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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#303253#7685. Barkley IIDetachWA 51ms5656kbC++172.0kb2024-01-11 23:21:102024-01-11 23:21:11

Judging History

你现在查看的是最新测评结果

  • [2024-01-11 23:21:11]
  • 评测
  • 测评结果:WA
  • 用时:51ms
  • 内存:5656kb
  • [2024-01-11 23:21:10]
  • 提交

answer

#include <bits/stdc++.h>
// #include <algorithm>
// #include <queue>
// #include <map>
// #include <iostream>
// #include <string>
// #include <set>
#define endl '\n'

using namespace std;

using LL = long long;
using PII = pair<int, int>;
using i128 = __int128_t;
using ULL = unsigned long long;

const int INF = 0x3f3f3f3f, MOD = 1e9 + 7, MAXN = 1e6 + 5;
const LL LINF = 0x3f3f3f3f3f3f3f3f;

int n;
int tr[MAXN], pre[MAXN];

int lowbit(int x)
{
    return x & -x;
}

void add(int x, int w)
{
    for(int i = x; i <= n; i += lowbit(i)) tr[i] += w;
}

int query(int x)
{
    int res = 0;
    for(int i = x; i; i -= lowbit(i)) res += tr[i];

    return res;
}

void solve()
{
    int m;
    cin >> n >> m;
    vector<tuple<int, int, int>> itv;
    vector<int> a(n + 2);
    
    for(int i = 1; i <= n; i ++ )
    {
        cin >> a[i];
        if(a[i] <= n + 1 and pre[a[i]] + 1 < i)
        {        
            itv.push_back({i - 1, pre[a[i]] + 1, a[i]});
        }
        pre[a[i]] = i;
    }
    
    for(int i = 1; i <= n + 1; i ++ )
    {
        if(pre[i] < n)
            itv.push_back({n, pre[i] + 1, i});
    }
    
    sort(itv.begin(), itv.end());
    
    for(int i = 1; i <= n + 1; i ++ )
        tr[i] = 0, pre[a[i]] = 0;
    
    int sz = itv.size(), ans = 0;
    for(int i = 0, j = 0; i < sz; i ++ )
    {
        auto [r, l, mex] = itv[i];
        while(j < r)
        {
            j ++ ;

            if(pre[a[j]])
            {
                add(pre[a[j]], -1);
            }

            add(j, 1);
            pre[a[j]] = j;
        }

        ans = max(ans, query(r) - query(l - 1) - mex);
    }

    cout << ans << endl;

    for(int i = 1; i <= n; i ++ ) 
        pre[a[i]] = 0;
}   

int main()
{
    // freopen("galactic.in", "r", stdin);
    ios::sync_with_stdio(false), cin.tie(nullptr);
    int T = 1; 
    cin >> T;

    while(T -- )
        solve();
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 5548kb

input:

2
5 4
1 2 2 3 4
5 10000
5 2 3 4 1

output:

2
3

result:

ok 2 number(s): "2 3"

Test #2:

score: 0
Accepted
time: 51ms
memory: 5608kb

input:

50000
10 19
12 6 1 12 11 15 4 1 13 18
10 8
8 7 6 7 6 2 2 3 4 8
10 6
3 2 6 6 5 2 3 4 5 6
10 11
6 3 7 9 2 1 2 10 10 4
10 6
6 1 2 6 1 1 3 4 2 1
10 9
8 5 3 9 1 7 5 5 1 1
10 5
1 4 3 2 5 4 5 3 5 2
10 14
3 8 12 10 4 2 3 13 7 3
10 14
5 5 12 2 8 1 13 9 8 5
10 7
5 5 6 6 1 5 3 7 3 4
10 7
5 1 4 6 1 6 4 3 7 5
10...

output:

6
5
4
4
2
4
3
7
4
4
4
5
2
3
6
6
7
5
7
6
5
5
6
2
6
8
7
2
5
5
6
2
2
3
4
5
3
3
7
3
2
5
6
1
3
5
3
3
3
8
6
6
5
7
4
4
5
4
6
6
6
3
7
3
6
3
3
7
7
6
6
7
4
3
3
4
4
6
3
4
6
6
4
5
5
9
4
5
7
5
3
5
2
2
5
6
6
8
4
3
4
5
5
5
7
7
3
2
6
5
3
5
4
4
5
6
6
5
6
7
7
4
5
7
4
7
3
7
6
6
6
5
4
2
5
4
2
3
6
5
2
6
5
5
4
3
5
6
6
6
...

result:

ok 50000 numbers

Test #3:

score: -100
Wrong Answer
time: 51ms
memory: 5656kb

input:

100000
5 4
4 3 1 3 1
5 4
2 2 1 3 4
5 9
7 8 7 1 3
5 3
3 2 2 3 1
5 7
1 4 2 4 7
5 4
4 4 4 2 3
5 3
2 1 2 2 2
5 5
2 1 2 5 4
5 9
1 8 4 4 7
5 6
2 6 4 6 2
5 5
1 2 4 4 4
5 3
2 1 1 1 3
5 5
5 4 5 2 5
5 4
3 3 3 2 1
5 3
3 1 3 2 3
5 7
1 5 2 2 7
5 6
2 2 6 5 6
5 10
6 3 3 1 7
5 8
1 6 8 4 3
5 4
1 2 1 3 3
5 7
2 2 4 3 ...

output:

1
1
2
1
2
2
0
2
2
2
1
0
2
1
1
2
2
2
3
0
3
1
2
2
3
3
1
3
0
0
3
2
2
0
2
2
1
0
2
2
3
3
3
1
3
2
2
3
2
3
2
1
2
3
1
3
3
1
2
3
1
1
2
2
2
2
0
1
0
1
0
2
1
3
0
2
2
3
2
2
1
3
1
3
1
1
1
3
1
1
4
0
1
3
2
2
2
0
3
2
4
3
3
2
1
0
4
4
3
2
1
2
1
2
3
2
3
4
4
3
0
0
1
4
1
3
3
2
3
1
3
4
3
1
2
2
3
2
3
2
3
3
1
3
1
1
4
1
1
3
...

result:

wrong answer 2377th numbers differ - expected: '-1', found: '0'