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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#303589#7780. Dark LaTeX vs. Light LaTeXPetroTarnavskyi#WA 1ms3628kbC++202.0kb2024-01-12 19:22:482024-01-12 19:22:49

Judging History

你现在查看的是最新测评结果

  • [2024-11-25 20:53:52]
  • hack成功,自动添加数据
  • (/hack/1258)
  • [2024-01-12 19:22:49]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:3628kb
  • [2024-01-12 19:22:48]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

#define FOR(i, a, b) for(int i = (a); i < (b); i++)
#define RFOR(i, a, b) for(int i = (a) - 1; i >= (b); i--)
#define SZ(a) int(a.size())
#define ALL(a) a.begin(), a.end()
#define PB push_back
#define MP make_pair
#define F first
#define S second

typedef long long LL;
typedef vector<int> VI;
typedef pair<int, int> PII;
typedef double db;

const LL LINF = 1.1e18;
const int N = 52;

int n;
VI p, q;
LL dp[N][N][2];

void updAdd(LL& a, LL b)
{
	a = min(a + b, LINF);
}

LL f()
{
	FOR(i, 0, N)
		FOR(j, 0, N)
			FOR(dir, 0, 2)
				dp[i][j][dir] = 0;
	int cnt = n - SZ(p);
	if (q[0] == -1)
	{
		FOR(j, 0, n)
			FOR(dir, 0, 2)
				dp[0][j][dir] = 1;
	}
	else
	{
		FOR(dir, 0, 2)
			dp[0][0][dir] = 1;
	}
	FOR(i, 0, n)
	{
		if (q[i] == -1)
			cnt--;
		if (i == n - 1)
			break;
		FOR(j, 0, cnt + 1)
		{
			if (q[i] != -1 && q[i + 1] != -1)
			{
				int dir = q[i] < q[i + 1];
				updAdd(dp[i + 1][0][dir ^ 1], dp[i][j][dir]);
				continue;
			}
			if (q[i] != -1)
			{
				FOR(k, 0, cnt)
					updAdd(dp[i + 1][k][0], dp[i][j][1]);
				continue;
			}
			if (q[i + 1] != -1)
			{
				updAdd(dp[i + 1][0][1], dp[i][j][0]);
				continue;
			}
			FOR(k, 0, cnt)
			{
				int dir = j <= k;
				updAdd(dp[i + 1][k][dir ^ 1], dp[i][j][dir]);
			}
		}
	}
	assert(cnt == 0);
	LL res = 0;
	FOR(dir, 0, 2)
		updAdd(res, dp[n - 1][0][dir]);
	return res;
}

int main()
{
	ios::sync_with_stdio(0); 
	cin.tie(0);
	cout << fixed << setprecision(15);
	LL k;
	cin >> n >> k;
	q.assign(n, -1);
	FOR(i, 0, n)
	{
		FOR(val, 0, n)
		{
			if (q[val] == -1)
			{
				p.PB(val);
				q[val] = i;
				LL cur = f();
				if (cur < k)
				{
					k -= cur;
					p.pop_back();
					q[val] = -1;
				}
				else
				{
					break;
				}
			}
		}
		if (SZ(p) != i + 1)
		{
			cout << "-1\n";
			return 0;
		}
	}
	FOR(i, 0, n)
	{
		if (i)
			cout << " ";
		cout << p[i] + 1;
	}
	cout << "\n";
	return 0;
}

詳細信息

Test #1:

score: 0
Wrong Answer
time: 1ms
memory: 3628kb

input:

abab
ab

output:



result:

wrong answer Answer contains longer sequence [length = 1], but output contains 0 elements