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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#303633#6510. Best Carry Player 3xuqinWA 19ms3872kbC++142.0kb2024-01-12 20:30:522024-01-12 20:30:52

Judging History

你现在查看的是最新测评结果

  • [2024-01-12 20:30:52]
  • 评测
  • 测评结果:WA
  • 用时:19ms
  • 内存:3872kb
  • [2024-01-12 20:30:52]
  • 提交

answer

#include<cstdio>
#include<cstring>
#include<algorithm>
#include<utility>
#include<ctime>
#include<vector>
#include<queue>
#include<iostream>
#include<set>
#include<random>
#include<cmath>
#include<chrono>
#include<map>
#define eb emplace_back

using namespace std;
const int maxn=2e3+10, maxm=2e5+10, P=998244353, inf=2e9;
typedef long long LL;
const LL INF=4e18;
typedef pair<int, int> pii;
typedef pair<LL, int> pli;
typedef pair<int, LL> pil;

inline int read() {
    int x=0, f=1; char c=getchar();
    for(; c<'0'||c>'9'; c=getchar()) if(c=='-') f=0;
    for(; c>='0'&&c<='9'; c=getchar()) x=x*10+c-'0';
    return f?x:-x;
}
inline int add(int x, int y) {x+=y; return x>=P?x-P:x;}
inline int del(int x, int y) {x-=y; return x<0?x+P:x;}
inline int ksm(int x, int y) {
    int s=1; for(; y; y>>=1, x=1LL*x*x%P) if(y&1) s=1LL*s*x%P; return s;
}
mt19937 rnd((unsigned)chrono::steady_clock::now().time_since_epoch().count());

int main() {
	int T=read();
	while(T--) {
		LL x, y, k;
		scanf("%lld%lld%lld", &x, &y, &k);
		if(x>y) swap(x, y);
		if(k<=1||x==y) printf("%lld\n", y-x);
			else {
				int t=0; LL tmp=k;
				while(tmp) tmp>>=1, ++t;
				LL tx=x>>(t-1), ty=y>>(t-1);
				if(tx==ty) printf("1\n");
					else {
						LL b=3;
						if((k&(k+1))==0) b=2;
						if((tx>>1)==(ty>>1)) {
							if((y^x)<=k||x+1==y) printf("1\n");
								else printf("2\n");
						} else {
							LL ans=0;
							//printf("tx=%lld ty=%lld\n", tx, ty);
							if(tx&1) {
								if(((x^(tx<<(t-1)))&((x^(tx<<(t-1)))+1))==0) ans=1;
									else ans=2;
								++tx;
								x=tx<<t;
							} else {
								if((((1<<t)-1)^(x&((1<<t)-1)))<=k) ans=2;
									else ans=3;
								tx+=2; x=tx<<t;
							}
							//printf("b=%lld\n", b);
							//printf("ans=%lld\n", ans);
							ans+=((ty>>1)-(tx>>1))*b;
							x=x&((1<<t)-1), y=y&((1<<t)-1);
							if(x==y) printf("%lld\n", ans);
								else if((y^x)<=k||x+1==y) printf("%lld\n", 1+ans);
									else printf("%lld\n", 2+ans);
						}
					}
			}
	}
    return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 1ms
memory: 3624kb

input:

8
4 5 0
5 8 3
9 2 6
15 28 5
97 47 8
164 275 38
114514 1919 810
0 1152921504606846975 1

output:

1
2
3
5
11
6
331
1152921504606846975

result:

ok 8 numbers

Test #2:

score: -100
Wrong Answer
time: 19ms
memory: 3872kb

input:

100000
84 318 6
54 226 7
92 33 0
39 54 5
76 79 7
247 110 0
211 90 0
4 430 3
230 17 1
491 93 5
196 117 7
137 29 2
76 490 6
422 43 7
277 26 4
159 43 1
67 37 5
17 2 5
113 176 7
85 473 0
68 217 7
275 8 7
124 34 1
30 66 0
80 149 3
103 149 6
84 354 1
27 342 7
94 114 1
69 125 1
72 48 7
361 8 7
285 82 1
74 ...

output:

86
45
59
6
1
137
121
213
213
149
20
81
155
95
95
116
11
6
16
388
38
67
90
36
35
17
270
79
20
56
6
89
203
108
26
15
157
98
111
389
174
122
59
288
78
17
21
35
275
191
17
102
60
92
100
11
5
79
44
63
91
60
22
109
11
3
10
67
11
85
207
47
38
83
156
189
106
27
81
247
81
335
32
144
11
49
54
347
233
175
30
7...

result:

wrong answer 1st numbers differ - expected: '87', found: '86'