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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#307694#6427. Just Another Game of StonesYaremaWA 262ms90084kbC++143.5kb2024-01-19 04:05:572024-01-19 04:05:57

Judging History

你现在查看的是最新测评结果

  • [2024-01-19 04:05:57]
  • 评测
  • 测评结果:WA
  • 用时:262ms
  • 内存:90084kb
  • [2024-01-19 04:05:57]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

#define FOR(i, a, b) for(int i = (a); i < (b); i++)
#define RFOR(i, a, b) for(int i = (a) - 1; i >= (b); i--)
#define SZ(a) int(a.size())
#define ALL(a) a.begin(), a.end()
#define PB push_back
#define MP make_pair
#define F first
#define S second

typedef long long LL;
typedef vector<int> VI;
typedef pair<int, int> PII;
typedef double db;

const int LOG = 31;
const LL INF = 1ll << 47;

struct Node
{
	LL mn, cnt, mn2, x, ps;
	int c[LOG];
	
	Node()
	{
		mn = INF;
		cnt = 0;
		mn2 = INF;
		x = 0;
		ps = -1;
		fill(c, c + LOG, 0);
	}
	
	void out()
	{
		cerr << mn << ' ' << cnt << ' ' << mn2 << ' ' << x << '\n';
		FOR (j, 0, 4)
			cerr << c[j] << ' ';
		cerr << '\n';		
	}
};

struct Segtree
{
	
	int n;
	vector<Node> t;
	
	void init(int _n)
	{
		n = 1;
		while (n < _n) n *= 2;
		t.resize(2 * n + 1);
	}
	
	Node combine(Node a, Node b)
	{
		Node res;
		if (a.mn == b.mn)
		{
			res.mn = a.mn;
			res.cnt = a.cnt + b.cnt;
			res.mn2 = min(a.mn2, b.mn2);
		}
		else
		{
			res.mn = min(a.mn, b.mn);
			res.cnt = a.mn > b.mn ? a.cnt : b.cnt;
			res.mn2 = min({a.mn2, b.mn2, max(a.mn, b.mn)});
		}
		res.x = a.x ^ b.x;
		FOR (i, 0, LOG)
			res.c[i] = a.c[i] + b.c[i];
		return res;
	}
	
	void build(int v, int tl, int tr, const VI& a)
	{
		if (tl + 1 == tr)
		{
			if (tl < SZ(a))
			{
				t[v].mn = a[tl];
				t[v].cnt = 1;
				t[v].mn2 = INF;
				t[v].x = a[tl];
				t[v].ps = -1;
				FOR (i, 0, LOG) t[v].c[i] = (a[tl] >> i) & 1;
			}
			return;
		}
		int tm = (tl + tr) / 2;
		build(v * 2 + 1, tl, tm, a);
		build(v * 2 + 2, tm, tr, a);
		t[v] = combine(t[v * 2 + 1], t[v * 2 + 2]);
	}
	
	void build(const VI& a)
	{
		init(SZ(a));
		build(0, 0, n, a);
	}
	
	Node query(int v, int tl, int tr, int l, int r)
	{
		if (l >= tr || tl >= r)
			return {};
		if (l <= tl && tr <= r)
			return t[v];
		int tm = (tl + tr) / 2;
		return combine(query(v * 2 + 1, tl, tm, l, r),
					   query(v * 2 + 2, tm, tr, l, r));
	}
	
	Node query(int l, int r)
	{
		return query(0, 0, n, l, r);
	}
	
	void push(int v)
	{
		if (v * 2 + 1 >= SZ(t) || t[v].ps == -1)
		{
			t[v].ps = -1;
			return;
		}
		up(t[v * 2 + 1], t[v].ps);
		up(t[v * 2 + 2], t[v].ps);
		t[v].ps = -1;
	}
	
	void up(Node& nd, int x)
	{		
		if (nd.cnt & 1)
			nd.x ^= nd.mn ^ x;
		FOR (i, 0, LOG)
		{
			nd.c[i] -= (nd.mn >> i) & 1;
			nd.c[i] += (x >> i) & 1;
		}
		nd.mn = x;
		nd.ps = max(nd.ps, LL(x));
	}
	
	void upd(int v, int tl, int tr, int l, int r, int x)
	{
		//cerr << v << ' ' << tl << ' ' << tr << ' ' << l << ' ' << r << ' ' << t[v].mn << ' ' << t[v].mn2 << '\n';
		if (l >= tr || tl >= r || t[v].mn >= x)
			return;
		if (l <= tl && tr <= r && t[v].mn2 > x)
		{
			up(t[v], x);
			return;
		}
		push(v);
		int tm = (tl + tr) / 2;
		upd(v * 2 + 1, tl, tm, l, r, x);
		upd(v * 2 + 2, tm, tr, l, r, x);
		t[v] = combine(t[v * 2 + 1], t[v * 2 + 2]);
	}
	
	void upd(int l, int r, int x)
	{
		upd(0, 0, n, l, r, x);
	}
};

int main()
{
	ios::sync_with_stdio(0); 
	cin.tie(0);
	cout << fixed << setprecision(15);
	
	int n, m;
	cin >> n >> m;
	VI a(n);
	FOR (i, 0, n) cin >> a[i];
	Segtree st;
	st.build(a);
	FOR (i, 0, m)
	{
		int t, l, r, x;
		cin >> t >> l >> r >> x;
		l--;
		if (t == 1)
		{
			st.upd(l, r, x);
		}
		else
		{
			auto nd = st.query(l, r);
			x ^= nd.x;
			if (x == 0)
				cout << 0 << '\n';
			else
			{
				int bt = 31 - __builtin_clz(x);
				cout << nd.c[bt] << '\n';
			}
		}
	}
	
	return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3648kb

input:

5 4
1 2 1 4 1
2 1 3 1
1 2 4 3
2 2 4 4
2 1 4 4

output:

1
0
3

result:

ok 3 number(s): "1 0 3"

Test #2:

score: -100
Wrong Answer
time: 262ms
memory: 90084kb

input:

200000 200000
962352030 173642520 1008864183 74920228 684681800 500911321 1001441054 257633652 185843534 59168654 317689197 731348417 123888883 708119712 340055368 876566011 980078202 969174443 814012870 715639041 596932238 173757742 314504576 1045746913 740811577 570187156 999816627 12441059 122507...

output:

38888
57352
46658
19708
34617
128598
4974
754
16086
45065
14051
12263
33399
5151
41869
21116
95046
6968
64611
737
30905
25031
145793
17042
73757
56260
5666
91773
49140
20627
31645
9810
36613
93750
183088
39224
1366
6067
13240
25369
9041
27588
2410
104767
89719
52220
118468
162689
94569
144104
15269
...

result:

wrong answer 1st numbers differ - expected: '38889', found: '38888'