#include <iostream>
#include<cstdio>
#include<cmath>
#include<cstring>
#include<iomanip>
#include<algorithm>
#include<deque>
#include<unordered_map>
#include<map>
#define ll long long
#define l(p) t[p].l
#define sum(p) t[p].sum
#define cnt(p) t[p].cnt
#define r(p) t[p].r
#define mod 998244353
#define sc(A) scanf("%d",&A)
#define rep(A,B,C) for(int C=A;C<=B;++C)
#define fep(A,B,C) for(int C=A;C>=B;--C)
#define put(x) printf("%d\n",x)
#define db double
using namespace std;
const int MAXN=5010;
int n,m,q,x,maxx=62,top;

char a[MAXN],b[MAXN];
int nex[MAXN];
int w[MAXN];
int c1[MAXN][MAXN];
int c2[MAXN][MAXN];
map<pair<unsigned ll,int>,int>H;
map<pair<unsigned ll,int>,int>H1;

signed main() 
{
	//freopen("1.in","r",stdin);
	scanf("%s",a+1);
	scanf("%s",b+1);
	int n=strlen(a+1);
	int m=strlen(b+1);
	rep(1,n,i)
	{
		int base1=23333;
		int base2=114514;
		unsigned ll s2=0;
		int s1=0;
		rep(i,n,j)
		{
			s1=((ll)s1*base1+a[j])%mod;
			s2=s2*base2+a[j];
			++H[make_pair(s2,s1)];
			
		}
	}

	ll ans=0;
	rep(1,m,i)
	{
		int base1=23333;
		int base2=114514;
		unsigned ll s2=0;
		int s1=0;
		rep(i,m,j)
		{
			s1=((ll)s1*base1+b[j])%mod;
			s2=s2*base2+b[j];
			ans+=H[make_pair(s2,s1)];
			c2[i][j]=H[make_pair(s2,s1)];
			++H1[make_pair(s2,s1)];
		}
	}

	rep(1,n,i)
	{
		int base1=23333;
		int base2=114514;
		unsigned ll s2=0;
		int s1=0;
		rep(i,n,j)
		{
			s1=((ll)s1*base1+a[j])%mod;
			s2=s2*base2+a[j];
			c1[i][j]=H1[make_pair(s2,s1)];
		}
	}
	


	rep(2,n,j)
	{
		int now=j;
		w[j+1]=1;
		w[j]=0;
		nex[j+1]=j;
		rep(j+2,n,i)
		{
			while(now!=j&&a[i]!=a[now+1])now=nex[now];
			if(a[i]==a[now+1])++now;
			nex[i]=now;
			w[i]=w[now]+1;
		}
		now=j;
		rep(1,j-1,i)
		{
			while(now!=j&&a[i]!=a[now+1])now=nex[now];
			if(a[i]==a[now+1])++now;
			ans+=(ll)w[now]*c1[i+1][j];
		}
	}

	rep(2,m,j)
	{
		int now=j;
		w[j+1]=1;
		w[j]=0;
		nex[j+1]=j;
		rep(j+2,m,i)
		{
			while(now!=j&&b[i]!=b[now+1])now=nex[now];
			if(b[i]==b[now+1])++now;
			nex[i]=now;
			w[i]=w[now]+1;
		}
		now=j;
		rep(1,j-1,i)
		{
			while(now!=j&&b[i]!=b[now+1])now=nex[now];
			if(b[i]==b[now+1])++now;
			ans+=(ll)w[now]*c2[i+1][j];
		}
	}

	printf("%lld\n",ans);
	return 0;
}