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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#307494#8005. Crossing the Borderucup_team_qiuly#WA 37ms9112kbC++143.1kb2024-01-18 18:33:162024-01-18 18:33:17

Judging History

你现在查看的是最新测评结果

  • [2024-01-18 18:33:17]
  • 评测
  • 测评结果:WA
  • 用时:37ms
  • 内存:9112kb
  • [2024-01-18 18:33:16]
  • 提交

answer

// 
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define debug(...) fprintf (stderr, __VA_ARGS__)

#define lep(i, l, r) for (int i = (l), i##_end = (r); i <= i##_end; ++ i)
#define rep(i, r, l) for (int i = (r), i##_end = (l); i >= i##_end; -- i)

char _c; bool _f; template <class T> inline void IN (T & x) {
	_f = 0, x = 0; while (_c = getchar (), ! isdigit (_c)) if (_c == '-') _f = 1;
	while (isdigit (_c)) x = x * 10 + _c - '0', _c = getchar (); if (_f) x = - x;
}

const int mod = 998244353;
inline int mul (int x, int y) { return 1ll * x * y % mod; }
inline int qpow (int x, int y, int r = 1) { for ( ; y; y >>= 1, x = mul (x, x)) if (y & 1) r = mul (r, x); return r; }
inline void pls (int &x, int y) { x += y; if (x >= mod) x -= mod; }
inline int add (int x, int y) { x += y; if (x >= mod) x -= mod; return x; }

const int N = 22;
const int NS = (1 << N) | 1;
const int inf = 1e9 + 7;

int n, W, w[N], sw[NS], c[N];
pair <int, int> dp[NS];

inline void trans (int m, int n) {
	auto highbit_id = [&] (int s) { return 31 - __builtin_clz (s); };
	auto highbit = [&] (int s) { return 1 << highbit_id (s); };

	vector <vector <int> > u (1 << n - m);
	lep (s, 1, (1 << n - m) - 1) {
		for (int _s = s ^ highbit (s), t = _s; ; t = (t - 1) & _s) {
			if (sw[s << m] - sw[t << m] <= W) u[t].emplace_back ( s << m );
			if (! t) break ;
		}
	}
	vector <vector <int> > v (1 << m);
	lep (s, 0, (1 << m) - 1) {
		for (int _s = s, t = _s; ; t = (t - 1) & _s) {
			if (sw[s] - sw[t] <= W) v[s].emplace_back ( t );
			if (! t) break ;
		}
	}

	lep (R, 0, (1 << n - m) - 1) {
		sort (u[R].begin (), u[R].end (), [&] (int a, int b) { return sw[a] > sw[b]; });
	}
	lep (L, 0, (1 << m) - 1) {
		sort (v[L].begin (), v[L].end (), [&] (int a, int b) { return sw[a] > sw[b]; });
	}

	auto upd = [&] (pair <int, int> & f, pair <int, int> & g) {
		if (g.first < f.first) f = g;
		else if (g.first == f.first) pls (f.second, g.second);
	};
	lep (R, 0, (1 << n - m) - 1) {
		lep (L, 0, (1 << m) - 1) {
			int sv = v[L].size (), pv = 0;
			pair <int, int> rec = { inf, 0 };

			for (auto & _R : u[R]) { // R in _R
				int lim = W - (sw[_R] - sw[R << m]);
				while (pv < sv && sw[L] - sw[v[L][pv]] <= lim) {
					upd (rec, dp[v[L][pv] | (R << m)]), ++ pv;
				}
				rec.first += c[highbit_id (_R)];
				upd (dp[L | _R], rec);
			}
		}
	}
}
signed main () {
	IN (n), IN (W);
	lep (i, 0, n - 1) IN (w[i]), IN (c[i]);

	lep (i, 0, n - 1) {
		lep (j, 1, n - 1) {
			if (c[j - 1] > c[j]) {
				swap (c[j - 1], c[j]);
				swap (w[j - 1], w[j]);
			}
		}
	}

	lep (i, 0, n - 1) sw[1 << i] = w[i];
	lep (i, 1, (1 << n) - 1) sw[i] = sw[i ^ (i & - i)] + sw[i & - i];

	lep (s, 1, (1 << n) - 1) dp[s] = { inf, 0 };
	dp[0] = { 0, 1 };
	function <void (int)> dfs = [&] (int n) {
		if (n == 1) {
			dp[1].first = c[0];
			dp[1].second = 1;
		} else {
			int m = min (n - 1, (n + 1) / 2);
			dfs (m), trans (m, n); // [0, p - 1] -> [0, n - 1]
		}
	}; dfs (n);
	printf ("%d %d\n", dp[(1 << n) - 1].first, dp[(1 << n) - 1].second);
	return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 5772kb

input:

5 5
3 5
1 4
2 3
2 2
2 1

output:

9 4

result:

ok 2 number(s): "9 4"

Test #2:

score: -100
Wrong Answer
time: 37ms
memory: 9112kb

input:

18 10000000
956231 904623
1692946 1796774
1081323 1170319
3218792 2542661
3183376 3037270
1869132 1442561
35436 35018
1564635 1939950
1847344 2006043
755870 899310
1671882 2057413
1369264 1338951
3132483 3504034
2056224 1825640
1840949 1562071
1514040 1405352
2300821 2421801
2466540 3004920

output:

9705895 5

result:

wrong answer 1st numbers differ - expected: '9391997', found: '9705895'