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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#303240#7685. Barkley IIDetachRE 0ms3524kbC++171.9kb2024-01-11 22:47:572024-01-11 22:47:58

Judging History

你现在查看的是最新测评结果

  • [2024-01-11 22:47:58]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:3524kb
  • [2024-01-11 22:47:57]
  • 提交

answer

#include <bits/stdc++.h>
// #include <algorithm>
// #include <queue>
// #include <map>
// #include <iostream>
// #include <string>
// #include <set>
#define endl '\n'

using namespace std;

using LL = long long;
using PII = pair<int, int>;
using i128 = __int128_t;
using ULL = unsigned long long;

const int INF = 0x3f3f3f3f, MOD = 1e9 + 7, MAXN = 1e6 + 5;
const LL LINF = 0x3f3f3f3f3f3f3f3f;

int n;
int tr[MAXN];

int lowbit(int x)
{
    return x & -x;
}

void add(int x, int w)
{
    for(int i = x; i <= n + 1; i += lowbit(i)) tr[i] += w;
}

int query(int x)
{
    int res = 0;
    for(int i = x; i; i -= lowbit(i)) res += tr[i];

    return res;
}

void solve()
{
    int m;
    cin >> n >> m;
    vector<tuple<int, int, int>> itv;
    vector<int> a(n + 1), pre(n + 2);

    for(int i = 1; i <= n; i ++ )
    {
        cin >> a[i];
        if(a[i] <= n + 1 and pre[a[i]] + 1 < i)
            itv.push_back({i - 1, pre[a[i]] + 1, a[i]});
        pre[a[i]] = i;
    }

    for(int i = 1; i <= n + 1; i ++ )
    {
        if(pre[i] < n)
            itv.push_back({n, pre[i] + 1, i});
    }
    
    sort(itv.begin(), itv.end());

    for(int i = 0; i <= n + 1; i ++ )
        tr[i] = 0, pre[i] = 0;

    int sz = itv.size(), ans = 0;
    for(int i = 0, j = 0; i < sz; i ++ )
    {
        auto [r, l, mex] = itv[i];
        while(j < r)
        {
            j ++ ;

            if(pre[a[j]])
            {
                add(pre[a[j]], -1);
            }

            add(j, 1);
            pre[a[j]] = j;
        }

        ans = max(ans, query(r) - query(l - 1) - mex);
    }

    cout << ans << endl;
}   

int main()
{
    // freopen("galactic.in", "r", stdin);
    ios::sync_with_stdio(false), cin.tie(nullptr);
    int T = 1; 
    cin >> T;

    while(T -- )
        solve();
    return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 0ms
memory: 3524kb

input:

2
5 4
1 2 2 3 4
5 10000
5 2 3 4 1

output:

2
3

result:

ok 2 number(s): "2 3"

Test #2:

score: -100
Runtime Error

input:

50000
10 19
12 6 1 12 11 15 4 1 13 18
10 8
8 7 6 7 6 2 2 3 4 8
10 6
3 2 6 6 5 2 3 4 5 6
10 11
6 3 7 9 2 1 2 10 10 4
10 6
6 1 2 6 1 1 3 4 2 1
10 9
8 5 3 9 1 7 5 5 1 1
10 5
1 4 3 2 5 4 5 3 5 2
10 14
3 8 12 10 4 2 3 13 7 3
10 14
5 5 12 2 8 1 13 9 8 5
10 7
5 5 6 6 1 5 3 7 3 4
10 7
5 1 4 6 1 6 4 3 7 5
10...

output:


result: