#include <queue>
#include <vector>
#include <string>
#include <iostream>
#include <algorithm>

#define endl '\n'
#define N 4010

using namespace std;

int main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);
    
    int n;
    cin >> n;
    vector<vector<int> > mp(n + 1, vector<int> (n + 1, 0));
    vector<vector<int> > ans(n + 1, vector<int> (n + 1, 0));
    for (int i = 1; i <= n; ++ i) {
        string s;
        cin >> s;
        for (int j = 0; j < s.length(); ++ j) {
            if(s[j] == '+') {
                ans[i][j + 1] = 0;
                mp[i][j + 1] = 1;
            }else {
                mp[i][j + 1] = -1;
                ans[i][j + 1] = 1;
            }
        }
    }
    vector<vector<int> > sum(2, vector<int>(n + 1));
    for (int i = 0; i < 2; ++ i) {
        for (int j = 1; j <= n; ++ j) {
            cin >> sum[i][j];
        }
    }
    for (int i = 1; i <= n; ++ i) {
        for (int j = 1; j <= n; ++ j) {
            if(mp[j][i] == -1) ++ sum[1][i];
            if(mp[i][j] == -1) ++ sum[0][i];
        }
    }
    auto No = [] {
        cout << "No" << endl;
        exit(0);
    };
    int sum1 = 0, sum2 = 0;
    for (int i = 1; i <= n; ++ i) {
        if(sum[0][i] > n || sum[1][i] > n || sum[0][i] < 0 || sum[1][i] < 0) No();
        sum1 += sum[0][i];
        sum2 += sum[1][i];
    }
    if(sum1 != sum2) No();
    
    for (int i = 1; i <= n; ++ i) {
        vector<int> buk[N];
        for (int j = 1; j <= n; ++ j) {
            buk[sum[1][j]].push_back(j);
        }
        int c = sum[0][i];
        for (int j = n; j >= 0 && c > 0; -- j) {
            if(buk[j].size()) {
                for (int k = 0; k < min(c, (int)buk[j].size()); ++ k) {
                    if(sum[1][buk[j][k]] <= 0) No();
                    ans[i][buk[j][k]] = 1 - ans[i][buk[j][k]];
                    -- sum[1][buk[j][k]];
                    
                }
                c -= buk[j].size();
            }
        }
        if(c > 0) No();
    }
    cout << "Yes" << endl;
    for (int i = 1; i <= n; ++ i) {
        for (int j = 1; j <= n; ++ j) {
            cout << ans[i][j];
        }
        cout << endl;
    }
    return 0;
}
/*
 3
 +-+
 -++
 +-+
 1 1 1
 1 -1 3
 3
 ---
 -++
 +++
 -2 -1 0
 -2 -1 0
 3
 +-+
 -++
 ++-
 1 0 2
 2 2 -1
 */