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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#306325#5434. Binary SubstringsNemanjaSo2005WA 6ms33952kbC++144.0kb2024-01-16 17:20:562024-01-16 17:20:57

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你现在查看的是最新测评结果

  • [2024-01-16 17:20:57]
  • 评测
  • 测评结果:WA
  • 用时:6ms
  • 内存:33952kb
  • [2024-01-16 17:20:56]
  • 提交

answer

#include<bits/stdc++.h>
#define ll long long
#define int long long
using namespace std;
int N,M,K;
const int maxn=(1<<20)+5;
vector<int> graf[maxn];
int perm[maxn],sleduje[maxn];
bool bio[maxn],uzmi[maxn];
priority_queue<pair<int,int>> PQ;
void getcycle(int x){
   if(bio[x])
      return;
   int gde=x,s=0;
   //cout<<"PRATIM "<<gde<<endl;
   do {
      s++;
      bio[gde]=true;
    //  cout<<gde<<endl;
      gde=perm[gde];
   } while(gde!=x);
  // cout<<"CIKLUS "<<s<<" "<<x<<endl;
   PQ.push({s,x});
}
int count_substrings(string x) {
    unordered_set<string> substrings;

    // Iterate over all substrings
    for (int i = 0; i < x.length(); ++i) {
        string substring = "";
        for (int j = i; j < x.length(); ++j) {
            substring.push_back(x[j]);
            substrings.insert(substring);
        }
    }

    // Return the count of distinct substrings
    return substrings.size();
}

void napravi(int k){
   M=1<<(k-1);
   for(int i=0;i<(1<<(k));i++){
      int a=i>>1;
      int b=i&((1<<(k-1))-1);
      graf[a].push_back(b);
   }
}
vector<int> V,R;
void poperm(int gde){
   R.push_back(gde);
   if(perm[gde]==0)
      return;
   int p=perm[gde];
   perm[gde]=0;
   poperm(p);
}
void euler(int gde){
   while(graf[gde].size()){
      int ko=graf[gde].back();
      graf[gde].pop_back();
      euler(ko);
   }
   V.push_back(gde);
}
void pisivektor(vector<int> V){
   for(int i=0;i<V.size();i++)
      cout<<V[i]<<" ";
   cout<<endl;
}
signed main(){
   cin>>N;
   if(N==1){
      cout<<"0\n";
      return 0;
   }
   if(N==2){
      cout<<"01\n";
      return 0;
   }
   if(N==3){
      cout<<"010\n";
      return 0;
   }
   if(N==4){
      cout<<"1001\n";
      return 0;
   }
   for(int i=0;i<=20;i++){
      if((1<<i)+i-1<=N)
         K=i;
   }
   //cout<<"DUZINA JE "<<K<<endl;
   napravi(K);
   euler(0);
   reverse(V.begin(),V.end());

   string poc="";
   if(((1<<(K))+K-1)!=N){
      vector<int> B;
      for(int i=1;i<V.size();i++)
         B.push_back((V[i-1]<<1) + (V[i]&1));
/*
      cout<<"NIZ B"<<endl;
      pisivektor(B);*/

      B.push_back(B[0]);
      for(int i=0;i+1<B.size();i++)
         perm[B[i]]=B[i+1]^1;
      for(int i=0;i+1<B.size();i++)
         sleduje[B[i]]=B[i+1];
/*
      cout<<"PERM:"<<endl;
      for(int i=0;i<B.size();i++)
         cout<<perm[i]<<" ";
      cout<<endl;

      cout<<"SLEDUJE:"<<endl;
      for(int i=0;i<B.size();i++)
         cout<<sleduje[i]<<" ";
      cout<<endl;*/


      for(int i=0;i+1<B.size();i++)
         getcycle(B[i]);

      int dod=N-((1<<K)+K-1);
     // cout<<"DOD JE "<<dod<<endl;
      vector<pair<int,int>> odbac;
      while(PQ.size()){
         if(dod==0)
            break;
         if(PQ.top().first>dod){
            odbac.push_back(PQ.top());
            PQ.pop();
         }
         else{
            dod-=PQ.top().first;
            uzmi[PQ.top().second]=true;
            PQ.pop();
         }
      }
      int poc=0;
      if(odbac.size() and dod!=0){
         poc=sleduje[odbac[0].second];
         uzmi[odbac[0].second]=true;
      }
    /*  cout<<"POCETAK JE "<<poc<<endl;
      cout<<"UZIMAM:"<<endl;
      for(int i=0;i<B.size();i++)
         cout<<uzmi[i]<<" ";
      cout<<endl;*/

      for(int i=(1<<K);i>=2;i>>=1)
         R.push_back((i&poc)>=1);
      for(int it=1;it<B.size();it++){
         if(uzmi[poc])
            poperm(poc);
         else
            R.push_back(poc);
         poc=sleduje[poc];
      }/*
      cout<<"CEO R je "<<endl;
      for(int i=0;i<R.size();i++)
         cout<<R[i]<<" ";
      cout<<endl;*/
   }
   else{
      //cout<<"OVAKAV"<<endl;
      for(int i=1;i<K;i++)
         cout<<"0";
      for(int i=1;i<V.size();i++)
         cout<<(V[i]&1);
      cout<<endl;
      return 0;
   }
   string X;
   for(int i=0;i<N;i++)
      X.push_back('0'+(R[i]&1));
   cout<<X<<"\n";
 //  cout<<count_substrings(X)<<endl;
   return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 28352kb

input:

2

output:

01

result:

ok meet maximum 3

Test #2:

score: 0
Accepted
time: 3ms
memory: 28912kb

input:

5

output:

01100

result:

ok meet maximum 12

Test #3:

score: 0
Accepted
time: 6ms
memory: 28828kb

input:

1

output:

0

result:

ok meet maximum 1

Test #4:

score: 0
Accepted
time: 5ms
memory: 29556kb

input:

3

output:

010

result:

ok meet maximum 5

Test #5:

score: 0
Accepted
time: 2ms
memory: 29164kb

input:

4

output:

1001

result:

ok meet maximum 8

Test #6:

score: -100
Wrong Answer
time: 0ms
memory: 33952kb

input:

6

output:

000111

result:

wrong answer not meet maximum 15 < 16