#include <bits/stdc++.h>
#define PII pair<int, int>
using namespace std;
const int N = 1e5 + 3;
const int W = (N << 1);
const int M = 2e5 + 3;
const int mod = 998244353;
const int inv2 = 499122177;

inline int read() {
    char ch = getchar(); int x = 0, f = 1;
    while (!isdigit(ch)) {if (ch == '-') {f = -1;} ch = getchar();}
    while (isdigit(ch)) {x = (x << 3) + (x << 1) + ch - 48; ch = getchar();}
    return x * f;
}
int fac[W], inv[W];
inline int add(int x, int y) {x += y; return x >= mod ? x - mod : x;}
inline int del(int x, int y) {x -= y; return x < 0 ? x + mod : x;}
inline void Add(int &x, int y) {x = add(x, y);}
inline void Del(int &x, int y) {x = del(x, y);}
inline int qpow(int x, int y) {
    int res = 1;
    while (y) {
        if (y & 1) res = 1ll * res * x % mod;
        x = 1ll * x * x % mod;
        y >>= 1;
    }
    return res;
}
inline int C(int x, int y) {return (x < 0 || y < 0 || x < y) ? 0 : 1ll * fac[x] * inv[y] % mod * inv[x - y] % mod;}
struct NTT {
    int len;
    vector<int> f, g;
    
    void init(int n) {
        len = 1;
        while (len <= n + n) len <<= 1;
        f.clear(); g.clear();
        f.resize(len + 5); g.resize(len + 5);
    }
};

int T, c, p, q, L, cnt, pos[10][10], pw[N][10];
PII id[10];

inline int calc(int x, int y, int k) {return 1ll * pw[x][id[k].first] * pw[y][id[k].second] % mod;}

namespace subtask1 {
    const int N1 = 1005;

    int f[N1][N1], g[N1][N1][10];
    
    bool check() {return L <= 1000;}

    void solve() {
        f[0][0] = 1;
        for (int i = 0; i < cnt; ++i) g[0][0][i] = calc(0, 0, i);
        for (int i = 0; i <= L; ++i)
            for (int j = 0; j <= L; ++j) {
                if (i == 0 && j == 0) continue;
                if (i) Add(f[i][j], f[i - 1][j]);
                if (j) Add(f[i][j], f[i][j - 1]);
                for (int k = 0; k < cnt; ++k) {
                    if (i) Add(g[i][j][k], g[i - 1][j][k]);
                    if (j) Add(g[i][j][k], g[i][j - 1][k]);
                    if (j <= i) Add(g[i][j][k], 1ll * f[i][j] * calc(i, j, k) % mod);
                }
            }
        int n, m, ans;
        while (T--) {
            n = read(); m = read(); ans = 0;
            for (int i = 0; i < cnt; ++i) Add(ans, 1ll * g[n][m][i] * read() % mod);
            printf("%d\n", ans);
        }
    }
}

namespace subtask2 {
    int f[N], g[N], n, m, v, ans;

    bool check() {return T == 1 && p == 0 && q == 0;}

    void solve() {
        n = read(); m = read(); v = read();
        if (n == m) {
            g[n] = qpow(4, n);
			f[n] = 1ll * del(1ll * (n + m + 1) * C(n + m, n) % mod, g[n]) * inv2 % mod;
            printf("%lld\n", 1ll * add(f[n], g[n]) * v % mod);
        }else if (n < m) {
			g[0] = 1;
			for (int i = 1; i <= n; ++i) g[i] = 4ll * g[i - 1] % mod;
			for (int i = 0; i <= n; ++i) {
				f[i] = 1ll * del(1ll * (i + i + 1) * C(i + i, i) % mod, g[i]) * inv2 % mod;
				Add(ans, 1ll * add(f[i], g[i]) * del(C(n - i + m - i - 1, n - i), C(n - i + m - i - 1, n - i - 1)) % mod);
			}
			ans = 1ll * ans * v % mod;
			printf("%d\n", ans);
        }else {
			g[0] = 1; ans = 1ll * (n + m + 1) * C(n + m, n) % mod;
			for (int i = 1; i <= m; ++i) g[i] = 4ll * g[i - 1] % mod;
			for (int i = 0; i <= m; ++i) {
				f[i] = 1ll * del(1ll * (i + i + 1) * C(i + i, i) % mod, g[i]) * inv2 % mod;
				Del(ans, 1ll * f[i] * del(C(n - i - 1 + m - i, m - i), C(n - i - 1 + m - i, n - i)) % mod);
			}
			ans = 1ll * ans * v % mod;
			printf("%d\n", ans);
		}
    }
}

int main() {
    fac[0] = 1;
    for (int i = 1; i <= M; ++i) fac[i] = 1ll * fac[i - 1] * i % mod;
    inv[M] = qpow(fac[M], mod - 2);
    for (int i = M; i >= 1; --i) inv[i - 1] = 1ll * inv[i] * i % mod;
    T = read(); c = read(); p = read(); q = read(); L = read(); L = max(L, L + c);
    for (int i = 0; i <= p; ++i)
        for (int j = 0; j <= q; ++j)
            id[pos[i][j] = cnt++] = make_pair(i, j);
    for (int i = 0; i <= L; ++i) {
        pw[i][0] = 1;
        for (int j = 1; j <= max(p, q); ++j) pw[i][j] = 1ll * pw[i][j - 1] * i % mod;
    }

    // subtask2 :: solve(); exit(0);

    if (subtask1 :: check()) subtask1 :: solve();
    else if (subtask2 :: check()) subtask2 :: solve();
    return 0;
}