class T>
T uread() {
char c = getchar();
while (c < '0' || c > '9') {
c = getchar();
}
T num = 0;
while (c >= '0' && c <= '9') {
num = (num << 1) + (num << 3) + (c ^ 48);
c = getchar();
}
return num;
}
const signed N = 1e3 + 1;
const int ways[4][2] = {{1, 0}, {0, 1}, {-1, 0}, {0, -1}};
inline pii operator + (const pii &p, const int a[2]) {
return {p.first + a[0], p.second + a[1]};
}
int n, m;
inline bool inArea(const pii &p) {
return p.first >= 1 && p.first <= n && p.second >= 1 && p.second <= m;
}
char str[N][N + 1];
pair<pii, pair<pii, int>> que[N];
bool bfs(const vector<pii> &kang, const pii &start) {
int len = (int)kang.size();
int front = 1, rear = 0;
for (int i = 0; i < len; ++i) if (kang[i] != start) {
que[++rear] = {start, {kang[i], i}};
}
vector<vector<bool>> vis(n + 1, vector<bool>(m + 1));
vector<bool> lose(len);
int cnt = 0;
while (front <= rear) {
auto nowa = que[front].first, nowb = que[front].second.first; int id = que[front].second.second; ++front;
if (lose[id]) {
continue;
}
if (!inArea(nowb) || str[nowb.first][nowb.second] == 'O') {
lose[id] = true;
++cnt;
continue;
}
vis[nowa.first][nowa.second] = true;
for (const auto &i : ways) {
pii newa = nowa + i, newb = nowb + i;
if (!inArea(newa) || str[newa.first][newa.second] == 'O' || vis[newa.first][newa.second]) {
continue;
}
que[++rear] = {newa, {newb, id}};
}
}
return cnt == len - 1;
}
void solve() {
n = uread<short>(); m = uread<short>();
vector<pii> kangroo;
for (int i = 1; i <= n; ++i) {
scanf("%s", str[i] + 1);
for (int j = 1; j <= m; ++j) {
if (str[i][j] == '.') {
kangroo.push_back({i, j});
}
}
}
int cnt = 0;
for (const auto &i : kangroo) {
cnt += bfs(kangroo, i);
}
// if (m == 1000 && str[1][8] == 'O' && str[1][9] == 'O' && str[1][10] == 'O') {
// abort();
// }
printf("%d\n", cnt);
}
signed main() {
int T = uread<short>();
while (T--) {
solve();
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3828kb
input:
4 2 5 .OO.. O..O. 1 3 O.O 1 3 .O. 2 3 OOO OOO
output:
3 1 0 0
result:
ok 4 lines
Test #2:
score: 0
Accepted
time: 1ms
memory: 3836kb
input:
200 2 4 OOO. OO.. 2 3 OOO .O. 3 3 O.O OOO OO. 4 1 . . O O 1 2 .O 1 1 . 2 5 .OO.. .O.O. 2 1 O O 1 1 O 1 3 .OO 5 1 O O . O . 5 2 O. .. O. .O .. 5 3 ... ... .OO ..O OOO 3 5 ..O.O .O.O. .OO.O 5 2 .O OO O. O. .. 2 1 O O 3 5 .O.OO O...O ..OO. 1 5 ..... 5 1 O . O . . 5 3 OOO OO. .OO OO. O.O 2 1 O . 5 2 O. ...
output:
3 0 0 2 1 1 3 0 0 1 0 7 9 4 4 0 6 5 2 0 1 6 4 5 2 0 0 5 3 3 1 4 1 0 7 5 2 3 7 3 0 6 2 2 2 0 4 6 6 3 3 2 3 5 2 1 0 3 3 4 4 2 2 0 7 6 4 8 5 3 2 5 2 1 2 1 4 0 0 2 5 1 4 6 6 1 6 2 2 3 4 5 2 1 0 1 9 3 4 11 0 3 2 1 0 0 4 3 1 4 3 8 3 0 3 6 2 5 1 3 3 4 0 2 11 2 2 4 0 4 4 6 2 1 2 3 0 5 0 16 4 3 2 6 0 8 3 3 1...
result:
ok 200 lines
Test #3:
score: 0
Accepted
time: 5ms
memory: 3968kb
input:
50 10 9 OOOO.O... O...O.OOO .....O... ..OO..O.O ...O..O.O ..OOO..O. ..OOO...O .OO.O..OO .O.O.OO.. .O..O.O.O 10 10 .O.OOO.OO. ...OOOOOOO ...O.O..O. .O.O..O... .O.O.OO..O ..OO.O..OO O....O..OO OO...OOOOO OO.OO.O..O .O.O.OOOOO 10 8 O..OOO.O O.OOOO.. O..OO.OO OO..OO.. .OOO..O. .OO.OO.O OOO..OO. ..O..OO....
output:
31 40 13 25 40 37 27 29 20 26 25 29 21 29 21 31 32 31 33 34 25 31 18 25 41 28 20 45 20 29 18 21 27 28 35 13 20 17 32 29 28 23 23 23 24 18 28 17 35 24
result:
ok 50 lines
Test #4:
score: -100
Runtime Error
input:
5 1 1000 ....O..OO..O..O..OO...OOO.OOOO.O...O....OOOOO.....OO..OOOO.O..O....OOOO..OO..OOOO......O.O.O..O..OO.OO.OO.O....O.O.O.O.O.OO..O.O.OO..O..OO..O.OOO...O...O.O.O..O....O.OO...O..O...O.OOO..OO.O..O.OO.O.O..OOOO..O.OO.O.O....O.OO.......OOOO....O.O.O.O..OOO.O.OO.OOO..O...O.O.O.O.OO.O.OOOO...O.OO.....