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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#311008#5419. TrianglesyuqihaoWA 1ms3872kbC++142.0kb2024-01-21 20:51:472024-01-21 20:51:47

Judging History

你现在查看的是最新测评结果

  • [2024-01-21 20:51:47]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:3872kb
  • [2024-01-21 20:51:47]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
#define int long long
const int N=3000,cm=1e7;
struct point{
	int x,y;
	friend point operator +(point a,point b){
		return {a.x+b.x,a.y+b.y};
	}
	friend point operator *(point a,int x){
		return {a.x*x,a.y*x};
	}
	friend point operator /(point a,int x){
		return {a.x/x,a.y/x};
	}
};
struct as{
	point a,b,c;
}q[N];
int l,r,k;
signed main(){
	scanf("%lld",&k);
	if(k<8){
		printf("No");
		return 0;
	}
	printf("Yes\n");
	l=1,r=0;
	if(k%3==0){
		k-=9;
		q[++r]={{0,100},{42,70},{55,100}}; 
		q[++r]={{0,100},{70,50},{0,0}}; 
		q[++r]={{0,0},{70,50},{100,0}}; 
		q[++r]={{100,0},{70,50},{100,60}}; 
		q[++r]={{100,60},{70,75},{100,100}}; 
		q[++r]={{100,100},{55,100},{70,75}}; 
		q[++r]={{55,100},{70,75},{42,70}}; 
		q[++r]={{42,70},{70,50},{70,75}}; 
		q[++r]={{70,50},{100,60},{70,75}}; 
	}
	else if(k%3==1){
		k-=10;
		q[++r]={{0,0},{40,0},{30,18}};
		q[++r]={{30,18},{50,14},{40,0}}; 
		q[++r]={{40,0},{50,14},{60,0}}; 
		q[++r]={{60,0},{50,14},{70,18}}; 
		q[++r]={{60,0},{70,18},{100,0}}; 
		q[++r]={{30,18},{50,14},{50,30}}; 
		q[++r]={{50,30},{70,18},{50,14}}; 
		q[++r]={{0,0},{50,30},{0,100}}; 
		q[++r]={{0,100},{100,100},{50,30}}; 
		q[++r]={{100,100},{50,30},{100,0}}; 
	}
	else{
		k-=8;
		q[++r]={{0,0},{45,20},{50,0}}; 
		q[++r]={{45,20},{50,0},{55,20}}; 
		q[++r]={{50,0},{55,20},{100,0}}; 
		q[++r]={{0,0},{0,100},{45,20}}; 
		q[++r]={{0,100},{45,20},{50,100}}; 
		q[++r]={{50,100},{45,20},{55,20}}; 
		q[++r]={{50,100},{100,100},{55,20}}; 
		q[++r]={{100,100},{55,20},{100,0}}; 
	}	
	for(int i=l;i<=r;i++){
		q[i].a=q[i].a*cm,q[i].b=q[i].b*cm,q[i].c=q[i].c*cm;
	}
	while(k){
		k-=3;
		point x1=(q[l].a+q[l].b)/2,x2=(q[l].b+q[l].c)/2,x3=(q[l].a+q[l].c)/2;
		q[++r]={x1,x2,x3};
		q[++r]={x1,x2,q[l].b};
		q[++r]={x1,x2,q[l].a};
		q[++r]={x2,x3,q[l].c};
		l++;
	}
	for(int i=l;i<=r;i++){
		printf("%lld %lld %lld %lld %lld %lld\n",q[i].a.x,q[i].a.y,q[i].b.x,q[i].b.y,q[i].c.x,q[i].c.y);
	}
	return 0;
}


Details

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Test #1:

score: 100
Accepted
time: 0ms
memory: 3680kb

input:

2

output:

No

result:

ok no solution

Test #2:

score: -100
Wrong Answer
time: 1ms
memory: 3872kb

input:

24

output:

Yes
1000000000 1000000000 550000000 1000000000 700000000 750000000
550000000 1000000000 700000000 750000000 420000000 700000000
420000000 700000000 700000000 500000000 700000000 750000000
700000000 500000000 1000000000 600000000 700000000 750000000
210000000 850000000 485000000 850000000 275000000 1...

result:

wrong answer triangle 7 not acute